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Oxygen Supply in Submarines Nuclear submarines can stay under water nearly indefinitely because they can produce their own oxygen by the electrolysis of water. a. How many liters of \(\mathrm{O}_{2}\) at \(25^{\circ} \mathrm{C}\) and 1.00 bar are produced in 1 hour in an electrolytic cell operating at a current of \(0.025 \mathrm{A} ?\) b. Could seawater be used as the source of oxygen in this electrolysis? Explain why or why not.

Short Answer

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Question: Calculate the volume of oxygen gas produced in 1 hour at a current of 0.025 A, given a pressure of 1.00 bar and temperature of 25掳C. Additionally, discuss if seawater can be used as a source of oxygen for this electrolysis process. Answer: The volume of oxygen gas produced in 1 hour at a current of 0.025 A, given a pressure of 1.00 bar and temperature of 25掳C, is approximately 0.577 L. Seawater cannot be used directly as a source of oxygen for this electrolysis process due to competing reactions and the production of undesired side products. Proper pre-treatment to remove dissolved salts is necessary for using seawater as a source.

Step by step solution

01

Calculate moles of electrons transferred

We will use the current to find the amount of charge transferred in 1 hour. Since Current (I) is the flow of charge, we have: I = Q/t, where I is the current, Q is the charge transferred, and t is the time. We are given I = 0.025 A and t = 1 hour = 3600 seconds. So, Q = I 脳 t = 0.025 A 脳 3600 s = 90 C (Coulombs). Now, we need to convert this charge to moles of electrons using the Faraday constant (F) which represents the charge of 1 mole of electrons 鈮 96485 C/mol. Moles of electrons transferred = Q/F = 90 C / 96485 C/mol 鈮 9.32 脳 10鈦烩伌 mol.
02

Calculate moles of \(\mathrm{O}_{2}\) produced

In the electrolysis of water, the reaction at the anode (oxygen production) can be represented as: 2H鈧侽 鈫 O鈧 + 4H鈦 + 4e鈦 From the stoichiometry of the reaction, we can see that for every 4 moles of electrons, 1 mole of O鈧 is produced. So, moles of \(\mathrm{O}_{2}\) produced = (Moles of electrons transferred / 4) = (9.32 脳 10鈦烩伌 mol) / 4 = 2.33 脳 10鈦烩伌 mol.
03

Calculate the volume of oxygen gas produced

Now, we will use the ideal gas law to find the volume of oxygen gas produced. Ideal gas law: PV = nRT, where P is the pressure, V is the volume, n is the moles, R is the universal gas constant (鈮 8.314 J/(mol K)), and T is the temperature. We are given P = 1.00 bar = 100000 Pa, and T = \(25^{\circ} \mathrm{C}\) + 273.15 K = 298.15 K. Rearrange the ideal gas law for the volume V: V = nRT/P Now, plug in the values: V = (2.33 脳 10鈦烩伌 mol) 脳 (8.314 J/(mol K)) 脳 (298.15 K) / (100000 Pa) = 5.77 脳 10鈦烩伌 m鲁. To convert from cubic meters to liters, note that 1 m鲁 = 1000 L: Volume of oxygen gas produced = 5.77 脳 10鈦烩伌 m鲁 脳 1000 L/m鲁 鈮 0.577 L.
04

Part b: Can seawater be used as the source of oxygen in electrolysis?

Seawater contains a high amount of dissolved salt, mainly sodium chloride (NaCl). In the electrolysis process, if seawater were used as the source, the salt would also be electrolyzed along with water molecules. The competing reactions on the electrodes would reduce the efficiency of oxygen production significantly. These undesired side reactions would lead to the production of chlorine gas and other compounds that can corrode the machinery of the submarine. Thus, seawater could not be used as the source of oxygen directly in this electrolysis process without proper pre-treatment to remove the dissolved salts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxygen Production
Producing oxygen via electrolysis primarily involves splitting water molecules into oxygen and hydrogen gases. This process is vital in environments like submarines, where it's necessary to generate a sustainable oxygen supply from water. Through this ingenious method, a current is passed through water, breaking the bonds between hydrogen and oxygen atoms.

For oxygen to be liberated, electrons are transferred as part of an electrochemical reaction at the anode, which releases oxygen gas. The general reaction is represented by the formula: \[2H_2O(l) \rightarrow O_2(g) + 4H^+(aq) + 4e^-\] This shows that it takes 4 electrons to produce one molecule of oxygen. Understanding this equation helps explain why a specific amount of current is needed to generate a measurable volume of oxygen. It's an elegant process converting electrical energy into chemical energy, ensuring a continuous replenishment of breathable air in confined spaces like submarines.
Ideal Gas Law
The Ideal Gas Law is a crucial tool in calculating the volume of gases produced during electrolysis. Expressed as \(PV = nRT\), this equation helps us determine the volume (\(V\)) of gas generated when parameters such as pressure (\(P\)), temperature (\(T\)), and the number of moles (\(n\)) are known.
  • \(P\) is the pressure, measured in pascals (Pa).
  • \(V\) is the volume we want to find.
  • \(n\) represents moles of gas.
  • \(R\) is the universal gas constant, approximately \(8.314 \text{ J/(mol K)}\).
  • \(T\) is the temperature in Kelvin (K).
For example, when determining the volume of oxygen gas at a given temperature and pressure, you simply rearrange the equation to:\[V = \frac{nRT}{P}\]This formula ensures precise calculations of gas volume, essential for understanding the logistics of gas storage in systems like submarines. By adjusting the variables accordingly, it enables one to predict and measure outcomes of gas production processes accurately.
Electrochemistry
Electrochemistry deals with the interaction between electrical energy and chemical changes. Electrolysis is a key component, encompassing reactions where chemical compounds are broken down by electric current.

This science is critical for the oxygen production process. When current flows through water equipped in electrodes, it triggers a series of reactions that split water molecules. At the anode, oxidation takes place, creating oxygen gas, while reduction happens at the cathode, producing hydrogen gas.
  • Electrodes: Materials that conduct electric current into the solution.
  • Anode: The electrode where oxidation and oxygen production occur.
  • Cathode: The site of reduction, resulting in the formation of hydrogen gas.
Through electrochemical principles, we understand how water's breakdown results in gas release, helping supply oxygen in synthetic environments where fresh air circulation is limited. These concepts emphasize the interrelationships in chemistry and electricity that underlie many technological advancements.
Seawater Electrolysis
Utilizing seawater for electrolysis presents challenges due to its complex composition. Unlike pure water, seawater contains a high concentration of salt (mainly sodium chloride). This poses problems when attempting oxygen production through electrolysis.

The presence of dissolved salts leads to undesired side reactions, such as the generation of chlorine gas. Such reactions can:
  • Decrease the efficiency of oxygen production.
  • Corrode equipment.
  • Produce hazardous by-products.
While theoretically possible, using seawater requires additional steps, like desalination, to remove salts and other impurities. This ensures only water is electrolyzed, preventing equipment damage and ineffective oxygen production. In practical applications, seawater is often pre-treated or avoided for these reasons, aligning better with efficient and safe oxygen supply operations.

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