/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 87 What is the difference between m... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 16: Problem 87

What is the difference between molar solubility and solubility product?

Short Answer

Expert verified
Answer: The key differences between molar solubility and solubility product are: 1. Molar solubility is a quantitative measure of the maximum concentration of a solute that can be dissolved in a solvent, whereas solubility product is an equilibrium constant for the dissolution of a sparingly soluble ionic compound. 2. Molar solubility is expressed in moles per liter (mol/L), while solubility product is a dimensionless number. 3. The relationship between molar solubility and solubility product depends on the stoichiometry of the dissolution reaction.

Step by step solution

01

Definition of Molar Solubility

Molar solubility is a measure of the maximum amount of a substance (solute) that can dissolve in a given volume of a solvent to form a saturated solution. It is expressed in units of moles per liter (mol/L). Molar solubility informs us about the maximum concentration of a solute that can be dissolved in the solvent to maintain equilibrium.
02

Definition of Solubility Product

Solubility Product (K_sp) is the equilibrium constant for the dissolution of a sparingly soluble ionic compound in a solvent, most commonly water. It describes the relationship between the concentrations of the ions and the overall solubility of a compound. A higher K_sp value for a compound indicates higher solubility. The solubility product is mathematically expressed as the product of the molar concentrations of the ions, each raised to the power of their coefficients in the balanced chemical equation.
03

Difference Between Molar Solubility and Solubility Product

Molar solubility and solubility product are related, but they are not the same thing. The key differences between the two concepts are: 1. Molar solubility is a quantitative measure of the maximum concentration of a solute that can be dissolved in a solvent, whereas solubility product is an equilibrium constant for the dissolution of a sparingly soluble ionic compound. 2. Molar solubility is expressed in moles per liter (mol/L), while solubility product is a dimensionless number. 3. The relationship between molar solubility and solubility product depends on the stoichiometry of the dissolution reaction. For example, for the dissolution of a compound AB into A^+ and B^-, the relationship is K_sp = [A^+][B^-] = (molar solubility)^2. In conclusion, molar solubility and solubility product are two different concepts that describe the solubility of a compound. While molar solubility gives us an idea about the maximum amount of solute that can dissolve in a solvent, solubility product helps us understand the equilibrium between the dissolved and undissolved forms of a sparingly soluble ionic compound.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility Product
The solubility product constant, denoted as \(K_{sp}\), is a key concept in the study of ionic compounds and their solubility in water. It provides a valuable insight into how a sparingly soluble compound behaves in a solution. The solubility product is a specific form of the equilibrium constant. It applies to the dissolution of ionic compounds in water, where an equilibrium is established between the solid and its ions in solution.
  • For a compound \(AB\) that dissolves to form \(A^+\) and \(B^-\), the equation for the solubility product is \(K_{sp} = [A^+][B^-]\).
  • This product is considered at equilibrium when the solution is saturated, meaning no more solute can dissolve.
  • Each ion's concentration is taken to the power of its coefficient in the balanced dissolution equation.
The \(K_{sp}\) value is crucial as it tells us how much of the compound can be found in the solution form. A higher solubility product indicates that more ions are present in the solution, meaning the compound is more soluble.
Equilibrium Constant
The equilibrium constant is a vital concept in chemistry, encapsulating the idea that chemical reactions can reach a point where the rates of the forward and reverse reactions are equal. This balance, known as equilibrium, can be described mathematically using an equilibrium constant.
  • This constant provides a ratio of the concentrations of products to reactants at equilibrium, each raised to the power of their coefficients in the balanced equation.
  • For dissolutions, the equilibrium constant specific to solubility is the solubility product \(K_{sp}\).
  • A larger value of an equilibrium constant indicates that the products of the reaction are favored.
In the context of ionic compounds dissolving in water, the \(K_{sp}\) helps us predict how much of a compound will dissolve or precipitate under specific conditions. It is a core tool for chemists to understand how substances interact in mixtures and reactions.
Ionic Compounds
Ionic compounds play a crucial role in solubility, as they are often the substances in question when discussing solubility products. These compounds consist of positive and negative ions bound together by ionic bonds, forming a crystal lattice structure. When they dissolve in water, they dissociate into their constituent ions.
  • For example, sodium chloride \(NaCl\) dissolves to form \(Na^+\) and \(Cl^-\) ions.
  • The solubility of these compounds depends on the strength of the ionic bonds and the polarity of water.
  • Not all ionic compounds dissolve easily; some are said to be sparingly soluble, contributing minimally to the solution's concentration of ions.
Understanding the behavior of ionic compounds in water helps us comprehend phenomena such as precipitation, where ions in a solution form a solid compound due to reaching saturation.
Stoichiometry
Stoichiometry is the bridge that connects the chemical equation with the quantities of reactants and products in a reaction. It quantifies the relationships between the amounts of substances participating in a chemical process. This concept is essential when working with solubility products and dissolution reactions.
  • It allows us to calculate how much product forms from a given quantity of reactants using ratios derived from the balanced chemical equation.
  • In solubility calculations, stoichiometry helps us determine the relationship between molar solubility and \(K_{sp}\).
  • The coefficients in a chemical equation indicate the proportions of ions, guiding how we calculate concentrations in a saturated solution.
By applying stoichiometry to solubility problems, we can convert between different units and predict the extent of reactions and dissolutions, making it a powerful tool for students and chemists alike.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A lab technician cleaning glassware that contains residues of AgCl washes the glassware with an aqueous solution of ammonia. The AgCl, which is insoluble in water, rapidly dissolves in the ammonia solution. Why?

What masses of ethylamine and ethylammonium chloride do you need to prepare \(1.00 \mathrm{L}\) of \(\mathrm{pH}=10.50\) buffer if the total concentration of the two components is \(0.250 M ?\)

Tooth enamel is composed of a mineral known as hydroxyapatite with the formula \(\mathrm{Ca}_{5}\left(\mathrm{PO}_{4}\right)_{3}(\mathrm{OH}) .\) Explain why tooth enamel can be eroded by acidic substances released by bacteria growing in the mouth.

Which, if any, aqueous solutions of the following chloride compounds are acidic? (a) \(\mathrm{CaCl}_{2} ;\) (b) \(\mathrm{CrCl}_{3} ;\) (c) \(\mathrm{NaCl}\) (d) \(\mathrm{FeCl}_{3}\)

At a particular temperature the \(\left[\mathrm{Ba}^{2+}\right]\) in a saturated solution of barium sulfate is \(1.04 \times 10^{-5} M .\) Starting with this information, calculate the \(K_{\mathrm{sp}}\) value of barium sulfate at this temperature.
See all solutions

Recommended explanations on Chemistry Textbooks

Making Measurements

Read Explanation

Chemical Reactions

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Kinetics

Read Explanation

Nuclear Chemistry

Read Explanation

Organic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.