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Give approximate values for the indicated bond angles. (a) angles in \(\mathrm{SF}_{6}\) (b) angle in \(\mathrm{XeF}_{2}\) (c) angle in \(\mathrm{ClF}_{2}^{-}\)

Short Answer

Expert verified
(a) 90°; (b) 180°; (c) 180°.

Step by step solution

01

Understanding Molecular Geometry of SF6

The molecule \(\mathrm{SF}_6\) has six fluorine atoms bonded to a central sulfur atom. Consequently, \(\mathrm{SF}_6\) has an electron geometry called octahedral, which characteristically has bond angles of \(90^\circ\) between each adjacent fluorine atom.
02

Determining Bond Angles in XeF2

\(\mathrm{XeF}_2\) has a central xenon atom with two fluorine atoms and three lone pairs. This leads to a linear geometry with bond angles of \(180^\circ\) between the fluorine atoms. The electron geometry is technically trigonal bipyramidal due to the lone pairs, but the observed molecular geometry is linear.
03

Calculating Bond Angles in ClF2-

The \(\mathrm{ClF}_2^-\) ion has three lone electron pairs and two fluorine atoms around the central chlorine atom, mimicking \(\mathrm{XeF}_2\) in terms of geometry. With five total electron pairs, the electron geometry is again trigonal bipyramidal, but the observed molecular geometry is linear, resulting in a bond angle of \(180^\circ\) between the fluorine atoms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bond Angles
Bond angles are the angles formed between two bonds that originate from the same atom. They are a crucial part in understanding molecular geometry, as they determine the shape and structure of a molecule.
By analyzing bond angles, chemists can predict the chemical properties and reactivity of a molecule.
  • For instance, if all the bond angles in a molecule are equal, the molecule tends to have higher symmetry.
  • Moreover, the value of bond angles can affect the polarity of a molecule.
Typically, the bond angles are measured in degrees, and the specific values depend on the number of bonded atoms and lone pairs around the central atom. Bond angles in molecular geometries like octahedral, linear, and trigonal bipyramidal configurations vary and are determined by the electron pair arrangements, either bonded or lone.
Octahedral Geometry
Octahedral geometry is a type of molecular shape where six atoms, groups, or ligands are symmetrically arranged around a central atom. This geometry is named after the shape of an octahedron, a polyhedron with eight faces.
Octahedral geometry is characterized by its symmetry and specific bond angles.
  • Each pair of adjacent bonds in an octahedral arrangement forms a bond angle of precisely 90°.
  • Occasionally, you will find bond angles of 180° along opposite bonds.
A well-known example of a molecule with octahedral geometry is sulfur hexafluoride (\(\mathrm{SF_{6}\)).Sulfur lies at the center, and six fluorine atoms are placed at the vertices of an octahedron,
ensuring that the bond angles remain at 90°. This type of geometry helps molecules maximize space efficiently,
providing stability through symmetrical distribution of electron density.
Linear Geometry
Linear geometry in molecules is a straightforward geometric concept where the atoms are arranged in a straight line. This results in a bond angle of 180° between the bonded atoms.
Despite its simplicity, linear geometry can provide insights into complex molecular interactions.
  • Molecules with two bonded atoms, and no or symmetrical lone pairs, often exhibit linear geometry.
  • Examples include beryllium hydride \(\mathrm{BeH_{2}\),carbon dioxide \(\mathrm{CO_{2}\), and xenon difluoride \(\mathrm{XeF_{2}\).
In \(\mathrm{XeF_{2}\),the lone pairs around the xenon atom adopt positions that minimize repulsion,leading to a linear arrangement of the fluorine atoms.With this understanding, it's clear that any linear molecule will have a consistent 180° bond angle.
Trigonal Bipyramidal Geometry
Trigonal bipyramidal geometry signifies a molecular shape where a central atom is surrounded by five atoms, groups, or ligands. These are arranged such that three lie in a plane (equatorial positions) and two lie above and below this plane (axial positions).
This unique arrangement affects the bond angles significantly.
  • The bond angles between equatorial positions are 120°.
  • Between axial and equatorial positions, the bond angles are 90°.
In certain molecules, like \(\mathrm{PF_{5}\), all positions are occupied yet, in molecules such as \(\mathrm{ClF_{2}^{-}\),some positions hold lone pairs.This modifies the observed geometry due to lone pair-lone pair and lone pair-bonded pair repulsion,leading to a differing molecular shape.The \(\mathrm{ClF_{2}^{-}\) ion thus appears linear,as the three lone pairs are among the equatorial positions, and fluorine atoms occupy the two axial positions.

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Most popular questions from this chapter

Write Lewis structures for \(\mathrm{XeOF}_{2}\) and \(\mathrm{ClOF}_{3}\). Use VSEPR theory to predict the electron-region and molecular geometries of these molecules, and note any differences between these geometries.

Which of these molecules is (are) polar? For each polar molecule, what is the direction of polarity; that is, which is the partial negative end and which is the partial positive end of the molecule? (a) \(\mathrm{CO}_{2}\) (b) \(\mathrm{HBF}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{Cl}\) (d) \(\mathrm{SO}_{3}\)

Write the Lewis structure and designate which are sigma and pi bonds in each of these molecules. (a) \(\mathrm{OCS}\) (b) \(\mathrm{NH}_{2} \mathrm{OH}\) (c) \(\mathrm{CH}_{2} \mathrm{CHCHO}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}\)

Nitrosyl azide, a yellow solid first synthesized in \(1993,\) has the molecular formula \(\mathrm{N}_{4} \mathrm{O}\). (a) Write its Lewis structure. (b) What is the hybridization on the terminal nitrogen? (c) What is the hybridization on the "central" nitrogen? (d) Which is the shortest nitrogen-nitrogen bond? (e) Give the approximate bond angle between the three nitrogens, beginning with the nitrogen that is bonded to oxygen. (f) Give the approximate bond angle between the last three nitrogens, those not involved in bonding to oxygen. (g) How many sigma bonds are there? How many pi bonds?

In each of these molecules or ions, two oxygen atoms are attached to a central atom. Draw the Lewis structure for each, and then describe the electron-region geometry and the molecular geometry. Comment on similarities and differences in the series. (a) \(\mathrm{CO}_{2}\) (b) \(\mathrm{NO}_{2}^{-}\) (c) \(\mathrm{SO}_{2}\) (d) \(\mathrm{O}_{3}\) (e) \(\mathrm{ClO}_{2}^{-}\)

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