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Two compounds have the molecular formula \(\mathrm{N}_{3} \mathrm{H}_{3}\). One of the compounds, triazene, contains an \(\mathrm{N}=\mathrm{N}\) bond; the other compound, triaziridene, does not. (a) Write the correct Lewis structures for each compound. (b) Approximate the bond angle between the three nitrogen atoms in each compound.

Short Answer

Expert verified
Triazene: \( \mathrm{NH}_2 - \mathrm{N} = \mathrm{N} - \mathrm{H} \), angles \( \approx 120^\circ \), Triaziridene: cyclic \( \mathrm{N}_3 \), angles \( \approx 60^\circ \).

Step by step solution

01

Lewis Structure for Triazene

Triazene contains an \( \mathrm{N} = \mathrm{N} \) bond. For the Lewis structure, start by arranging the three nitrogen atoms linearly with the central atom having a double bond with one nitrogen and a single bond with the other. The structure can be written as \( \mathrm{NH}_2 - \mathrm{N} = \mathrm{N} - \mathrm{H} \). Each nitrogen should have a complete octet, with appropriate hydrogen atoms to balance the total hydrogens.
02

Lewis Structure for Triaziridene

Triaziridene has all single bonds between the nitrogen atoms since there is no \( \mathrm{N} = \mathrm{N} \) bond. Assume a cyclic structure with each nitrogen atom equidistant and bonded to two hydrogen atoms. The structure can be represented as a three-membered ring: \( \mathrm{N}(-\mathrm{H}) - \mathrm{N}(-\mathrm{H}) - \mathrm{N}(-\mathrm{H}) \), where each nitrogen forms two single bonds, one to a neighboring nitrogen and one to a hydrogen.
03

Bond Angles in Triazene

In triazene, the presence of the \( \mathrm{N} = \mathrm{N} \) double bond suggests a trigonal planar geometry around the double-bonded nitrogen, leading to bond angles of approximately \( 120^\circ \) in this planar region. However, the arrangement around the single-bonded nitrogens is approximately linear, suggesting a slight deviation in angle between the three nitrogens.
04

Bond Angles in Triaziridene

Triaziridene forms a three-membered ring. Such a small ring causes significant angle strain and typically results in bond angles smaller than \( 120^\circ \). These structures usually have bond angles approximating \( 60^\circ \), as a result of the triangular shape of the cyclic molecule.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis Structures
Lewis structures are a way to represent molecules where you use dots to indicate electrons and lines for bonds. When drawing a Lewis structure, we want to show how the atoms bond in a molecule, and often aim to satisfy the octet rule, which means each atom wants to have eight electrons in its outer shell.

To create a Lewis structure, you first count the total number of valence electrons available. Then, deciding on an arrangement of atoms, you arrange these electrons to form a stable structure. In triazene (\(\mathrm{N}_{2}\mathrm{H}_{3}\)) for instance, you would arrange nitrogen atoms linearly with a double bond, whereas in triaziridene, a cyclic formation is chosen.

  • Triazene: This compound features an "\( \mathrm{N} = \mathrm{N} \)" double bond, and the structure is non-cyclic.
  • Triaziridene: Contrastingly, this compound has only single bonds arranged in a cyclic pattern.
Molecular Geometry
Molecular geometry is about the shape of the molecule. It affects not just how a molecule looks but also its properties and how it interacts with other molecules. The shape is determined by the arrangement of bonded atoms and the electron pairs around a central atom.

In triazene, because of the "\( \mathrm{N} = \mathrm{N} \)" double bond, part of the molecule forms a trigonal planar shape, with angles around \(120^\circ\), due to the repulsion between atoms and non-bonding pairs trying to maximize distance.

On the other hand, triaziridene has a ring shape, which involves significant angle strain because the angles within a triangle are much smaller than \(120^\circ\). This significant angle strain gives triaziridene its unique properties and affects its reactivity.
Cyclic Compounds
Cyclic compounds have atoms connected in a loop. These structures can sometimes be harder to visualize and draw because of the constraints involved, such as ring strain.

In a cyclic compound like triaziridene, the nitrogen atoms form a ring. Because this makes a three-membered ring, it results in significant angle strain, **leading to bond angles of about \(60^\circ\).** This is much smaller than the optimal \(120^\circ\), leading to instability. Such compounds can have unique characteristics because of their cyclic nature.

These constraints make cyclic compounds interesting to study, due to the tension within their structures. This angle strain can influence both stability and reaction pathways, making cyclic compounds a crucial area of study in organic chemistry.

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Azidotrifluoromethane, \(\mathrm{CF}_{3} \mathrm{~N}_{3},\) is a colorless gas that is stable at room temperature. (a) Write a plausible Lewis structure for this compound and estimate the \(\mathrm{N}-\mathrm{N}-\mathrm{C}\) bond angle. (b) Estimate the \(\mathrm{N}-\mathrm{N}-\mathrm{N}\) bond angle. (c) Identify the hybridization of the central nitrogen atom and the hybridization of the carbon atom. (d) An intermediate compound with the molecular formula \(\mathrm{CF}_{3} \mathrm{~N}_{3} \mathrm{H}_{2}\) forms during the synthesis of azidotrifluoromethane. Draw the correct Lewis structures for two plausible resonance hybrids of this intermediate. Identify the hybridization of each nitrogen atom in each of the two structures.

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