Chapter 18: Problem 68
Cobalt- 60 is a therapeutic radioisotope used in treating certain cancers. A sample of cobalt-60 initially disintegrates at a rate of \(4.3 \times 10^{6} \mathrm{~s}^{-1}\) and after 21.2 years the rate has dropped to \(2.6 \times 10^{5} \mathrm{~s}^{-1}\). Calculate the half-life of cobalt- 60
Short Answer
Expert verified
The half-life of Cobalt-60 is approximately 5.29 years.
Step by step solution
01
Understand the problem and formula
We need to find the half-life of Cobalt-60 given the initial disintegration rate and the rate after 21.2 years. The equation governing the decay process is based on exponential decay: \( N(t) = N_0 e^{-\lambda t} \), where \( N(t) \) is the disintegration rate at time \( t \), \( N_0 \) is the initial disintegration rate, and \( \lambda \) is the decay constant. The half-life \( t_{1/2} \) is related to \( \lambda \) by the equation \( t_{1/2} = \frac{\ln 2}{\lambda} \).
02
Set up the decay equation
Use the exponential decay equation to express the rate of disintegration after 21.2 years: \( 2.6 \times 10^{5} = 4.3 \times 10^{6} e^{-\lambda \times 21.2} \).
03
Solve for the decay constant \( \lambda \)
Rearrange the equation from Step 2 to solve for \( \lambda \):\[ e^{-\lambda \cdot 21.2} = \frac{2.6 \times 10^{5}}{4.3 \times 10^{6}} = \frac{26}{430} \approx 0.060465 \] Take the natural logarithm of both sides to solve for \( \lambda \):\[ -\lambda \cdot 21.2 = \ln(0.060465) \] \[ \lambda = -\frac{\ln(0.060465)}{21.2} \].
04
Calculate \( \lambda \)
Compute \( \lambda \) using the values obtained in Step 3: \[ \lambda = -\frac{\ln(0.060465)}{21.2} \approx 0.1310 \text{ year}^{-1} \].
05
Calculate the half-life \( t_{1/2} \)
Use the decay constant from Step 4 to find the half-life: \[ t_{1/2} = \frac{\ln 2}{\lambda} = \frac{0.693}{0.1310} \approx 5.29 \text{ years} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-life
In radioactive decay, the half-life of a substance is the time it takes for half of the radioactive atoms in a sample to decay. It is a key concept because it helps us understand how long a radioactive material remains active or potentially hazardous. For Cobalt-60, the half-life is calculated using the decay constant found from actual decay data.
The half-life formula is given as:
For instance, in the case of Cobalt-60, the decay constant allows us to figure out its half-life, which is about 5.29 years. This tells us that every 5.29 years, half of any given amount of Cobalt-60 will have decayed.
The half-life formula is given as:
- \( t_{1/2} = \frac{\ln 2}{\lambda} \)
For instance, in the case of Cobalt-60, the decay constant allows us to figure out its half-life, which is about 5.29 years. This tells us that every 5.29 years, half of any given amount of Cobalt-60 will have decayed.
Decay Constant
The decay constant, denoted as \( \lambda \), is a fundamental concept in understanding radioactive decay processes. Simply put, it is a probability rate at which a specific type of radioactive atom will decay per unit time. High values of \( \lambda \) mean the isotope decays faster. It's a critical factor in the exponential decay equation which relates all the key parameters.
The decay constant is derived from the exponential decay formula:
For example, in the provided calculation, the decay constant was derived using experimental data over a span of 21.2 years, resulting in a value of approximately 0.1310 year^{-1}.
The decay constant is derived from the exponential decay formula:
- \( N(t) = N_0 e^{-\lambda t} \)
For example, in the provided calculation, the decay constant was derived using experimental data over a span of 21.2 years, resulting in a value of approximately 0.1310 year^{-1}.
Exponential Decay
Exponential decay describes a process where the quantity of a radioactive substance decreases at a rate proportional to its current amount. It's a consistent pattern seen across various radioactive materials. The concept can be visualized as a rapid decline initially, which slows over time.
The mathematical model of exponential decay is characterized by the equation:
This principled decay is consistently applied in various applications, such as dating archaeological finds, managing nuclear waste, and even understanding medical treatments using isotopes like Cobalt-60.
The mathematical model of exponential decay is characterized by the equation:
- \( N(t) = N_0 e^{-\lambda t} \)
This principled decay is consistently applied in various applications, such as dating archaeological finds, managing nuclear waste, and even understanding medical treatments using isotopes like Cobalt-60.