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Define the Gibbs free energy change of a chemical reaction in terms of its enthalpy and entropy changes. Why is the Gibbs free energy change especially useful in predicting whether a reaction is product-favored?

Short Answer

Expert verified
Gibbs free energy ( \( \Delta G = \Delta H - T \Delta S \)) determines reaction spontaneity, combining enthalpy and entropy.

Step by step solution

01

Understanding Gibbs Free Energy

Gibbs free energy change \( \Delta G \) is a thermodynamic quantity that combines enthalpy and entropy changes to determine whether a process will occur spontaneously. It is defined in terms of a system's enthalpy change \( \Delta H \), entropy change \( \Delta S \), and temperature \( T \).
02

Gibbs Free Energy Equation

The Gibbs free energy change is given by the equation \[ \Delta G = \Delta H - T \Delta S \] where \( T \) is the absolute temperature in Kelvin. This equation shows the relationship between enthalpy, entropy, and the spontaneity of a reaction.
03

Interpreting the Gibbs Equation

If \( \Delta G < 0 \), the reaction is spontaneous and product-favored under the given conditions. If \( \Delta G > 0 \), the reaction is non-spontaneous under the same conditions.
04

Significance of Gibbs Free Energy in Reactions

The Gibbs free energy change is particularly useful for predicting the favorability of a chemical reaction because it accounts for both energy (enthalpy) and order (entropy) changes, considering temperature effects. It provides a criterion for the direction of spontaneous change without needing to measure the surrounding conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy
Enthalpy, often symbolized by the letter \( H \), represents the heat content of a system. It is a fundamental concept in understanding energy exchanges during chemical reactions. Enthalpy change \( \Delta H \) refers to the difference in enthalpy between the products and the reactants in a chemical reaction. - **Exothermic Reactions**: These reactions release heat, resulting in a negative \( \Delta H \). - **Endothermic Reactions**: These reactions absorb heat, leading to a positive \( \Delta H \).In the context of Gibbs Free Energy, enthalpy provides insight into the energy dynamics of a reaction. A lower enthalpy change might favor a spontaneous reaction, but it is essential to consider it alongside entropy change to understand the reaction's overall feasibility.
Entropy
Entropy, denoted by \( S \), is a measure of disorder or randomness in a system. In simple terms, it quantifies how spread out or chaotic the energy within a system is. The change in entropy, \( \Delta S \), signifies the difference in disorder between the products and the reactants.- **Increased Entropy**: When \( \Delta S \) is positive, the reaction leads to a greater degree of disorder. This often occurs when gases form from liquids or solids, boosting spontaneity. - **Decreased Entropy**: A negative \( \Delta S \) indicates a decrease in disorder, which can happen when gases condense into liquids or solids.Entropy is a vital factor in determining the spontaneity of a reaction. The Gibbs Free Energy equation \( \Delta G = \Delta H - T \Delta S \) demonstrates how entropy plays a critical role, as it can oppose or enhance the effects of enthalpy change depending on temperature.
Spontaneity of Reactions
The spontaneity of a chemical reaction refers to whether a reaction will occur on its own without any external intervention. The Gibbs Free Energy change \( \Delta G \) is the ultimate criterion used to predict spontaneity. A negative \( \Delta G \) indicates that the reaction is spontaneous and will proceed towards the formation of products under the given conditions. On the other hand, a positive \( \Delta G \) means the reaction is non-spontaneous and requires external energy to proceed. Key points about spontaneity:
  • Spontaneity relates directly to the sign of \( \Delta G \).
  • The temperature (\( T \)) in the \( \Delta G = \Delta H - T \Delta S \) equation is crucial since it influences the impact of entropy (\( \Delta S \)).
  • Reactions might be spontaneous at one temperature and non-spontaneous at another, illustrating the dynamic interplay between enthalpy, entropy, and temperature.
Understanding spontaneity is crucial for chemists and industry professionals as it dictates reaction conditions for desired product formation and efficiency.

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Most popular questions from this chapter

For each process, tell whether the entropy change of the system is positive or negative. (a) Water boils. (b) A teaspoon of sugar dissolves in a cup of coffee. (The system consists of both sugar and coffee.) (c) Calcium carbonate precipitates out of water in a cave to form stalactites and stalagmites. (Consider only the calcium carbonate to be the system.)

Using the reactions $$ \begin{array}{l} 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(\ell) \\ 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \end{array} $$ as an example, explain why it may be incorrect to assun for reactions involving solids or liquids that \(\Delta_{\mathrm{r}} S^{\circ}\) and \(\Delta_{1} H^{\circ}\) do not change appreciably with increasing temperature.

Appendix J lists standard molar entropies \(S^{\circ},\) not standard entropies of formation \(\Delta_{\mathrm{f}} S^{\circ} .\) Why is this possible for entropy but not for internal energy, enthalpy, or Gibbs free energy?

How can kinetically stable substances exist at all if they are not thermodynamically stable?

Without consulting tables of \(\Delta_{\mathrm{f}} H^{\circ}, S^{\circ},\) or \(\Delta_{\mathrm{f}} G^{\circ}\) values, predict which of these reactions is (i) always product-favored. (ii) product-favored at low temperatures, but not productfavored at high temperatures. (iii) not product-favored at low temperatures, but productfavored at high temperatures. (iv) never product-favored. (a) \(2 \mathrm{NO}_{2}(\mathrm{~g}) \longrightarrow \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g})\) (b) \(\mathrm{C}_{5} \mathrm{H}_{12}(\mathrm{~g})+8 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 5 \mathrm{CO}_{2}(\mathrm{~g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) (c) \(\mathrm{P}_{4}(\mathrm{~g})+10 \mathrm{~F}_{2}(\mathrm{~g}) \longrightarrow 4 \mathrm{PF}_{5}(\mathrm{~g})\)

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