Chapter 15: Problem 126
An experiment requires the addition of 0.075 mol gaseous \(\mathrm{NH}_{3}\) to \(1.0 \mathrm{~L}\) of \(0.025-\mathrm{M} \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2} .\) Ammonium chloride, \(\mathrm{NH}_{4} \mathrm{Cl}\), is added prior to the addition of the \(\mathrm{NH}_{3}\) to prevent precipitation of \(\mathrm{Mg}(\mathrm{OH})_{2} .\) Calculate the minimum mass in grams of ammonium chloride that must be added. \(K_{\mathrm{sp}}\) of \(\mathrm{Mg}(\mathrm{OH})_{2}=1.8 \times 10^{-11}\)
Short Answer
Step by step solution
Write the dissociation equations
Calculate hydroxide ion concentration
Solve for [OH^-]
Calculate ammonia concentration
Calculate minimum mass of NH4Cl
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solubility Product Constant
The reaction for any precipitation can be written as:
\[ AB(s) \rightleftharpoons A^{+}(aq) + B^{-}(aq) \]
The \(K_{sp}\) for this reaction is expressed as:
\[ K_{sp} = [A^{+}][B^{-}] \]
In the case of magnesium hydroxide (\(\text{Mg(OH)}_2\)), this reaction is:
\[ \text{Mg}^{2+} + 2\text{OH}^- \rightleftharpoons \text{Mg(OH)}_2 \]
The \(K_{sp}\) expression becomes:
\[ K_{sp} = [\text{Mg}^{2+}][\text{OH}^-]^2 \]
A small \(K_{sp}\) value, like \(1.8 \times 10^{-11}\) for magnesium hydroxide, indicates that only a tiny amount of solid dissolves, making it a low solubility substance. Understanding the \(K_{sp}\) is crucial to avoid unwanted precipitates in reactions.
Dissociation Equations
For ammonium chloride \((\text{NH}_4\text{Cl})\), the dissociation is straightforward as it splits into ammonium \((\text{NH}_4^+)\) and chloride ions \((\text{Cl}^-)\):
\[ \text{NH}_4\text{Cl} \rightarrow \text{NH}_4^+ + \text{Cl}^- \]
Similarly, when magnesium hydroxide \((\text{Mg(OH)}_2)\) dissociates in solution, it forms magnesium ions \((\text{Mg}^{2+})\) and hydroxide ions \((\text{OH}^-)\):
\[ \text{Mg(OH)}_2 \rightarrow \text{Mg}^{2+} + 2\text{OH}^- \]
These equations are fundamental to understanding how the components interact in a system, affecting factors such as solubility and the potential formation of a precipitate.
This understanding allows for precise control in experimental settings, ensuring reactions proceed as desired.
Hydroxide Ion Concentration
To prevent the precipitation of magnesium hydroxide \((\text{Mg(OH)}_2)\), keeping the \([\text{OH}^-]\) concentration below a certain threshold is essential.
The \(K_{sp}\) equation for magnesium hydroxide demonstrates this:
\[ K_{sp} = [\text{Mg}^{2+}] [\text{OH}^-]^2 \]
Solving for \([\text{OH}^-]^2\), given a fixed \([\text{Mg}^{2+}]\), provides the maximum allowable \([\text{OH}^-]\). In this scenario, calculated to be approximately \(2.68 \times 10^{-5} \text{M}\).
Exceeding this concentration results in the formation of a solid \(\text{Mg(OH)}_2)\) precipitate.
Understanding this balance is crucial for controlling reactions in laboratory and industrial processes.
Ammonia and Ammonium Ion Equilibrium
\[ \text{NH}_3 + \text{H}_2\text{O} \rightleftharpoons \text{NH}_4^+ + \text{OH}^- \]
When ammonium chloride \((\text{NH}_4\text{Cl})\) is added to a solution, it increases the \([\text{NH}_4^+]\) concentration.
This action drives the equilibrium to the left, reducing \([\text{OH}^-]\) and preventing the precipitation of magnesium hydroxide.
This aspect allows the control of \([\text{OH}^-]\) in the solution by adjusting \([\text{NH}_4^+]\) accordingly, which is calculated to be necessary for preventing unwanted reactions.
For students, mastering this concept can open doors to a deeper understanding of chemical equilibria and their practical applications.