/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 Write a chemical equation that i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write a chemical equation that illustrates how the hydrated \(\mathrm{Ni}^{2+}\) ion, \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\), acts as an acid in aqueous solution.

Short Answer

Expert verified
\([ ext{Ni(H}_2 ext{O)}_6]^{2+} + \text{H}_2\text{O} \rightarrow [\text{Ni(H}_2\text{O)}_5(\text{OH})]^+ + \text{H}_3\text{O}^+\).

Step by step solution

01

Understanding the Acidic Nature

The hydrated nickel ion, \([ ext{Ni(H}_2 ext{O)}_6]^{2+}\), acts as an acid in aqueous solutions by donating a proton (H\(^+\)) from one of the water molecules attached to the nickel ion. This causes the formation of hydronium ion \(\text{H}_3\text{O}^{+}\) and a complex with one less water molecule.
02

Formula Representation of Proton Donation

When \([ ext{Ni(H}_2 ext{O)}_6]^{2+}\) acts as an acid, it donates a proton to water, forming \(\text{H}_3\text{O}^{+}\) and \(\left[ ext{Ni(H}_2 ext{O)}_5( ext{OH})\right]^+\). This can be represented by the following chemical equation: \[[A ext{Ni(H}_2 ext{O)}_6]^{2+} + ext{H}_2 ext{O} \rightarrow [ ext{Ni(H}_2 ext{O)}_5( ext{OH})]^+ + ext{H}_3 ext{O}^+.\]
03

Balanced Chemical Equation

Ensure that the equation is properly balanced in terms of charge and mass. In this situation, both the number of atoms of each element and the net charge are balanced: \((+2) + (0) = (+1) + (+1)\). So, we have the equation: \[[ ext{Ni(H}_2 ext{O)}_6]^{2+} + ext{H}_2 ext{O} \rightarrow [ ext{Ni(H}_2 ext{O)}_5( ext{OH})]^+ + ext{H}_3 ext{O}^+.\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Hydrated Ions
Hydrated ions form when ions interact with water molecules in an aqueous solution. The water molecules organize around the ion due to electrostatic interactions. In the case of the \([\text{Ni(H}_2\text{O)}_6]^{2+}\) ion, six water molecules surround the central nickel ion. This creates a structure where the nickel ion is at the center, and the water molecules act as a shield or cushion around it.
  • Hydration stabilizes ions and affects their reactivity.
  • The number of water molecules surrounding an ion can vary, but for transition metal ions like \(\mathrm{Ni}^{2+}\), it is commonly six.
  • These interactions are essential as they define the ion's behavior and characteristics in solution.
Hydration helps ions remain suspended in the solution and significantly influences their chemical properties. Understanding this concept is crucial as it is often the key to predicting how these ions will react with other substances in a solution.
Exploring Proton Donation
Proton donation is a hallmark of acidic behavior in chemistry. It refers to the process where a molecule or ion donates a hydrogen ion (H\(^+\)) to another species. The hydrated nickel complex \([\text{Ni(H}_2\text{O)}_6]^{2+}\), acts as a weak acid.When it donates a proton to water, the water molecule accepts the proton and forms a \,\text{hydronium ion} \(\text{H}_3\text{O}^{+}\). The nickel complex loses one water molecule, converting into \([\text{Ni(H}_2\text{O)}_5(\text{OH})]^+\). This process is summed up by the chemical equation:\[ [\text{Ni(H}_2\text{O)}_6]^{2+} + \text{H}_2\text{O} \rightarrow [\text{Ni(H}_2\text{O)}_5(\text{OH})]^+ + \text{H}_3\text{O}^+ \]
Understanding proton donation is important because:
  • It is a key process in many chemical reactions, especially those involving acids and bases.
  • Proton transfer affects pH levels in solutions, which can influence the outcome of a reaction.
  • It helps in predicting equilibrium states and determining the strength of acids.
Insights into Chemical Equilibrium
Chemical equilibrium is the state where the concentrations of reactants and products remain constant over time. This occurs when the forward and reverse reactions occur at the same rate. In the context of the hydrated nickel complex, after donating a proton, the system can reach equilibrium.Even though the equation:\[ [\text{Ni(H}_2\text{O)}_6]^{2+} + \text{H}_2\text{O} \rightleftharpoons [\text{Ni(H}_2\text{O)}_5(\text{OH})]^+ + \text{H}_3\text{O}^+ \]appears one-way, it can exist in dynamic equilibrium. This means the reverse reaction, where \([\text{Ni(H}_2\text{O)}_5(\text{OH})]^+\) accepts a proton to revert to \([\text{Ni(H}_2\text{O)}_6]^{2+}\), also occurs.Equilibrium concepts are vital because:
  • They allow us to understand reaction completeness and yield.
  • They are crucial in optimizing conditions in industrial chemical processes.
  • The equilibrium constant provides insight into the ratio of products to reactants at equilibrium.
By studying equilibrium, chemists can manipulate and predict the outcomes of chemical reactions efficiently.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the ionization equation for a weak acid and the equation for its conjugate base reaction with water. Show that adding these two equations gives the autoionization equation for water.

Write a chemical equation to describe the proton transfer that occurs when each of these bases is added to water. (a) \(\mathrm{PO}_{4}^{3-}\) (b) \(\mathrm{SO}_{3}^{2-}\) (c) \(\mathrm{HPO}_{4}^{2-}\)

Identify the Lewis acid and the Lewis base in each reaction. (a) \(\mathrm{H}_{2} \mathrm{O}(\ell)+\mathrm{SO}_{2}(\mathrm{aq}) \longrightarrow \mathrm{H}_{2} \mathrm{SO}_{3}(\mathrm{aq})\) (b) \(\mathrm{H}_{3} \mathrm{BO}_{3}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) \longrightarrow \mathrm{B}(\mathrm{OH})_{4}^{-}(\mathrm{aq})\) (c) \(\mathrm{Cu}^{2+}(\mathrm{aq})+4 \mathrm{NH}_{3}(\mathrm{aq}) \longrightarrow\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}(\mathrm{aq})\) (d) \(2 \mathrm{Cl}^{-}(\mathrm{aq})+\mathrm{SnCl}_{2}(\mathrm{aq}) \longrightarrow \mathrm{SnCl}_{4}^{2-}(\mathrm{aq})\)

Ascorbic acid (vitamin \(\left.\mathrm{C}, \mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{6}\right)\) is a diprotic acid \(\left(K_{\mathrm{a}_{1}}=7.9 \times 10^{-5}, K_{\mathrm{a}_{2}}=1.6 \times 10^{-12}\right) .\) Calculate the \(\mathrm{pH}\) of a solution that contains \(5.0 \mathrm{mg}\) acid per mL water. (Assume that only the first ionization is important in determining pH.)

The measured \(\mathrm{pH}\) of a sample of seawater is 8.30 . (a) Calculate the \(\mathrm{H}_{3} \mathrm{O}^{+}\) concentration. (b) Is the sample acidic or basic?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.