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Write a chemical equation to describe the proton transfer that occurs when each of these acids is added to water. (a) HIO (b) \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{4} \mathrm{COOH}\) (c) HOOCCOOH (d) \(\mathrm{CH}_{3} \mathrm{NH}_{3}^{+}\)

Short Answer

Expert verified
Equations: (a) HIO + H鈧侽 鈫 IO鈦 + H鈧僌鈦; (b) Pentanoic acid + H鈧侽 鈫 carboxylate + H鈧僌鈦; (c) Oxalic acid + H鈧侽 鈫 hydrogen oxalate + H鈧僌鈦; (d) Methylammonium ion + H鈧侽 鈫 methylamine + H鈧僌鈦.

Step by step solution

01

Understand Proton Transfer

Proton transfer involves an acid donating a proton (H鈦) to water or to a base, forming the conjugate base of the acid and hydronium ion (H鈧僌鈦). This is a crucial step in understanding acid-base reactions.
02

Write Chemical Equation for HIO

For hypoiodous acid (HIO), it donates a proton to water: \[ \text{HIO} + \text{H}_2\text{O} \rightarrow \text{IO}^- + \text{H}_3\text{O}^+ \] Here, HIO acts as the acid, water as the base, resulting in IO鈦 as the conjugate base and H鈧僌鈦.
03

Write Chemical Equation for Pentanoic Acid

For the carboxylic acid \(\text{CH}_3(\text{CH}_2)_4\text{COOH}\), it donates a proton to water: \[ \text{CH}_3(\text{CH}_2)_4\text{COOH} + \text{H}_2\text{O} \rightarrow \text{CH}_3(\text{CH}_2)_4\text{COO}^- + \text{H}_3\text{O}^+ \] The carboxylic acid donates an H鈦 to form the corresponding carboxylate ion and hydronium.
04

Write Chemical Equation for Oxalic Acid

For oxalic acid (HOOCCOOH), it donates a proton to water: \[ \text{HOOCCOOH} + \text{H}_2\text{O} \rightarrow \text{HOOC-COO}^- + \text{H}_3\text{O}^+ \] Oxalic acid loses a proton to form the hydrogen oxalate ion and the hydronium ion.
05

Write Chemical Equation for Methylammonium Ion

For the methylammonium ion \(\text{CH}_3\text{NH}_3^+\), it donates a proton to water: \[ \text{CH}_3\text{NH}_3^+ + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{NH}_2 + \text{H}_3\text{O}^+ \] The methylammonium ion acts as an acid, transferring a proton to water, resulting in methylamine and hydronium.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reactions
Acid-base reactions, also known as proton transfer reactions, are fundamental chemical processes where an acid transfers a proton (H鈦) to a base. In simpler terms, the acid loses a hydrogen ion, while the base gains it. This process often results in the formation of a conjugate base from the acid, and a conjugate acid from the base. Typically, water acts as a base in these reactions, accepting a proton to become the hydronium ion (H鈧僌鈦).To understand these reactions, consider the role of each participant:
  • An **acid** is a molecule or ion that donates a proton.
  • A **base** is a molecule or ion that accepts a proton.
The reaction can usually be generalized by the equation:\[ \text{HA} + \text{B} \rightarrow \text{A}^- + \text{HB}^+ \]Here, HA represents an acid, which donates a proton to B, a base. As a result, A鈦 is the conjugate base, and HB鈦 the conjugate acid.
Conjugate Base
When an acid donates a proton during an acid-base reaction, it transforms into a conjugate base. The conjugate base is what remains of the acid after it has released a proton. Understanding conjugate bases is crucial for predicting the outcome of reactions and their corresponding strengths.For instance, in the reaction of hypoiodous acid (HIO) with water:\[ \text{HIO} + \text{H}_2\text{O} \rightarrow \text{IO}^- + \text{H}_3\text{O}^+ \]HIO donates a proton to water, resulting in the conjugate base IO鈦. This conjugate base can be used to measure the strength of the original acid. A strong acid will generally produce a weak conjugate base, and vice versa.Here鈥檚 what to remember:
  • The **conjugate base** often helps maintain equilibrium in solutions.
  • Increased stability of a conjugate base implies lower proton affinity.
  • A weak conjugate base suggests a strong parent acid.
Hydronium Ion
In many acid-base reactions, particularly those involving water, the hydronium ion (H鈧僌鈦) is a key product. It results when water acts as a proton acceptor, gaining an additional hydrogen ion (H鈦). This transformation is central to defining the acidity in aqueous solutions.Consider the reaction of pentanoic acid (\(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{4} \mathrm{COOH}\)) with water:\[ \mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{4}\mathrm{COOH} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{4}\mathrm{COO}^- + \mathrm{H}_{3}\mathrm{O}^+ \]In this scenario, water receives a proton from the acid, forming the hydronium ion (H鈧僌鈦). This ion is significant because:
  • It indicates the presence of an acidic environment.
  • Its concentration is directly associated with the pH of the solution.
  • High levels of H鈧僌鈦 denote a low pH, indicating stronger acidity.
The hydronium ion plays a crucial role in many chemical reactions, acting as a medium that facilitates proton transfers and acidity measurement.

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