Chapter 13: Problem 37
Show mathematically how 1 ppb is equivalent to \(1 \mu \mathrm{g} / 1 \mathrm{~kg}\).
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Chapter 13: Problem 37
Show mathematically how 1 ppb is equivalent to \(1 \mu \mathrm{g} / 1 \mathrm{~kg}\).
These are the key concepts you need to understand to accurately answer the question.
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Explain why the Tyndall effect is not observed with solutions.
(a) Calculate the molality of a solution made by dissolving \(115.0 \mathrm{~g}\) ethylene glycol, \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH},\) in \(500 . \mathrm{mL}\) water. The density of water at this temperature is \(0.978 \mathrm{~g} / \mathrm{mL}\) (b) Calculate the molarity of the solution.
Why would the same solid readily dissolve in one liquid and be almost insoluble in another liquid? Give an example of such behavior.
The maximum contamination level (MCL) for chlordane is 0.002 ppm. A sample of well water contained 5 ppb chlordane. Is the sample within the MCL for chlordane?
Describe what happens when an ionic solid dissolves in water. Sketch an illustration that includes at least three positive ions, three negative ions, and a dozen or so water molecules in the vicinity of the ions.
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