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Decomposition of ammonium dichromate is shown in the designated series of photos. In a closed container this process reaches an equilibrium state. Write a balanced chemical equation for the equilibrium reaction. How is the equilibrium affected if (a) more ammonium dichromate is added to the equilibrium system? (b) more water vapor is added? (c) more chromium(III) oxide is added?

Short Answer

Expert verified
(a) Shifts right; (b) Shifts left; (c) No effect.

Step by step solution

01

Write the decomposition reaction

The decomposition reaction of ammonium dichromate is shown by the equation: \[ \text{(NH}_4\text{)}_2\text{Cr}_2\text{O}_7 (s) \rightarrow \text{Cr}_2\text{O}_3 (s) + \text{N}_2 (g) + 4\text{H}_2\text{O} (g) \] This represents the ammonium dichromate breaking down into chromium(III) oxide, nitrogen gas, and water vapor.
02

Consider the equilibrium state

In the closed container, the reaction establishes an equilibrium between the reactants and products. Therefore, the equilibrium reaction would be: \[ \text{(NH}_4\text{)}_2\text{Cr}_2\text{O}_7 (s) \leftrightarrow \text{Cr}_2\text{O}_3 (s) + \text{N}_2 (g) + 4\text{H}_2\text{O} (g) \] This equation is balanced as written.
03

Analyze the effect of adding ammonium dichromate

Adding more ammonium dichromate (\(\text{(NH}_4\text{)}_2\text{Cr}_2\text{O}_7\)) to the system increases the concentration of reactants. According to Le Chatelier's principle, the equilibrium will shift to the right, favoring the formation of products \(\text{Cr}_2\text{O}_3\), \(\text{N}_2\), and \(\text{H}_2\text{O}\).
04

Analyze the effect of adding water vapor

Adding more water vapor (\(\text{H}_2\text{O}\)) will increase the concentration of gaseous products. According to Le Chatelier's principle, the equilibrium shifts to the left to counteract the change, favoring the decomposition of \(\text{Cr}_2\text{O}_3\), \(\text{N}_2\), and \(\text{H}_2\text{O}\) back to ammonium dichromate.
05

Analyze the effect of adding chromium(III) oxide

Adding more chromium(III) oxide \(\text{Cr}_2\text{O}_3\) does not affect the equilibrium because \(\text{Cr}_2\text{O}_3\) is a solid, and changes in the amount of a pure solid do not affect the position of equilibrium in a reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Le Chatelier's Principle
Le Chatelier's Principle is a fundamental concept in the study of chemical equilibria. It helps predict how a change in conditions affects a chemical equilibrium. When a system at equilibrium experiences a change in concentration, temperature, or pressure, it will adjust to minimize that change and achieve a new equilibrium state.
  • If a reactant is added, the equilibrium shifts to the right, favoring product formation.
  • If a product is added, the equilibrium shifts to the left, favoring reactant formation.
  • Changes in concentration of solids or liquids typically do not affect equilibrium, whereas changes in gases do.
In the case of ammonium dichromate decomposition, adding more ( ext{NH}_4 ext{)}_2 ext{Cr}_2 ext{O}_7 ext{)} will shift the equilibrium towards the formation of more products, while adding more water vapor shifts it the opposite way. This principle provides a powerful tool for predicting the direction of the shift based on various stressors.
Ammonium Dichromate Decomposition
Ammonium dichromate, ( ext{NH}_4 ext{)}_2 ext{Cr}_2 ext{O}_7, is an interesting compound due to its vivid decomposition reaction, which can be demonstrated through a striking volcanic-like eruption. During decomposition, it breaks into chromium(III) oxide ( ext{Cr}_2 ext{O}_3 ), nitrogen gas ( ext{N}_2 ), and water vapor ( 4 ext{H}_2 ext{O} ). This decomposition reaction is often used as a dramatic demonstration of chemical change.
In a closed container, the reaction reaches a dynamic equilibrium, meaning the rate of decomposition of ammonium dichromate equals the rate of formation from its decomposition products. Observing this process helps to understand the principles of equilibrium and reaction dynamics in a controlled environment. The reaction also serves as an excellent illustration for Le Chatelier's principle in action, particularly when observing shifts in equilibrium due to changes in reactant or product concentrations.
Balanced Chemical Equation
A balanced chemical equation represents the transmutation of reactants into products while maintaining the law of conservation of mass. This means the number of atoms of each element must remain constant through the reaction. For the decomposition of ammonium dichromate, the equation is:\[ \text{(NH}_4\text{)}_2\text{Cr}_2\text{O}_7\ (s) \leftrightarrow \text{Cr}_2\text{O}_3\ (s) + \text{N}_2\ (g) + 4\text{H}_2\text{O}\ (g) \]This balanced equation shows the breakdown of one mole of solid ammonium dichromate into one mole of chromium(III) oxide, one mole of nitrogen gas, and four moles of water vapor.
Properly balancing chemical equations is crucial in chemistry as it ensures stoichiometric relationships, allowing for predictions of amounts of reactants needed or products formed. Such representations are not only vital for understanding chemical reactions but also for qualitative analysis and calculations in real-world applications.

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Most popular questions from this chapter

The chemistry of compounds composed of a transition metal and carbon monoxide has been an interesting area of research for more than 70 years. \(\mathrm{Ni}(\mathrm{CO})_{4}\) is formed by the reaction of nickel metal with carbon monoxide. (a) Calculate the mass of \(\mathrm{Ni}(\mathrm{CO})_{4}\) that can be formed if you combine \(2.05 \mathrm{~g} \mathrm{CO}\) with \(0.125 \mathrm{~g}\) nickel metal.(b) An excellent way to make pure nickel metal is to decompose \(\mathrm{Ni}(\mathrm{CO})_{4}\) in a vacuum at a temperature slightly higher than room temperature. If the standard formation enthalpy of \(\mathrm{Ni}(\mathrm{CO})_{4}\) gas is \(-602.9 \mathrm{~kJ} / \mathrm{mol}\), calculate the enthalpy change for this decomposition reaction. $$ \mathrm{Ni}(\mathrm{CO})_{4}(\mathrm{~g}) \longrightarrow \mathrm{Ni}(\mathrm{s})+4 \mathrm{CO}(\mathrm{g}) $$ (c) Predict whether there is an increase or a decrease in entropy when this reaction occurs. (d) In an experiment at \(100 .{ }^{\circ} \mathrm{C}\) it is determined that with \(0.010 \mathrm{~mol} \mathrm{Ni}(\mathrm{CO})_{4}(\mathrm{~g})\) initially present in a sealed \(1.0-\mathrm{L}\) flask, only 0.000010 mol remains after decomposition. (i) Calculate the equilibrium concentration of \(\mathrm{CO}\) in the flask. (ii) Calculate the value of the equilibrium constant \(K_{\mathrm{c}}\) for this reaction at \(100 .{ }^{\circ} \mathrm{C}\). (iii) Calculate the equilibrium constant \(K_{\mathrm{P}}\) for this reaction at \(100 .{ }^{\circ} \mathrm{C}\).

Carbonylbromide, \(\mathrm{COBr}_{2}\), can be formed by combining carbon monoxide and bromine gas. $$ \mathrm{CO}(\mathrm{g})+\mathrm{Br}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{COBr}_{2}(\mathrm{~g}) $$ When equilibrium is established at \(346 \mathrm{~K},\) the partial pressures (in atm) of \(\mathrm{COBr}_{2}, \mathrm{CO},\) and \(\mathrm{Br}_{2}\) are 0.12,1.00 , and \(0.65,\) respectively. (a) Calculate \(K_{\mathrm{p}}\) at \(346 \mathrm{~K}\). (b) Enough bromine condenses to decrease its partial pressure to 0.50 atm. Calculate the equilibrium partial pressures of all gases after equilibrium is re-established.

The equilibrium constant, \(K_{\mathrm{c}}\), for the reaction $$ \mathrm{Br}_{2}(\mathrm{~g})+\mathrm{F}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{BrF}(\mathrm{g}) $$ is 55.3 . Calculate what the equilibrium concentrations of all these gases are if the initial concentrations of bromine and fluorine were both \(0.220 \mathrm{~mol} / \mathrm{L}\). (Assume constantvolume conditions.)

Write equilibrium constant expressions, in terms of reactant and product concentrations, for each of these reactions. $$ \mathrm{H}_{2} \mathrm{O}(\ell) \rightleftharpoons \mathrm{H}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) \quad K_{\mathrm{c}}=1.0 \times 10^{-14} $$ \(\mathrm{CH}_{3} \mathrm{COOH}(\mathrm{aq}) \rightleftharpoons \mathrm{CH}_{3} \mathrm{COO}^{-}(\mathrm{aq})+\mathrm{H}^{+}(\mathrm{aq})\) $$ \begin{array}{c} K_{\mathrm{c}}=1.8 \times 10^{-5} \\ \mathrm{~N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g}) \end{array} $$ Assume that all gases and solutes have initial concentrations of \(1.0 \mathrm{~mol} / \mathrm{L}\). Then let the first reactant in each reaction change its concentration by \(-x\). (a) Using the reaction table (ICE table) approach, write equilibrium constant expressions in terms of the unknown variable \(x\) for each reaction. (b) Which of these expressions yield quadratic equations? (c) How would you go about solving the others for \(x ?\)

List three characteristics that you would need to verify in order to determine that a chemical system is at equilibrium.

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