Chapter 12: Problem 1
Define the terms chemical equilibrium and dynamic equilibrium.
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Chapter 12: Problem 1
Define the terms chemical equilibrium and dynamic equilibrium.
These are the key concepts you need to understand to accurately answer the question.
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If an equilibrium is product-favored, is its equilibrium constant large or small with respect to \(1 ?\) Explain.
Write the equilibrium constant expression for each of these heterogeneous systems. (a) \(\mathrm{CaSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}(\mathrm{s}) \rightleftharpoons \mathrm{CaSO}_{4} \cdot 3 \mathrm{H}_{2} \mathrm{O}(\mathrm{s})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) (b) \(\mathrm{SiF}_{4}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{SiO}_{2}(\mathrm{~s})+4 \mathrm{HF}(\mathrm{g})\) (c) \(\mathrm{LaCl}_{3}(\mathrm{~s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{LaClO}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{g})\)
Indicate whether each statement below is true or false. If a statement is false, rewrite it to produce a closely related statement that is true. (a) For a given reaction, the magnitude of the equilibrium constant is independent of temperature. (b) If there is an increase in entropy and a decrease in enthalpy when reactants in their standard states are converted to products in their standard states, the equilibrium constant for the reaction must be negative. (c) The equilibrium constant for the reverse of a reaction is the reciprocal of the equilibrium constant for the reaction itself. (d) For the reaction $$ \mathrm{H}_{2} \mathrm{O}_{2}(\ell) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(\ell)+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) $$ the equilibrium constant is one half the magnitude of the equilibrium constant for the reaction $$ 2 \mathrm{H}_{2} \mathrm{O}_{2}(\ell) \rightleftharpoons 2 \mathrm{H}_{2} \mathrm{O}(\ell)+\mathrm{O}_{2}(\mathrm{~g}) $$
Write equilibrium constant expressions, in terms of reactant and product concentrations, for each of these reactions. $$ \mathrm{H}_{2} \mathrm{O}(\ell) \rightleftharpoons \mathrm{H}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) \quad K_{\mathrm{c}}=1.0 \times 10^{-14} $$ \(\mathrm{CH}_{3} \mathrm{COOH}(\mathrm{aq}) \rightleftharpoons \mathrm{CH}_{3} \mathrm{COO}^{-}(\mathrm{aq})+\mathrm{H}^{+}(\mathrm{aq})\) $$ \begin{array}{c} K_{\mathrm{c}}=1.8 \times 10^{-5} \\ \mathrm{~N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g}) \end{array} $$ Assume that all gases and solutes have initial concentrations of \(1.0 \mathrm{~mol} / \mathrm{L}\). Then let the first reactant in each reaction change its concentration by \(-x\). (a) Using the reaction table (ICE table) approach, write equilibrium constant expressions in terms of the unknown variable \(x\) for each reaction. (b) Which of these expressions yield quadratic equations? (c) How would you go about solving the others for \(x ?\)
The reaction of hydrazine, \(\mathrm{N}_{2} \mathrm{H}_{4},\) with chlorine trifluoride, \(\mathrm{ClF}_{3}\), has been used in experimental rocket motors. \(\mathrm{N}_{2} \mathrm{H}_{4}(\mathrm{~g})+\frac{4}{3} \mathrm{ClF}_{3}(\mathrm{~g}) \rightleftharpoons 4 \mathrm{HF}(\mathrm{g})+\mathrm{N}_{2}(\mathrm{~g})+\frac{2}{3} \mathrm{Cl}_{2}(\mathrm{~g})\) How is the equilibrium constant, \(K_{\mathrm{p}}\), for this reaction related to \(K_{\mathrm{p}}^{\prime}\) for the reaction written this way? $$ \mathrm{N}_{2} \mathrm{H}_{4}(\mathrm{~g})+4 \mathrm{ClF}_{3}(\mathrm{~g}) \rightleftharpoons 12 \mathrm{HF}(\mathrm{g})+3 \mathrm{~N}_{2}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) $$ (a) \(K_{\mathrm{P}}=K_{\mathrm{P}}^{\prime}\) (b) \(K_{\mathrm{P}}=1 / K_{\mathrm{P}}^{\prime}\) (c) \(K_{\mathrm{p}}^{3}=K_{\mathrm{P}}^{\prime}\) (d) \(K_{\mathrm{P}}=\left(K_{\mathrm{P}}^{\prime}\right)^{3}\) (e) \(3 K_{\mathrm{p}}=K_{\mathrm{P}}^{\prime}\)
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