/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 If a battery can release \(535 \... [FREE SOLUTION] | 91Ó°ÊÓ

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If a battery can release \(535 \mathrm{~J}\) of energy and \(455 \mathrm{~J}\) are used for work, how much energy is released as heat?

Short Answer

Expert verified
80 J of energy is released as heat.

Step by step solution

01

Identify Given Values

Start by identifying the total energy released by the battery and the amount of energy used for work. According to the exercise, the battery releases a total of 535 J of energy and 455 J are used for work.
02

Calculate the Energy Released as Heat

The energy that is not used for work is released as heat. Use the conservation of energy principle, where the total energy released by the battery is the sum of the energy used for work and the energy released as heat. Subtract the energy used for work from the total energy to find the energy released as heat: Energy released as heat = Total energy - Energy used for work.
03

Complete the Calculation

Substitute the given values into the equation to find the energy released as heat: Energy released as heat = 535 J - 455 J.
04

Final Result

Complete the subtraction to find the energy released as heat: Energy released as heat = 80 J. This is the amount of energy that was released as heat by the battery.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamics
Thermodynamics is the branch of physics that deals with the relationships and conversions between heat and other forms of energy. It's at the very heart of physics, chemistry, and engineering, and is vital in understanding the behavior of gases and vapors. One of the most fundamental concepts in thermodynamics is the first law, which states that energy cannot be created or destroyed, only transferred or transformed.

In the context of our exercise, where a battery releases energy, thermodynamics helps us understand how this energy can be converted into work – like powering a device – or released as heat. It’s through the principles of thermodynamics that we can predict and calculate these energy transformations, ensuring energy conservation holds true. Students need to appreciate that when a battery 'loses' energy, it doesn't disappear but is merely converted into different forms, adhering to the laws of thermodynamics.
Heat Energy
Heat energy, often referred to simply as heat, is the manifestation of thermal energy as it naturally transfers from one body or substance to another. It flows from regions or objects at higher temperatures to those at lower temperatures. In our problem, the portion of energy from the battery that isn't used for work is converted into heat.

Understanding heat energy is central to solving problems like the textbook exercise. Students should be aware that energy conversions often involve generating heat as a by-product. It's important to identify that heat is not just a waste product; it can be harnessed for useful purposes, but in some cases, like with the battery, it can also indicate inefficiencies in the energy conversion process.
Work-Energy Principle
The work-energy principle is a fundamental concept in physics which states that work done on an object is equivalent to the change in its kinetic energy. In other words, work results in energy transfer. This principle helps us solve problems where forces are applied to objects and we're interested in the resulting motion or energy changes.

Applying this principle to the battery problem, we can determine that part of the battery's energy is spent on doing work, such as lighting a bulb or moving a motor. The rest of the energy, as our step-by-step calculation shows, is not used for work, which, by the conservation of energy, is released as heat. The calculation we completed employs the work-energy principle. We took the total energy from the battery and subtracted the energy used to perform work, hence determining the leftover transferred as heat. It's crucial for students to recognize that the work done is just another form of energy and can be equated and accounted for within the total energy balance of a system.

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Most popular questions from this chapter

Given the following thermochemical equations, $$ 3 \mathrm{Mg}(s)+2 \mathrm{NH}_{3}(g) \longrightarrow \mathrm{Mg}_{3} \mathrm{~N}_{2}(s)+3 \mathrm{H}_{2}(g) $$ \(\Delta H^{\circ}=-371 \mathrm{~kJ}\) $$ \frac{1}{2} \mathrm{~N}_{2}(g)+\frac{3}{2} \mathrm{H}_{2}(g) \longrightarrow \mathrm{NH}_{3}(g) \quad \Delta H^{\circ}=-46 \mathrm{~kJ} $$ calculate \(\Delta H^{\circ}\) (in kilojoules) for the following reaction: $$ 3 \mathrm{Mg}(s)+\mathrm{N}_{2}(g) \longrightarrow \mathrm{Mg}_{3} \mathrm{~N}_{2}(s) $$

A vat of \(4.54 \mathrm{~kg}\) of water underwent a decrease in temperature from \(60.25^{\circ} \mathrm{C}\) to \(58.65^{\circ} \mathrm{C}\). How much energy in kilojoules left the water? (For this range of temperature, use a value of \(4.18 \mathrm{~J} \mathrm{~g}^{-1}{ }^{\circ} \mathrm{C}^{-1}\) for the specific heat of water.

What is meant by the term chemical energy?

Toluene, \(\mathrm{C}_{7} \mathrm{H}_{8}\), is used in the manufacture of explosives such as TNT (trinitrotoluene). A \(1.500 \mathrm{~g}\) sample of liquid toluene was placed in a bomb calorimeter along with excess oxygen. When the combustion of the toluene was initiated, the temperature of the calorimeter rose from \(25.000^{\circ} \mathrm{C}\) to \(26.413^{\circ} \mathrm{C}\). The products of the combustion were \(\mathrm{CO}_{2}(g)\) and \(\mathrm{H}_{2} \mathrm{O}(l),\) and the heat capacity of the calorimeter was \(45.06 \mathrm{~kJ}^{\circ} \mathrm{C}^{-1}\) (a) Write the balanced chemical equation for the reaction in the calorimeter. (b) How many joules were liberated by the reaction? (c) How many joules would be liberated under similar conditions if 1.000 mol of toluene was burned?

Methane burns with oxygen to produce carbon dioxide and water as a gas. The balanced thermochemical equation is $$ \mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g) \atop \Delta H^{\circ}=-802 \mathrm{~kJ} $$ How much methane, in grams, must be burned to release \(432 \mathrm{~kJ}\) of heat?

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