Chapter 18: Problem 121
When an ideal gas expands at a constant temperature, \(\Delta E=0\) for the change. Why?
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Chapter 18: Problem 121
When an ideal gas expands at a constant temperature, \(\Delta E=0\) for the change. Why?
These are the key concepts you need to understand to accurately answer the question.
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Will the entropy change for each of the following be positive or negative? (a) Moisture condenses on the outside of a cold glass. (b) Raindrops form in a cloud. (c) Gasoline vaporizes in the carburetor of an automobile engine. (d) Air is pumped into a tire. (e) Frost forms on the windshield of your car. (f) Sugar dissolves in coffee.
Given the following reactions and their \(\Delta G^{\circ}\) values, \(\mathrm{COCl}_{2}(g)+4 \mathrm{NH}_{3}(g) \longrightarrow\) $$ \begin{aligned} \mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2}(s)+2 \mathrm{NH}_{4} \mathrm{Cl}(s) & \Delta G^{\circ}=-332.0 \mathrm{~kJ} \\ \mathrm{COCl}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{HCl}(g) \\ \Delta G^{\circ}=-141.8 \mathrm{~kJ} \end{aligned} $$ calculate the value of \(\Delta G^{\circ}\) for the reaction $$ \mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{NH}_{3}(g) $$
How can a process have a negative entropy change for the system, and yet still be spontaneous?
An instant cold pack purchased in a pharmacy contains a packet of solid ammonium nitrate surrounded by a pouch of water. When the packet of \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) is broken, the solid dissolves in water and a cooling of the mixture occurs because the solution process for \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) in water is endothermic. Explain, in terms of what happens to the molecules and ions, why this mixing occurs spontaneously.
How is the equilibrium constant related to the standard free energy change for a reaction? (Write the equation.)
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