Chapter 14: Problem 21
State Le Châtelier's principle in your own words.
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Chapter 14: Problem 21
State Le Châtelier's principle in your own words.
These are the key concepts you need to understand to accurately answer the question.
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At \(25^{\circ} \mathrm{C}, K_{\mathrm{c}}=0.145\) for the following reaction in the solvent \(\mathrm{CCl}_{4}\) $$ 2 \mathrm{BrCl} \rightleftharpoons \mathrm{Br}_{2}+\mathrm{Cl}_{2} $$ If the initial concentration of \(\mathrm{BrCl}\) in the solution is \(0.050 M,\) what will the equilibrium concentrations of \(\mathrm{Br}_{2}\) and \(\mathrm{Cl}_{2}\) be?
The reaction $$ \mathrm{CO}(g)+2 \mathrm{H}_{2}(g) \rightleftharpoons \mathrm{CH}_{3} \mathrm{OH}(g) $$ has \(\Delta H^{\circ}=-18 \mathrm{~kJ} .\) How will the amount of \(\mathrm{CH}_{3} \mathrm{OH}\) present at equilibrium be affected by the following changes? (a) Adding \(\mathrm{CO}(g)\) (b) Removing \(\mathrm{H}_{2}(g)\) (c) Decreasing the volume of the container (d) Adding a catalyst (e) Increasing the temperature
A 0.050 mol sample of formaldehyde vapor, \(\mathrm{CH}_{2} \mathrm{O}\), was placed in a heated \(500 \mathrm{~mL}\) vessel and some of it decomposed. The reaction is $$ \mathrm{CH}_{2} \mathrm{O}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{CO}(g) $$ At equilibrium, the \(\mathrm{CH}_{2} \mathrm{O}(g)\) concentration was \(0.066 \mathrm{~mol} \mathrm{~L}^{-1}\). Calculate the value of \(K_{\mathrm{c}}\) for this reaction.
To study the following reaction at \(20^{\circ} \mathrm{C}\), \(\mathrm{NO}(g)+\mathrm{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons 2 \mathrm{HNO}_{2}(g)\) a mixture of \(\mathrm{NO}(g), \mathrm{NO}_{2}(g)\), and \(\mathrm{H}_{2} \mathrm{O}(g)\) was prepared in a \(10.0 \mathrm{~L}\) glass bulb. For \(\mathrm{NO}, \mathrm{NO}_{2},\) and \(\mathrm{HNO}_{2},\) the initial concentrations were as follows: \([\mathrm{NO}]=\left[\mathrm{NO}_{2}\right]=\) \(2.59 \times 10^{-3} M\) and \(\left[\mathrm{HNO}_{2}\right]=0 M .\) The initial partial pressure of \(\mathrm{H}_{2} \mathrm{O}(g)\) was 17.5 torr. When equilibrium was reached, the \(\mathrm{HNO}_{2}\) concentration was \(4.0 \times 10^{-4} \mathrm{M}\) Calculate the equilibrium constant, \(K_{\mathrm{c}},\) for this reaction.
How is the term reaction quotient defined? What symbol is it given?
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