Chapter 14: Problem 11
State in words how \(K_{\mathrm{p}}\) is written.
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Chapter 14: Problem 11
State in words how \(K_{\mathrm{p}}\) is written.
These are the key concepts you need to understand to accurately answer the question.
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When a chemical equation and its equilibrium constant are given, why is it not necessary to also specify the form of the mass action expression?
At \(25^{\circ} \mathrm{C}, K_{\mathrm{c}}=0.145\) for the following reaction in the solvent \(\mathrm{CCl}_{4}\) $$ 2 \mathrm{BrCl} \rightleftharpoons \mathrm{Br}_{2}+\mathrm{Cl}_{2} $$ If the initial concentration of \(\mathrm{BrCl}\) in the solution is \(0.050 M,\) what will the equilibrium concentrations of \(\mathrm{Br}_{2}\) and \(\mathrm{Cl}_{2}\) be?
Consider the following equilibrium. \(2 \mathrm{NaHCO}_{3}(s) \rightleftharpoons \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)\) If you were converting between \(K_{\mathrm{P}}\) and \(K_{\mathrm{c}}\), what value of \(\Delta n_{\mathrm{g}}\) would you use?
At a certain temperature, \(K_{\mathrm{c}}=0.18\) for the equilibrium \(\mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{PCl}_{5}(g)\) Suppose a reaction vessel at this temperature contained these three gases at the following concentrations: \(\left[\mathrm{PCl}_{3}\right]=\) \(0.0420 \mathrm{M},\left[\mathrm{Cl}_{2}\right]=0.0240 \mathrm{M},\left[\mathrm{PCl}_{5}\right]=0.00500 \mathrm{M}\) (a) Compute the reaction quotient and use it to determine whether the system is in a state of equilibrium. (b) If the system is not at equilibrium, in which direction will the reaction proceed to get to equilibrium?
Why doesn't a catalyst affect the position of equilibrium in a chemical reaction?
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