/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Silver has a density of \(10.5 \... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Silver has a density of \(10.5 \mathrm{~g} \mathrm{~cm}^{-3}\). Express this as an equivalence between mass and volume for silver. Write two conversion factors that can be formed from this equivalence for use in calculations.

Short Answer

Expert verified
The equivalence is 1 cm^3 of silver equals 10.5 g. Conversion factors are \(10.5 \mathrm{~g/cm^3}\) for volume to mass and \(1/10.5 \mathrm{~cm^3/g}\) for mass to volume.

Step by step solution

01

Understanding Density

Density is defined as the mass of a substance divided by its volume. It is expressed as a ratio where the numerator is mass and the denominator is volume. For silver, the density is given as \(10.5 \mathrm{~g/cm^3}\).
02

Writing the Equivalence

Since density is mass per unit volume, the equivalence can be written as: '1 cm^3 of silver has a mass of 10.5 g'. This directly states the relationship between the mass of silver and its volume. The equivalence is formed by setting the density equal to the mass divided by the volume.
03

Formulating Conversion Factors

Using the equivalence, two conversion factors can be formed. For conversion from volume to mass: \(10.5 \mathrm{~g/cm^3}\) (1 cm^3 of silver is equivalent to 10.5 g of silver). For conversion from mass to volume: \(1/10.5 \mathrm{~cm^3/g}\) (1 g of silver is equivalent to \(1/10.5\) cm^3 of silver).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density Calculations
Density is a fundamental concept in physical sciences that relates the mass of a substance to its volume. In essence, it answers the question: 'How much mass is packed into a given volume?' Understanding this concept is crucial for a range of applications, from designing ships to measuring the purity of precious metals like silver.

To calculate density, you take the mass (usually in grams) and divide it by the volume (commonly in cubic centimeters). Mathematically, it's expressed as the formula: \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \). In the case of silver, its density is given to be \(10.5 \text{ g/cm}^3\), which is a relatively high density indicative of its status as a precious metal. Knowing how to compute and interpret density paves the way for more advanced concepts like buoyancy, and is also essential in stoichiometry problems in chemistry where mass-to-volume conversions are necessary.
Mass-Volume Relationship
The relationship between mass and volume is at the very heart of the concept of density. With silver's density at \(10.5 \text{ g/cm}^3\), you can infer that for every cubic centimeter of silver, the mass is 10.5 grams. This direct proportionality forms the basis for many mathematical models and solutions in chemistry and physics.

Having a clear understanding of this relationship allows students to solve practical problems. For example, if a jeweler needs to know the mass of a piece of silver jewelry, they can simply calculate the volume of the piece and use the density to find the mass. Conversely, knowing the mass, they could determine the volume.

This interplay between mass and volume also factors into chemical equations and reactions where precise measurements are critical for accuracy. Therefore, a solid grasp of how mass and volume correlate is indispensable for both theoretical understanding and practical problem-solving.
Chemistry Problem Solving
Problem-solving in chemistry often involves navigating complex relationships between variables, and it requires a systematic approach to dissect problems into manageable parts. In the context of the mass-volume relationship, the density of a substance can serve as a bridge that links these two variables. By forming an equivalence as demonstrated with silver, you can extrapolate either value when provided with the other.

For instance, if you know the mass of silver and need to find the volume, you utilize the formula derived from the given density. Just as in the equation \( \text{Volume} = \frac{\text{Mass}}{\text{Density}} \). This process underscores the importance of understanding the underlying principles that govern chemical behavior and properties.

Moreover, adopting units consistent with the extensive use in chemistry, such as grams for mass and cubic centimeters for volume, simplifies the calculations and avoids potential errors due to unit conversion. Emphasizing unit analysis and thoughtfully arranging variables maintains accuracy and fosters proficient problem-solving skills in chemistry.
Conversion Factors in Chemistry
Conversion factors are essential tools in chemistry that assist with the translation of one unit of measure to another. When dealing with densities and the mass-volume relationship, these factors enable the seamless interpolation between mass and volume. Based on the silver density example, the two most straightforward conversion factors would be \(10.5 \text{ g/cm}^3\) and its reciprocal \(1/10.5 \text{ cm}^3/g\).

These allow for swift conversions in calculations without needing to perform complex algebra each time. For practical problem-solving, having this sort of 'shorthand' can streamline the process and minimize error. When moving between mass and volume, it's recommended to write out the conversion factors explicitly at the start of a problem. This clarifies the pathway of the calculation and serves as a double-check to ensure the accuracy of dimensional analysis.

By consistently practicing with conversion factors, students can develop a strong intuitive sense of how to convert units across various chemical contexts, enhancing both their efficiency and effectiveness in tackling chemistry problems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Perform the following arithmetic and round off the answers to the correct number of significant figures. Include the correct units with the answers. (a) \(3.58 \mathrm{~g} / 1.739 \mathrm{~mL}\) (b) \(4.02 \mathrm{~mL}+0.001 \mathrm{~mL}\) (c) \((22.4 \mathrm{~g}-8.3 \mathrm{~g}) /(1.142 \mathrm{~mL}-0.002 \mathrm{~mL})\) (d) \((1.345 \mathrm{~g}+0.022 \mathrm{~g}) /(13.36 \mathrm{~mL}-8.4115 \mathrm{~mL})\) (e) \((74.335 \mathrm{~m}-74.332 \mathrm{~m}) /(4.75 \mathrm{~s} \times 1.114 \mathrm{~s})\)

Give four sets of units for density. What mathematical operation must be carried out to convert the density into specific gravity for these four sets of units?

Natural gas is mostly methane, a substance that boils at a temperature of \(109 \mathrm{~K}\). What is its boiling point in \({ }^{\circ} \mathrm{C}\) and \({ }^{\circ} \mathrm{F}\) ?

An astronomy web site states that neutron stars have a density of \(1.00 \times 10^{8}\) tons per cubic centimeter. The site does not specify whether "tons" means metric tons (1 metric ton \(=1000 \mathrm{~kg}\) ) or English tons ( 1 English ton \(=2000\) pounds). How many grams would one teaspoon of a neutron star weigh if the density were in metric tons per \(\mathrm{cm}^{3}\) ? How many grams would the teaspoon weigh if the density were in English tons per \(\mathrm{cm}^{3}\) ? (One teaspoon is defined as \(5.00 \mathrm{~mL} .\) )

Because of the serious consequences of lead poisoning, the Federal Centers for Disease Control in Atlanta has set a threshold of concern for lead levels in children's blood. This threshold was based on a study that suggested that lead levels in blood as low as 10 micrograms of lead per deciliter of blood can result in subtle effects of lead toxicity. Suppose a child had a lead level in her blood of \(2.5 \times 10^{-4}\) grams of lead per liter of blood. Is this person in danger of exhibiting the effects of lead poisoning?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.