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Give the electron-domain and molecular geometries of a molecule that has the following electron domains on its central atom: (a) four bonding domains and no nonbonding domains, (b) three bonding domains and two nonbonding domains, (c) five bonding domains and one nonbonding domain, (d) four bonding domains and two nonbonding domains.

Short Answer

Expert verified
(a) Electron-domain geometry: tetrahedral, Molecular geometry: tetrahedral (e.g. CH4) (b) Electron-domain geometry: trigonal bipyramidal, Molecular geometry: T-shaped (e.g. ClF3) (c) Electron-domain geometry: octahedral, Molecular geometry: square pyramidal (e.g. SF6) (d) Electron-domain geometry: octahedral, Molecular geometry: square planar (e.g. XeF4)

Step by step solution

01

(a) Four bonding domains and no nonbonding domains

With four bonding domains and no nonbonding domains, the electron-domain geometry is tetrahedral, as all electron pairs are equally distributed around the central atom. Since all the electrons are involved in bonding, the molecular geometry is also tetrahedral. An example of a molecule with this configuration would be methane (CH4).
02

(b) Three bonding domains and two nonbonding domains

With three bonding domains and two nonbonding domains, the electron-domain geometry is trigonal bipyramidal. In this case, due to the presence of two nonbonding domains, the molecular geometry will be T-shaped. An example of a molecule with this configuration would be chlorine trifluoride (ClF3).
03

(c) Five bonding domains and one nonbonding domain

With five bonding domains and one nonbonding domain, the electron-domain geometry is octahedral. The molecular geometry will be square pyramidal, as only five electron domains are involved in bonding. An example of a molecule with this configuration would be sulfur hexafluoride (SF6).
04

(d) Four bonding domains and two nonbonding domains

With four bonding domains and two nonbonding domains, the electron-domain geometry is octahedral. However, due to the presence of two nonbonding domains, the molecular geometry will be square planar. An example of a molecule with this configuration would be xenon hexafluoride (XeF4).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron-Domain Geometry
Electron-domain geometry is a way to describe the arrangement of electron pairs around a central atom in a molecule. This includes both bonding and nonbonding electrons, also known as electron domains. It essentially provides a view of the electron landscape around a central atom and is crucial in determining the overall shape of the molecule.

Different electron-domain geometries arise depending on the number of these electron pairs. For example, two electron domains will arrange themselves linearly, three will form a trigonal planar shape, while four will create a tetrahedral geometry. As you increase the number of electron domains, the geometrical arrangement changes to accommodate these additional electron pairs. Knowing the electron-domain geometry helps predict the molecular geometry, as it gives insights into how the electrons will influence the positioning of the atoms.
Bonding Domains
Bonding domains refer to regions in a molecule where electron pairs are shared between atoms, leading to the formation of chemical bonds. These domains are critical as they define how atoms are connected within a molecule, contributing to its stability and reactivity.

The number of bonding domains around a central atom influences the electron-domain geometry. For instance, methane ( ext{CH}_4) has four bonding domains with no nonbonding domains, resulting in a tetrahedral shape. In such cases, all electron domains are used for forming bonds, affecting both electron-domain and molecular geometry. Understanding bonding domains is essential for predicting molecular geometry and thereby determining the molecule's physical properties and chemical behavior.
Nonbonding Domains
Nonbonding domains, often called lone pairs, are pairs of valence electrons that are not involved in bonding but still occupy space around the central atom. These domains influence the shape of a molecule, even though they do not contribute directly to bonding.

Nonbonding domains repel bonding domains, causing changes in molecular geometry. For example, in water ( ext{H}_2 ext{O}), two of the four electron domains are nonbonding, leading to a bent molecular shape despite its tetrahedral electron-domain geometry. These nonbonding electrons can also lead to asymmetrical charge distribution within the molecule, which can affect polarity and intermolecular interactions.
Tetrahedral
The tetrahedral electron-domain geometry occurs when a central atom is surrounded by four electron domains. This shape is named for the geometric figure, which resembles a pyramid with a triangular base. In a perfect tetrahedron, the angles between the bonds are approximately 109.5 degrees.

A molecule such as methane ( ext{CH}_4) is an excellent example of tetrahedral geometry, where four hydrogen atoms are equally spaced around a central carbon atom. In this case, as there are no nonbonding domains, the electron-domain and molecular geometries are the same. Tetrahedral geometry is common in organic compounds and is associated with sp^3 hybridization of orbitals.
Trigonal Bipyramidal
A trigonal bipyramidal electron-domain geometry features a central atom surrounded by five electron domains. This configuration results from three domains forming an equatorial plane with two axial atoms perpendicular to it. The bond angles can be 90 degrees (axial to equatorial) and 120 degrees (equatorial to equatorial).

In phosphorus pentachloride ( ext{PCl}_5), the central phosphorus is surrounded by five chlorine atoms, creating this shape. However, the presence of nonbonding domains can alter the geometry. For example, if some domains are lone pairs, the structure can change to a T-shaped or seesaw geometry, reflecting changes in molecular geometry, while maintaining trigonal bipyramidal electron-domain geometry.
Octahedral
Octahedral electron-domain geometry is seen when a molecule has six electron domains around a central atom. The atoms form a shape resembling an octahedron, where all positions are equivalent and opposite each other. This geometry typically forms 90-degree bond angles between adjacent domains.

An example of octahedral geometry can be seen in sulfur hexafluoride ( ext{SF}_6), where six fluorine atoms surrond the central sulfur atom. If there are nonbonding domains, the geometry can alter. For instance, in xenon hexafluoride ( ext{XeF}_4), two nonbonding domains result in a square planar molecular geometry while the electron-domain geometry remains octahedral. This distinction between domain and molecular geometry is crucial for understanding how nonbonding pairs influence molecular shape.

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Most popular questions from this chapter

Sodium azide is a shock-sensitive compound that releases \(\mathrm{N}_{2}\) upon physical impact. The compound is used in automobile airbags. The azide ion is \(\mathrm{N}_{3}\). (a) Draw the Lewis structure of the azide ion that minimizes formal charge (it does not form a triangle). Is it linear or bent? (b) State the hybridization of the central \(\mathrm{N}\) atom in the azide ion. (c) How many \(\sigma\) bonds and how many \(\pi\) bonds does the central nitrogen atom make in the azide ion?

The \(\mathrm{O}-\mathrm{H}\) bond lengths in the water molecule \(\left(\mathrm{H}_{2} \mathrm{O}\right)\) are \(96 \mathrm{pm}\), and the \(\mathrm{H}-\mathrm{O}-\mathrm{H}\) angle is \(104.5^{\circ} .\) The dipole moment of the water molecule is \(1.85 \mathrm{D}\). (a) In what directions do the bond dipoles of the \(\mathrm{O}-\mathrm{H}\) bonds point? \(\mathrm{In}\) what direction does the dipole moment vector of the water molecule point? (b) Calculate the magnitude of the bond dipole of the \(\mathrm{O}-\mathrm{H}\) bonds. (Note: You will need to use vector addition to do this.) (c) Compare your answer from part (b) to the dipole moments of the hydrogen halides (Table 8.3). Is your answer in accord with the relative electronegativity of oxvgen?

Benzaldehyde, \(\mathrm{C}_{7} \mathrm{H}_{6} \mathrm{O}\), is a fragrant substance responsible for the aroma of almonds. Its Lewis structure is O=Cc1cccc(C=O)c1 (a) What is the hybridization at each of the carbonatoms of the molecule? (b) What is the total number of valence electrons in benzaldehyde? (c) How many of the valence electrons are used to make \(\sigma\) bonds in the molecule? (d) How many valence electrons are used to make \(\pi\) bonds? (e) How many valence electrons remain in nonbonding pairs in the molecule?

Butadiene, \(\mathrm{C}_{4} \mathrm{H}_{6},\) is a planar molecule that has the following carbon-carbon bond lengths: $$ \mathrm{H}_{2} \mathrm{C}=\mathrm{CH}_{134 \mathrm{pm}} \mathrm{CH}=\mathrm{CH}_{2} $$ (a) Predict the bond angles around each of the carbon atoms and sketch the molecule. (b) From left to right, what is the hybridization of each carbon atom in butadiene? (c) The middle \(\mathrm{C}-\mathrm{C}\) bond length in butadiene \((148 \mathrm{pm})\) is a little shorter than the average \(\mathrm{C}-\mathrm{C}\) single bond length (154 pm). Does this imply that the middle \(\mathrm{C}-\mathrm{C}\) bond in butadiene is weaker or stronger than the average \(\mathrm{C}-\mathrm{C}\) single bond? (d) Based on your answer for part (c), discuss what additional aspects of bonding in butadiene might support the shorter middle \(\mathrm{C}-\mathrm{C}\) bond.

The Lewis structure for allene is Make a sketch of the structure of this molecule that is analogous to Figure \(9.25 .\) In addition, answer the following three questions: (a) Is the molecule planar? (b) Does it have a nonzero dipole moment? (c) Would the bonding in allene be described as delocalized? Explain.

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