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(a) Boron trichloride \(\left(\mathrm{BCl}_{3}\right)\) and the carbonate ion \(\left(\mathrm{CO}_{3}^{2-}\right)\) are both described as trigonal. What does this indicate about their bond angles? (b) The \(\mathrm{PCl}_{3}\) molecule is trigonal pyramidal, while \(\mathrm{ICl}_{3}\) is T-shaped. Which of these molecules is flat?

Short Answer

Expert verified
In BCl3 and CO鈧兟测伝, both have trigonal planar molecular geometries, which indicates that their bond angles are equal to 120掳. PCl3 has a trigonal pyramidal geometry, while ICl3 has a T-shaped geometry. Among these, ICl3 is the flat molecule as all atoms lie in the same plane.

Step by step solution

01

Determining Molecular Geometries of BCl3 and CO鈧兟测伝

The central atom in BCl3 is B (boron) and in CO鈧兟测伝 is C (carbon). Using the VSEPR (Valence Shell Electron Pair Repulsion) theory and considering the number of bonding pairs (BP) and lone pairs (LP) on the central atom, we can determine the molecular geometries. BCl3 has 3 bonding pairs (BP) and 0 lone pairs (LP) on the central atom (B). So, the VSEPR notation is AX鈧, which indicates a trigonal planar geometry. CO鈧兟测伝 also has 3 bonding pairs (BP) and 0 lone pairs (LP) on the central atom (C). So, the VSEPR notation is AX鈧, which again indicates a trigonal planar geometry.
02

Determining Bond Angles in BCl3 and CO鈧兟测伝

In both BCl3 and CO鈧兟测伝, the molecular geometries are trigonal planar, which implies that the bond angles will be equal to 120掳.
03

Determining Molecular Geometries of PCl鈧 and ICl鈧

The central atom in PCl3 is P (phosphorus) and in ICl3 is I (iodine). Using the VSEPR theory, we can determine their molecular geometries based on their electron domains. PCl3 has 3 bonding pairs (BP) and 1 lone pair (LP) on the central atom (P), making it an AX鈧僂 system. This gives the molecule a trigonal pyramidal geometry. ICl3 has 3 bonding pairs (BP) and 2 lone pairs (LP) on the central atom (I), making it an AX鈧僂鈧 system. The geometry of this molecule is T-shaped.
04

Identifying the Flat Molecule

Now that we know the molecular geometries of PCl3 (trigonal pyramidal) and ICl3 (T-shaped), we can identify which of these molecules is flat. A flat molecule is one where all the atoms lie in the same plane. The trigonal pyramidal geometry of PCl鈧 is not flat, as the phosphorus atom isn't in the same plane as the chlorine atoms. However, the T-shaped geometry of ICl鈧 is flat, as the iodine atom, the central atom, lies in the same plane with all the chlorine atoms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Geometry
Molecular geometry describes the three-dimensional arrangement of atoms in a molecule. This arrangement is crucial for understanding the molecule's properties and behavior.
For instance, the molecular geometry affects the reactivity, polarity, phase of matter, color, magnetism, biological activity, and more.
One of the methods to determine molecular geometry is the VSEPR (Valence Shell Electron Pair Repulsion) theory.
  • VSEPR theory predicts the shape of molecules based on electron pairs surrounding a central atom.
  • The electron pairs repel each other and place themselves as far apart as possible, resulting in a specific geometric arrangement.
  • The notation AXE is used to describe the geometry, where A is the central atom, X is the number of bonding pairs, and E is the number of lone pairs.
In the case of \(\mathrm{BCl}_3\) and \(\mathrm{CO}_3^{2-}\), both have a trigonal planar molecular geometry.
For \(\mathrm{PCl}_3\) and \(\mathrm{ICl}_3\), applying VSEPR gives a trigonal pyramidal and T-shaped geometry, respectively.
Bond Angles
Bond angles refer to the angle formed between three atoms across at least two bonds in a molecule.
These angles are influenced heavily by the molecule's geometry and the repulsion between electron pairs.
A common theme in VSEPR theory is that molecules will adjust to have bond angles that minimize electron-electron repulsion.
  • In a trigonal planar geometry, like in \(\mathrm{BCl}_3\) and \(\mathrm{CO}_3^{2-}\), the bond angles are typically 120掳.
  • Other molecular geometries will have different bond angles based on their shape. For example, a tetrahedral shape has bond angles of about 109.5掳.
Understanding bond angles allows chemists to predict how molecules will interact with each other and behave in different environments.
They are also a vital component in computational chemistry and molecular modelling.
Trigonal Planar
A trigonal planar shape is a type of molecular geometry where a central atom is bonded to three other atoms, placed equidistantly in a flat, triangular shape.
This geometry is characterized by bond angles of 120掳 due to the equal repulsion between the bonding pairs.
The AX鈧 VSEPR notation indicates a trigonal planar geometry.
  • No lone pairs are on the central atom, which is crucial for maintaining the flat, planar shape.
  • In \(\mathrm{BCl}_3\) and \(\mathrm{CO}_3^{2-}\), the trigonal planar shape plays a significant role in their reactivity and interaction with other molecules.
Trigonal planar molecules are often seen in compounds involving elements that typically form three bonds, such as boron in \(\mathrm{BCl}_3\).
This geometry allows the atoms to be as far apart as possible, minimizing repulsion and stabilizing the molecule.
Trigonal Pyramidal
Trigonal pyramidal molecular geometry is formed when a central atom is bonded to three other atoms and has one lone pair, making it different from a trigonal planar geometry.
The presence of the lone pair affects the angle and spatial arrangement of the bonded atoms.
For the \(\mathrm{PCl}_3\) molecule:
  • The AX鈧僂 VSEPR notation describes the arrangement, where E represents the lone pair.
  • The bond angles are typically less than 109.5掳 due to the lone pair-bond pair repulsion being greater than bond pair-bond pair repulsion.
In trigonal pyramidal geometry, the molecule is not flat as the lone pair pushes the bonded atoms closer, creating a pyramid-like shape.
This affects the molecule's overall polarity and reactivity since the lone pair is often involved in interactions with other molecules.
Understanding why a molecule like \(\mathrm{PCl}_3\) is not flat can explain its distinct chemical properties compared to molecules with a similar layer of bonding but different numbers of lone pairs.

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Most popular questions from this chapter

Name the proper three-dimensional molecular shapes for each of the following molecules or ions, showing lone pairs as needed: \((\mathbf{a}) \mathrm{ClO}_{2}^{-}(\mathbf{b}) \mathrm{SO}_{4}^{2-}(\mathbf{c}) \mathrm{NF}_{3}(\mathbf{d}) \mathrm{CCl}_{2} \mathrm{Br}_{2}(\mathbf{e}) \mathrm{SF}_{4}^{2+}\)

Consider the molecule \(\mathrm{PF}_{4}\) Cl. (a) Draw a Lewis structure for the molecule, and predict its electron-domain geometry. (b) Which would you expect to take up more space, a \(\mathrm{P}-\mathrm{F}\) bond or a \(\mathrm{P}-\mathrm{Cl}\) bond? Explain. (c) Predict the molecular geometry of \(\mathrm{PF}_{4} \mathrm{Cl}\). How did your answer for part (b) influence your answer here in part (c)? (d) Would you expect the molecule to distort from its ideal electron-domain geometry? If so, how would it distort?

Draw the Lewis structure for each of the following molecules or ions, and predict their electron-domain and molecular geometries: (a) \(\mathrm{AsF}_{3}\) (b) \(\mathrm{CH}_{3}^{+},(\mathbf{c}) \mathrm{Br} \mathrm{F}_{3}\) (d) \(\mathrm{ClO}_{3}^{-}\) (e) \(\mathrm{XeF}_{2}\) (f) \(\mathrm{BrO}_{2}^{-}\).

Methyl isocyanate, \(\mathrm{CH}_{3} \mathrm{NCO},\) was made infamous in 1984 when an accidental leakage of this compound from a storage tank in Bhopal, India, resulted in the deaths of about 3800 people and severe and lasting injury to many thousands more. (a) Draw a Lewis structure for methyl isocyanate. (b) Draw a ball-and-stick model of the structure, including estimates of all the bond angles in the compound. (c) Predict all the bond distances in the molecule. (d) Do you predict that the molecule will have a dipole moment? Explain.

The molecule shown here is difluoromethane (CH_2F2), which is used as a refrigerant called R-32. (a) Based on the structure, how many electron domains surround the \(\mathrm{C}\) atom in this molecule? (b) Would the molecule have a nonzero dipole moment? (c) If the molecule is polar, which of the following describes the direction of the overall dipole moment vector in the molecule: (i) from the carbon atom toward a fluorine atom, (ii) from the carbon atom to a point midway between the fluorine atoms, (iii) from the carbon atom to a point midway between the hydrogen atoms, or (iv) from the earbon atom toward a hydrogen atom? [Sections 9.2 and 9.3\(]\)

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