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Write a balanced equation for the reaction that occurs in each of the following cases: (a) Lithium is added to water. (b) Calcium is added to water. (c) Potassium reacts with chlorine gas. (d) Rubidium reacts with oxygen.

Short Answer

Expert verified
(a) 2 Li (s) + 2 Hâ‚‚O (l) -> 2 LiOH (aq) + Hâ‚‚ (g) (b) Ca (s) + 2 Hâ‚‚O (l) -> Ca(OH)â‚‚ (aq) + Hâ‚‚ (g) (c) 2 K (s) + Clâ‚‚ (g) -> 2 KCl (s) (d) 4 Rb (s) + Oâ‚‚ (g) -> 2 Rbâ‚‚O (s)

Step by step solution

01

(a) Lithium is added to water.

Lithium (Li) is an alkali metal, and it reacts with water (Hâ‚‚O) to form lithium hydroxide (LiOH) and hydrogen gas (Hâ‚‚). The balanced equation for this reaction can be obtained by ensuring that the number of H and O atoms is equal on both sides. Thus, the balanced equation is: \( \) 2 Li (s) + 2 Hâ‚‚O (l) -> 2 LiOH (aq) + Hâ‚‚ (g) \( \)
02

(b) Calcium is added to water.

Calcium (Ca) is an alkaline earth metal, and it reacts with water (Hâ‚‚O) to form calcium hydroxide (Ca(OH)â‚‚) and hydrogen gas (Hâ‚‚). To balance this equation, ensure that the number of H and O atoms is equal on both sides. The balanced equation is: \( \) Ca (s) + 2 Hâ‚‚O (l) -> Ca(OH)â‚‚ (aq) + Hâ‚‚ (g) \( \)
03

(c) Potassium reacts with chlorine gas.

Potassium (K) is an alkali metal, and it reacts with chlorine gas (Clâ‚‚) to form potassium chloride (KCl). To balance this equation, ensure that the number of K and Cl atoms is equal on both sides. The balanced equation is: \( \) 2 K (s) + Clâ‚‚ (g) -> 2 KCl (s) \( \)
04

(d) Rubidium reacts with oxygen.

Rubidium (Rb) is an alkali metal, and it reacts with oxygen (Oâ‚‚) to form rubidium oxide (Rbâ‚‚O). To balance this equation, ensure that the number of Rb and O atoms is equal on both sides. The balanced equation is: \( \) 4 Rb (s) + Oâ‚‚ (g) -> 2 Rbâ‚‚O (s) \( \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lithium reaction with water
When lithium, a soft, silvery alkali metal, is introduced to water, an interesting chemical reaction occurs. As part of the alkali metal group, lithium is highly reactive. When it interacts with water, the reaction forms lithium hydroxide and releases hydrogen gas, which can be observed as bubbling on the surface. This type of reaction is exothermic, meaning it releases heat.
The balanced chemical equation for lithium reacting with water is: \[ 2 \text{Li (s)} + 2 \text{H}_2\text{O (l)} \rightarrow 2 \text{LiOH (aq)} + \text{H}_2\text{(g)} \]
This equation shows us:
  • Two lithium atoms react with two water molecules.
  • The products are two molecules of lithium hydroxide and one molecule of hydrogen gas.
Understanding the balanced equation helps ensure the conversation of mass, which is important in all chemical reactions.
Alkali metals reactions
Alkali metals, including lithium, sodium, potassium, rubidium, and cesium, share characteristics of high reactivity and low density. These metals react vigorously, often explosively, with water. Each of these reactions forms a metal hydroxide and hydrogen gas.
A few properties about alkali metals:
  • They are located in Group 1 of the periodic table.
  • They have a single electron in their outermost shell, which they eagerly give up to achieve a stable, noble gas configuration.
  • Their reactivity increases down the group from lithium to cesium.
When balancing these reactions, ensure the number of metal atoms and water molecules are the same on both sides of the equation. These reactions highlight the characteristics of alkali metals as strong reducing agents.
Rubidium oxide formation
Rubidium, another member of the alkali metal family, displays typical reactivity traits when exposed to oxygen. When rubidium comes into contact with oxygen, it forms rubidium oxide. This reaction needs to be controlled because it is highly exothermic, hinting that even a small amount of rubidium can produce a significant release of energy.
The balanced chemical equation is: \[ 4 \text{Rb (s)} + \text{O}_2\text{(g)} \rightarrow 2 \text{Rb}_2\text{O (s)} \]
Key points about the reaction:
  • Four rubidium atoms react with one oxygen molecule.
  • Two units of rubidium oxide are formed.
  • The equation must remain balanced by having the same number of each type of atom on both sides.
This reaction further illustrates rubidium's aggressive reactivity as an alkali metal.
Potassium reaction with chlorine
Potassium, a well-known alkali metal, reacts with chlorine gas to produce potassium chloride, a compound extensively used as a salt substitute. This reaction is vigorous and exothermic, releasing energy in the form of heat and light.
The balanced equation for this reaction states: \[ 2 \text{K (s)} + \text{Cl}_2\text{(g)} \rightarrow 2 \text{KCl (s)} \]
Here are some important notes:
  • Two potassium atoms react with one chlorine molecule.
  • Produces two units of solid potassium chloride.
  • The reaction is balanced to maintain equal numbers of each type of atom.
Understanding these equations helps reveal the simplicity in how alkali metals form compounds with nonmetals, maintaining charge balance as well.

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Most popular questions from this chapter

An element X reacts with \(\mathrm{F}_{2}(g)\) to form the molecular product shown here. (a) Write a balanced equation for this reaction (do not worry about the phases for \(\mathrm{X}\) and the product). (b) Do you think that \(\mathrm{X}\) is a metal or nonmetal? [Section 7.6\(]\)

Arrange the following oxides in order of increasing acidity: \(\mathrm{K}_{2} \mathrm{O}, \mathrm{BaO}, \mathrm{ZnO}, \mathrm{H}_{2} \mathrm{O}, \mathrm{CO}_{2}, \mathrm{SO}_{2}\)

Write equations that show the processes that describe the first, second, and third ionization energies of a chlorine atom. Which process would require the least amount of energy?

Mercury in the environment can exist in oxidation states \(0,\) \(+1,\) and \(+2 .\) One major question in environmental chemistry research is how to best measure the oxidation state of mercury in natural systems; this is made more complicated by the fact that mercury can be reduced or oxidized on surfaces differently than it would be if it were free in solution. XPS, X-ray photoelectron spectroscopy, is a technique related to PES (see Exercise 7.111 ), but instead of using ultraviolet light to eject valence electrons, X rays are used to eject core electrons. The energies of the core electrons are different for different oxidation states of the element. In one set of experiments, researchers examined mercury contamination of minerals in water. They measured the XPS signals that corresponded to electrons ejected from mercury's 4 forbitals at \(105 \mathrm{eV}\), from an X-ray source that provided \(1253.6 \mathrm{eV}\) of energy \(\left(1 \mathrm{ev}=1.602 \times 10^{-19} \mathrm{~J}\right)\) The oxygen on the mineral surface gave emitted electron energies at \(531 \mathrm{eV}\), corresponding to the \(1 s\) orbital of oxygen. Overall the researchers concluded that oxidation states were +2 for \(\mathrm{Hg}\) and -2 for O. (a) Calculate the wavelength of the \(\mathrm{X}\) rays used in this experiment. (b) Compare the energies of the \(4 f\) electrons in mercury and the \(1 s\) electrons in oxygen from these data to the first ionization energies of mercury and oxygen from the data in this chapter. (c) Write out the ground- state electron configurations for \(\mathrm{Hg}^{2+}\) and \(\mathrm{O}^{2-}\); which electrons are the valence electrons in each case?

Consider the first ionization energy of neon and the electron affinity of fluorine. (a) Write equations, including electron configurations, for each process. (b) These two quantities have opposite signs. Which will be positive, and which will be negative? (c) Would you expect the magnitudes of these two quantities to be equal? If not, which one would you expect to be larger?

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