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A hydrogen atom orbital has \(n=4\) and \(m_{l}=-2\). (a) What are the possible values of \(l\) for this orbital? (b) What are the possible values of \(m_{s}\) for the orbital?

Short Answer

Expert verified
(a) The possible values of \(l\) for this orbital are 2 and 3. (b) The possible values of \(m_s\) for the orbital are always +1/2 and -1/2.

Step by step solution

01

(a) Possible values of l

To find the possible values of the angular momentum quantum number l, we need to recall the relationship between n, l and m_l: \(l\) can have integer values from 0 to n-1, and \(m_{l}\) can have integer values ranging from -l to +l. In our case, n = 4, and \(m_{l} = -2\). Since m_l = -2, we know that l must be at least 2, since m_l can only take values from -l to +l. Therefore, we will try each possible value of l = 2, 3, and check if \(m_l = -2\) is a valid option. For l = 2, \(m_l\) can take values -2, -1, 0, 1, 2, which includes \(m_l = -2\). For l = 3, \(m_l\) can take values -3, -2, -1, 0, 1, 2, 3, which also includes \(m_l = -2\). So, the possible values of l for this orbital are 2 and 3.
02

(b) Possible values of m_s

To find the possible values of the spin quantum number \(m_s\), we recall that for an electron in an orbital, there are only two possible spin orientations available: 1. Spin-up (represented as +1/2) 2. Spin-down (represented as -1/2) So, for any electron in an orbital, the possible values of \(m_s\) are always +1/2 and -1/2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Momentum Quantum Number
The angular momentum quantum number, represented by the symbol \(l\), plays a crucial role in quantum mechanics, specifically in the understanding of atomic orbitals. It helps define the shape of an electron's orbital within an atom. The value of \(l\) is directly linked to the principal quantum number \(n\), which determines the electron’s energy level.

In any atom:
  • \(l\) can take any integer value from 0 to \(n-1\).
  • Each value of \(l\) corresponds to a different type of orbital, like \(s, p, d,\) and \(f\).
For example, if \(n = 4\), \(l\) can be 0, 1, 2, or 3. These numbers dictate the shape and complexity of the orbitals: 0 for \(s\), 1 for \(p\), 2 for \(d\), and 3 for \(f\).

In the exercise provided, since \(m_{l}=-2\), the possible \(l\) values that permit \(m_{l} = -2\) are 2 and 3. This is due to the fact that the magnetic quantum number \(m_{l}\) can only be within the range \(-l \leq m_{l} \leq +l\). Therefore, both \(l = 2\) and \(l = 3\) can have \(m_{l} = -2\).
Spin Quantum Number
The spin quantum number, denoted by \(m_{s}\), is essential in understanding the intrinsic "spin" or angular momentum of electrons within an atom. Unlike other quantum numbers which describe electron paths, \(m_{s}\) denotes the orientation of the electron's spin.

The possible values for \(m_{s}\) are unique because:
  • \(m_{s}\) can only take on two possible values: +1/2 or -1/2.
  • These two values represent the two possible orientations of an electron's spin - often referred to as "spin-up" and "spin-down".
In any given orbital, electrons will usually pair with opposite spins, minimizing their mutual repulsion, which is a cornerstone principle of electron configurations.

In the context of the exercise, regardless of other quantum numbers like \(n\), \(l\), or \(m_{l}\), \(m_{s}\) remains limited to these two values. This reflects the fundamental nature of electron spin, a quantum property that is fixed for all electrons.
Magnetic Quantum Number
The magnetic quantum number, symbolized by \(m_{l}\), further refines the understanding of an electron's position within an atom's electron cloud. It gives insight into the orientation of an orbital around the nucleus in space.

The following guidelines determine the possible values of \(m_{l}\):
  • \(m_{l}\) can take on integer values ranging from \(-l\) to \(+l\).
  • It defines the electron’s exact orientation in space within a given orbital type \(l\).
For instance, when \(l = 2\) (a \(d\) orbital), \(m_{l}\) can be -2, -1, 0, 1, or 2, showing five unique spatial orientations. Similarly, for \(l = 3\) (an \(f\) orbital), \(m_{l}\) can range from -3 to +3, offering seven orientations.

In the given exercise scenario, \(m_{l}=-2\) constrains \(l\) to those values that allow this orientation, namely 2 and 3. It provides insight into the possible spatial distribution of the electron within the hydrogen atom, showing how quantum numbers interact to define states of the electron.

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Most popular questions from this chapter

Titanium metal requires light with a maximum wavelength of \(286 \mathrm{nm}\) to emit electrons. (a) What is the minimum energy of the photons necessary to emit electrons from titanium via the photoelectric effect? (b) What is the frequency of this radiation? (c) Is it possible to eject electrons from titanium metal using infrared light? (d) If titanium is irradiated with light of wavelength \(276 \mathrm{nm}\), what is the maximum possible kinetic energy of the emitted electrons?

(a) Calculate the energy of a photon of electromagnetic radiation whose frequency is \(2.94 \times 10^{14} \mathrm{~s}^{-1}\). (b) Calculate the energy of a photon of radiation whose wavelength is 413 \(\mathrm{nm} .\) (c) What wavelength of radiation has photons of energy \(6.06 \times 10^{-19} \mathrm{~J} ?\)

Indicate whether energy is emitted or absorbed when the following electronic transitions occur in hydrogen: (a) from \(n=2\) to \(n=3,(\mathbf{b})\) from an orbit of radius 0.529 to one of radius \(0.476 \mathrm{nm},(\mathbf{c})\) from the \(n=9\) to the \(n=6\) state.

(a) The average distance from the nucleus of a 3 s electron in a chlorine atom is smaller than that for a \(3 p\) electron. In light of this fact, which orbital is higher in energy? (b) Would you expect it to require more or less energy to remove a 3 s electron from the chlorine atom, as compared with a \(2 p\) electron?

A diode laser emits at a wavelength of \(987 \mathrm{nm} .\) (a) In what portion of the electromagnetic spectrum is this radiation found? (b) All of its output energy is absorbed in a detector that measures a total energy of \(0.52 \mathrm{~J}\) over a period of \(32 \mathrm{~s}\). How many photons per second are being emitted by the laser?

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