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Using the periodic table as a guide, write the condensed electron configuration and determine the number of unpaired electrons for the ground state of (a) \(\mathrm{Cl},(\mathbf{b}) \mathrm{Al},(\mathbf{c}) \mathrm{Zr},(\mathbf{d})\) As, (e) \(\mathrm{Sb},(\mathbf{f}) \mathrm{W}\)

Short Answer

Expert verified
The condensed electron configurations and number of unpaired electrons for the given elements are: a) Cl: [Ne] 3s虏 3p鈦, 3 unpaired electrons b) Al: [Ne] 3s虏 3p鹿, 1 unpaired electron c) Zr: [Kr] 5s虏 4d虏, 2 unpaired electrons d) As: [Ar] 4s虏 3d鹿鈦 4p鲁, 3 unpaired electrons e) Sb: [Kr] 5s虏 4d鹿鈦 5p鲁, 3 unpaired electrons f) W: [Xe] 6s虏 4f鹿鈦 5d鈦, 4 unpaired electrons

Step by step solution

01

a) Electron Configuration and Unpaired Electrons for Chlorine (Cl)

Chlorine (Cl) has an atomic number (Z) of 17, so it has 17 electrons in its ground state. Following the order in the periodic table: 1s虏 2s虏 2p鈦 3s虏3p鈦 Condensed Electron Configuration: [Ne] 3s虏 3p鈦 Number of Unpaired Electrons: Since the last subshell (3p) has five electrons, there are three unpaired electrons.
02

b) Electron Configuration and Unpaired Electrons for Aluminum (Al)

Aluminum (Al) has an atomic number (Z) of 13, so it has 13 electrons in its ground state. Following the order in the periodic table: 1s虏 2s虏 2p鈦 3s虏 3p鹿 Condensed Electron Configuration: [Ne] 3s虏 3p鹿 Number of Unpaired Electrons: Since the last subshell (3p) has only one electron, there is one unpaired electron.
03

c) Electron Configuration and Unpaired Electrons for Zirconium (Zr)

Zirconium (Zr) has an atomic number (Z) of 40, so it has 40 electrons in its ground state. Following the order in the periodic table: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d虏 Condensed Electron Configuration: [Kr] 5s虏 4d虏 Number of Unpaired Electrons: Since the last subshell (4d) has two electrons, there are two unpaired electrons.
04

d) Electron Configuration and Unpaired Electrons for Arsenic (As)

Arsenic (As) has an atomic number (Z) of 33, so it has 33 electrons in its ground state. Following the order in the periodic table: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鲁 Condensed Electron Configuration: [Ar] 4s虏 3d鹿鈦 4p鲁 Number of Unpaired Electrons: Since the last subshell (4p) has three electrons, there are three unpaired electrons.
05

e) Electron Configuration and Unpaired Electrons for Antimony (Sb)

Antimony (Sb) has an atomic number (Z) of 51, so it has 51 electrons in its ground state. Following the order in the periodic table: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鲁 Condensed Electron Configuration: [Kr] 5s虏 4d鹿鈦 5p鲁 Number of Unpaired Electrons: Since the last subshell (5p) has three electrons, there are three unpaired electrons.
06

f) Electron Configuration and Unpaired Electrons for Tungsten (W)

Tungsten (W) has an atomic number (Z) of 74, so it has 74 electrons in its ground state. Following the order in the periodic table: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 4f鹿鈦 5d鈦 Condensed Electron Configuration: [Xe] 6s虏 4f鹿鈦 5d鈦 Number of Unpaired Electrons: Since the last subshell (5d) has four electrons, there are four unpaired electrons.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Periodic Table
The periodic table is a chart that organizes elements by increasing atomic number and similar chemical properties. It serves as a guide in determining the electron configuration of elements. By placing elements in order, we can see the filling order of electrons in their atomic orbitals.

Each row, or period, represents the filling of a set of orbitals. For example, elements in the second period fill the 2s and 2p orbitals. This orderly pattern allows us to predict and write electron configurations for elements.

Using the periodic table, we can determine the electronic arrangement of elements efficiently and predict their chemical behavior. Recognizing groups, like the noble gases or transition metals, helps in predicting specific properties and behaviors.
Ground State
The ground state of an atom is its lowest energy state where all the electrons are in their lowest possible energy levels. Think of it as the perfectly relaxed state of the atom, where no extra energy is used to excite electrons to a higher level.

The determination of an atom's ground state configuration is critical since it's the most stable and common form found in nature. In chemistry, knowing the ground state helps us understand how an element will interact in chemical reactions.

By using the atom's atomic number, which tells us how many electrons it has, we can distribute these electrons into orbitals following specific rules (like the Aufbau principle), ensuring they are in positions of least energy.
Unpaired Electrons
Unpaired electrons are single electrons present in an atomic orbital that are not paired with another electron with an opposite spin. Recognizing unpaired electrons is important because they contribute greatly to the magnetic properties and reactivity of an element.

Elements like chlorine, with the electron configuration [Ne] 3s虏 3p鈦, have unpaired electrons in their outer orbitals.
  • The presence of unpaired electrons often leads to paramagnetism, where elements are attracted to magnetic fields.
  • As such, unpaired electrons are also clues to predict how elements will interact or bond with others.
Knowing the number of unpaired electrons allows chemists to predict the type and strength of chemical bonds that an element might form.
Condensed Electron Configuration
Condensed electron configuration is a shorthand method of writing the electron configuration of an element. It uses the nearest noble gas that precedes the element in the periodic table to represent filled electron shells.

Take aluminum (Al) for example, with the electron configuration 1s虏 2s虏 2p鈦 3s虏 3p鹿. Its condensed form is [Ne] 3s虏 3p鹿 by using neon ([Ne]) to represent the completed electron shells up to 2p.
  • This method simplifies the electron configuration, making it easier to identify valence electrons.
  • Condensed configurations highlight the outermost electrons directly involved in chemical reactions.
Using the condensed configuration is not only efficient but also provides clarity when studying complex elements. It directly reflects the element's reactivity and interactions with other atoms.

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Most popular questions from this chapter

Molybdenum metal must absorb radiation with an energy higher than \(7.22 \times 10^{-19} \mathrm{~J}\) ( "energy threshold") before it can eject an electron from its surface via the photoelectric effect. (a) What is the frequency threshold for emission of electrons? (b) What wavelength of radiation will provide a photon of this energy? (c) If molybdenum is irradiated with light of wavelength of \(240 \mathrm{nm}\), what is the maximum possible velocity of the emitted electrons?

(a) What is the frequency of radiation whose wavelength is \(0.86 \mathrm{nm} ?(\mathbf{b})\) What is the wavelength of radiation that has a frequency of \(6.4 \times 10^{11} \mathrm{~s}^{-1} ?(\mathbf{c})\) Would the radiations in part (a) or part (b) be detected by an X-ray detector? (d) What distance does electromagnetic radiation travel in 0.38 ps?

The discovery of hafnium, element number \(72,\) provided a controversial episode in chemistry. G. Urbain, a French chemist, claimed in 1911 to have isolated an element number 72 from a sample of rare earth (elements \(58-71\) ) compounds. However, Niels Bohr believed that hafnium was more likely to be found along with zirconium than with the rare earths. D. Coster and G. von Hevesy, working in Bohr's laboratory in Copenhagen, showed in 1922 that element 72 was present in a sample of Norwegian zircon, an ore of zirconium. (The name hafnium comes from the Latin name for Copenhagen, Hafnia). (a) How would you use electron configuration arguments to justify Bohr's prediction? (b) Zirconium, hafnium's neighbor in group \(4 \mathrm{~B}\), can be produced as a metal by reduction of solid \(\mathrm{ZrCl}_{4}\) with molten sodium metal. Write a balanced chemical equation for the reaction. Is this an oxidation- reduction reaction? If yes, what is reduced and what is oxidized? (c) Solid zirconium dioxide, \(\mathrm{ZrO}_{2}\), reacts with chlorine gas in the presence of carbon. The products of the reaction are \(\mathrm{ZrCl}_{4}\) and two gases, \(\mathrm{CO}_{2}\) and \(\mathrm{CO}\) in the ratio \(1: 2 .\) Write a balanced chemical equation for the reaction. Starting with a \(55.4-\mathrm{g}\) sample of \(\mathrm{ZrO}_{2}\), calculate the mass of \(\mathrm{ZrCl}_{4}\) formed, assuming that \(\mathrm{ZrO}_{2}\) is the limiting reagent and assuming \(100 \%\) yield. (d) Using their electron configurations, account for the fact that \(\mathrm{Zr}\) and Hf form chlorides \(\mathrm{MCl}_{4}\) and oxides \(\mathrm{MO}_{2}\).

(a) What are the similarities of and differences between the \(1 s\) and \(2 s\) orbitals of the hydrogen atom? (b) In what sense does a \(2 p\) orbital have directional character? Compare the "directional" characteristics of the \(p_{x}\) and \(d_{x^{2}-y^{2}}\) orbitals. (That is, in what direction or region of space is the electron density concentrated?) (c) What can you say about the average distance from the nucleus of an electron in a \(2 s\) orbital as compared with a 3 s orbital? ( \(\mathbf{d}\) ) For the hydrogen atom, list the following orbitals in order of increasing energy (that is, most stable ones first): \(4 f, 6 s, 3 d, 1 s, 2 p\)

Is energy emitted or absorbed when the following electronic transitions occur in hydrogen? (a) from \(n=3\) to \(n=2\), (b) from an orbit of radius \(0.846 \mathrm{nm}\) to one of radius 0.212 \(\mathrm{nm},(\mathbf{c})\) an electron adds to the \(\mathrm{H}^{+}\) ion and ends up in the \(n=2\) shell?

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