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(a) When a compound containing C, H, and O is completely combusted in air, what reactant besides the hydrocarbon is involved in the reaction? (b) What products form in this reaction? (c) What is the sum of the coefficients in the balanced chemical equation for the combustion of one mole of acetone, \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l),\) in air?

Short Answer

Expert verified
(a) The other reactant involved in the combustion reaction is oxygen gas, O2. (b) The products formed in the reaction are carbon dioxide (CO2) and water (H2O). (c) The sum of the coefficients in the balanced chemical equation for the combustion of one mole of acetone is 11. The balanced equation is: \( C_{3}H_{6}O(l) + 4O_{2}(g) \rightarrow 3CO_{2}(g) + 3H_{2}O(l) \).

Step by step solution

01

(a) Identifying the other reactant in the combustion reaction

In a combustion reaction, when a compound containing C, H, and O is combusted, the other reactant is oxygen gas, O2.
02

(b) Identifying the products in the combustion reaction

In a complete combustion reaction involving a hydrocarbon (compound containing only C and H) or a compound containing C, H, and O, the products formed are carbon dioxide (CO2) and water (H2O).
03

(c) Balancing the equation for the combustion of one mole of acetone

To balance the equation for the combustion of one mole of acetone (C3H6O), we need to balance the number of atoms of each element on both sides of the reaction. The unbalanced equation is: C3H6O(l) + O2(g) → CO2(g) + H2O(l) 1. Balance the Carbon atoms: C3H6O(l) + O2(g) → 3CO2(g) + H2O(l) 2. Balance the Hydrogen atoms: C3H6O(l) + O2(g) → 3CO2(g) + 3H2O(l) 3. Balance the Oxygen atoms: C3H6O(l) + 4O2(g) → 3CO2(g) + 3H2O(l) Now, the balanced chemical equation for the combustion of one mole of acetone is: C3H6O(l) + 4O2(g) → 3CO2(g) + 3H2O(l)
04

Calculate the sum of the coefficients in the balanced equation

The balanced chemical equation is C3H6O(l) + 4O2(g) → 3CO2(g) + 3H2O(l). Therefore, the sum of the coefficients in this balanced equation is 1 (acetone) + 4 (oxygen) + 3 (carbon dioxide) + 3 (water) = 11.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

chemical equation balancing
Balancing a chemical equation is like solving a puzzle. The goal is to have the same number of each type of atom on both sides of the equation. This ensures the law of conservation of mass is satisfied, meaning that mass is neither created nor destroyed in a chemical reaction. For example, in the combustion of acetone, represented by the chemical formula \( \text{C}_3\text{H}_6\text{O} \), we start with an unbalanced equation:
\[ \text{C}_3\text{H}_6\text{O}(l) + \text{O}_2(g) \rightarrow \text{CO}_2(g) + \text{H}_2\text{O}(l) \]
To balance it:
  • Start with carbon: Acetone has 3 carbon atoms, so we need 3 \( \text{CO}_2 \) molecules.
  • Next, balance hydrogen: There are 6 hydrogen atoms in acetone, requiring 3 \( \text{H}_2\text{O} \) molecules.
  • Finally, balance oxygen: Check the number of oxygen atoms needed, which ends up requiring 4 \( \text{O}_2 \) molecules.
Thus, the balanced equation for the combustion of acetone is:\[\text{C}_3\text{H}_6\text{O}(l) + 4\text{O}_2(g) \rightarrow 3\text{CO}_2(g) + 3\text{H}_2\text{O}(l)\]
acetone combustion
Acetone, commonly known as nail polish remover, undergoes combustion, a process that involves burning in the presence of oxygen. This reaction is an example of a chemical reaction where energy is released, usually in the form of heat and light. Combustion of organic compounds like acetone, which contain carbon, hydrogen, and oxygen, typically results in the formation of carbon dioxide and water.
In practical terms, acetone combusts according to the equation:
\[\text{C}_3\text{H}_6\text{O}(l) + 4\text{O}_2(g) \rightarrow 3\text{CO}_2(g) + 3\text{H}_2\text{O}(l)\]
This reaction illustrates complete combustion, meaning acetone is fully converted into \( \text{CO}_2 \) and \( \text{H}_2\text{O} \) without any leftover acetone. It's important to have enough oxygen to ensure complete combustion, preventing the formation of carbon monoxide or other byproducts.
oxygen as reactant
Oxygen is a critical reactant in combustion reactions. It pairs with hydrocarbons, substances made of hydrogen and carbon, or compounds containing carbon, hydrogen, and oxygen to sustain the reaction. Without sufficient oxygen, combustion cannot occur. This is why oxygen is always involved in burning processes, such as the combustion of acetone.
In the combustion of acetone, \( \text{O}_2 \) molecules are needed to break the bonds in the acetone molecule and rearrange its atoms to form new compounds:
  • The chemical equation shows that 4 molecules of \( \text{O}_2 \) are necessary to react with 1 molecule of acetone.
  • The presence of oxygen ensures carbon is converted into carbon dioxide and hydrogen into water, completing the reaction.
Without enough oxygen, incomplete combustion might occur, leading to lower energy output and the potential production of harmful substances like carbon monoxide.
combustion products
The combustion products of any hydrocarbon or oxygen-containing hydrocarbon like acetone are primarily carbon dioxide and water. These products result from the chemical transformation that occurs during combustion. Each carbon atom in the fuel combines with oxygen to form \( \text{CO}_2 \), while each pair of hydrogen atoms combines with oxygen to form \( \text{H}_2\text{O} \).
In the case of acetone, the balanced chemical reaction tells us:
  • 3 molecules of \( \text{CO}_2 \) are produced from the 3 carbon atoms in acetone.
  • 3 molecules of \( \text{H}_2\text{O} \) result from the 6 hydrogen atoms.
This conversion is efficient and maximizes energy release, which is why \( \text{CO}_2 \) and \( \text{H}_2\text{O} \) are the hallmark products of any complete combustion process.

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Most popular questions from this chapter

(a) What is the mass, in grams, of \(2.50 \times 10^{-3} \mathrm{~mol}\) of ammonium phosphate? (b) How many moles of chloride ions are in \(0.2550 \mathrm{~g}\) of aluminum chloride? (c) What is the mass, in grams, of \(7.70 \times 10^{20}\) molecules of caffeine, \(\mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2} ?\) (d) What is the molar mass of cholesterol if \(0.00105 \mathrm{~mol}\) has a mass of \(0.406 \mathrm{~g}\) ?

Write balanced chemical equations to correspond to each of the following descriptions: (a) When sulfur trioxide gas reacts with water, a solution of sulfuric acid forms. (b) Boron sulfide, \(\mathrm{B}_{2} \mathrm{~S}_{3}(s),\) reacts violently with water to form dissolved boric acid, \(\mathrm{H}_{3} \mathrm{BO}_{3},\) and hydrogen sulfide gas. (c) Phosphine, \(\mathrm{PH}_{3}(g)\), combusts in oxygen gas to form water vapor and solid tetraphosphorus decaoxide. (d) When solid mercury(II) nitrate is heated, it decomposes to form solid mercury(II) oxide, gaseous nitrogen dioxide, and oxygen. (e) Copper metal reacts with hot concentrated sulfuric acid solution to form aqueous copper(II) sulfate, sulfur dioxide gas, and water.

(a) Define the terms limiting reactant and excess reactant. (b) Why are the amounts of products formed in a reaction determined only by the amount of the limiting reactant? (c) Why should you base your choice of which compound is the limiting reactant on its number of initial moles, not on its initial mass in grams?

A piece of aluminum foil \(1.00 \mathrm{~cm}^{2}\) and \(0.550-\mathrm{mm}\) thick is allowed to react with bromine to form aluminum bromide. (a) How many moles of aluminum were used? (The density of aluminum is \(2.699 \mathrm{~g} / \mathrm{cm}^{3} .\) ) (b) How many grams of aluminum bromide form, assuming the aluminum reacts completely?

Boron nitride, \(\mathrm{BN}\), is an electrical insulator with remarkable thermal and chemical stability. Its density is \(2.1 \mathrm{~g} / \mathrm{cm}^{3}\). It can be made by reacting boric acid, \(\mathrm{H}_{3} \mathrm{BO}_{3}\), with ammonia. The other product of the reaction is water. (a) Write a balanced chemical equation for the synthesis of BN. (b) If you made \(225 \mathrm{~g}\) of boric acid react with \(150 \mathrm{~g}\) ammonia, what mass of BN could you make? (c) Which reactant, if any, would be left over, and how many moles of leftover reactant would remain? (d) One application of \(\mathrm{BN}\) is as thin film for electrical insulation. If you take the mass of BN from part (a) and make a \(0.4 \mathrm{~mm}\) thin film from it, what area, in \(\mathrm{cm}^{2}\), would it cover?

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