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Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) triamminetriaquachromium(III) nitrate (b) dichlorobis(ethylenediamine)platinum(II) (c) pentacarbonyliron(0) (d) ammonium diaquabis(oxalato)Co(II) (e) tris(bipyridyl)cobalt(III) sulfate

Short Answer

Expert verified
The formulas for the given compounds are: (a) \([Cr(NH鈧)鈧(H鈧侽)鈧僝(NO鈧)鈧僜) (b) \([PtCl鈧(en)鈧俔虏+\) (c) \([Fe(CO)鈧匽鈧\) (d) \((NH鈧)鈧俒Co(H鈧侽)鈧(C鈧侽鈧)鈧俔\) (e) \([Co(bipy)鈧僝鈧(SO鈧)鈧僜)

Step by step solution

01

Identify the central metal ion, ligands, and counter-ion

The central metal ion is chromium(III) (Cr鲁+), the ligands are three ammine groups (NH鈧) and three aqua groups (H鈧侽), and the counter-ion is nitrate (NO鈧冣伝).
02

Write the formula for the complex

Since there are multiple ligands, we need to indicate the coordination sphere using brackets. The formula for this complex is [Cr(NH鈧)鈧(H鈧侽)鈧僝鲁+.
03

Write the formula including the counter-ion

Since the complex has a 3+ charge, and the counter-ion (NO鈧冣伝) has a -1 charge, we need three nitrate ions to balance the overall charge. The formula is [Cr(NH鈧)鈧(H鈧侽)鈧僝(NO鈧)鈧. (b) dichlorobis(ethylenediamine)platinum(II)
04

Identify the central metal ion, ligands, and counter-ion

The central metal ion is platinum(II) (Pt虏+), the ligands are two chloro groups (Cl鈦) and two ethylenediamine molecules with the abbreviated name of en (C鈧侶鈧(NH鈧)鈧), and there is no counter-ion indicated.
05

Write the formula for the complex

The formula for this complex is [PtCl鈧(en)鈧俔虏+. (c) pentacarbonyliron(0)
06

Identify the central metal ion and ligands

The central metal ion is iron(0), and the ligands are five carbonyl groups (CO).
07

Write the formula for the complex

The formula for this complex is [Fe(CO)鈧匽鈧. (d) ammonium diaquabis(oxalato)Co(II)
08

Identify the central metal ion, ligands, and counter-ion

The central metal ion is cobalt(II) (Co虏+), the ligands are two aqua groups (H鈧侽) and two oxalato groups (C鈧侽鈧劼测伝), and the counter-ion is ammonium (NH鈧勨伜).
09

Write the formula for the complex

The formula for this complex is [Co(H鈧侽)鈧(C鈧侽鈧)鈧俔虏-.
10

Write the formula including the counter-ion

Since the complex has a 2- charge, and the counter-ion (NH鈧勨伜) has a +1 charge, we need two ammonium ions to balance the overall charge. The formula is (NH鈧)鈧俒Co(H鈧侽)鈧(C鈧侽鈧)鈧俔. (e) tris(bipyridyl)cobalt(III) sulfate
11

Identify the central metal ion, ligands, and counter-ion

The central metal ion is cobalt(III) (Co鲁+), the ligands are three bipyridyl molecules with the abbreviated name of bipy (C鈧佲個H鈧圢鈧), and the counter-ion is sulfate (SO鈧劼测伝).
12

Write the formula for the complex

The formula for this complex is [Co(bipy)鈧僝鲁+.
13

Write the formula including the counter-ion

Since the complex has a 3+ charge, and the counter-ion (SO鈧劼测伝) has a -2 charge, we need two cobalt complexes and three sulfate ions to balance the overall charge. The formula is [Co(bipy)鈧僝鈧(SO鈧)鈧.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Ions
Complex ions are the heart of coordination chemistry. They consist of a central metal atom or ion and are surrounded by molecules or ions known as ligands. This central metal atom is at the core of the structure, forming multiple bonds with the ligands.

The metal ion, often found in transition elements, displays high electronegativity and can exhibit variable oxidation states. This allows them to form stable complexes with ligands through coordinate covalent bonds. These complexes are often enclosed by brackets to indicate the coordination sphere. This is crucial when writing their chemical formulas.
  • Example: In the complex [Cr(NH鈧)鈧(H鈧侽)鈧僝鲁+, chromium (Cr) is the central metal ion.
  • The formula's brackets indicate that within lies the whole coordination sphere.
Overall charge balance is achieved when metal ions form complex ions, sometimes attracting counter-ions that balance out their charge.
Ligands
Ligands are ions or molecules that bind to the central metal ion in a complex. They are integral in determining the properties and reactivity of the complex ion.

Ligands can be classified based on the number of binding sites or donor atoms:
  • Monodentate Ligands: These ligands have a single donor atom that binds to the metal ion, like chloride (Cl鈦) or ammonia (NH鈧).
  • Bidentate Ligands: These ligands bind through two donor atoms, creating a more stable chelate formation. Examples include ethylenediamine (en) and oxalate (C鈧侽鈧劼测伝).
Ligands affect the color, magnetic properties, and stability of the complex. For instance, in the compound [Co(bipy)鈧僝鲁+, bipyridyl acts as a ligand creating a stable octahedral structure around cobalt.

Understanding ligands and their interactions with metal ions is essential in predicting the behavior and application of coordination compounds.
Metal Ions
At the center of complex ions, metal ions serve as the primary bonding site for ligands. These are generally transition metals due to their ability to form various oxidation states and stable complex geometries.

The metal ion contributes significantly to the properties of the coordination compound. It dictates:
  • The number of ligands the complex can accommodate, also called the coordination number.
  • The oxidation state of the metal, impacting the overall charge.
For example, chromium in [Cr(NH鈧)鈧(H鈧侽)鈧僝鲁+ exerts a 3+ oxidation state. Likewise, cobalt in [Co(bipy)鈧僝鲁+ has to accommodate the 3+ charge, affecting how the complex interacts with counter-ions to maintain charge neutrality.

Metal ions are crucial in fields ranging from industrial catalysts to biological systems, where they are key in enzymes and active sites of proteins.
Counter Ions
Counter ions are essential in maintaining charge balance in coordination compounds. While they are not part of the coordination sphere, their role in charge neutrality cannot be overlooked.

In many complexes, counter ions are required to balance out the charge derived from the metal ions and the ligands in the coordination sphere:
  • In [Cr(NH鈧)鈧(H鈧侽)鈧僝(NO鈧)鈧, nitrate ions (NO鈧冣伝) serve as counter ions for the 3+ charge from the chromium complex.
  • In (NH鈧)鈧俒Co(H鈧侽)鈧(C鈧侽鈧)鈧俔, ammonium ions (NH鈧勨伜) neutralize the 2- charge from the cobalt complex.
Counter ions are important not only for maintaining the compound's stability but also for ensuring the crystal structure when the complex solidifies.

They significantly influence solubility and conductivity of the compounds in solutions, making them key to understanding the physical attributes of coordination compounds.

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Most popular questions from this chapter

Consider the following three complexes: \(\left(\right.\) Complex 1) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SCN}\right]^{2+}\) \(\left(\right.\) Complex 2) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right]^{2+}\) \(\left(\right.\) Complex 3) \(\mathrm{CoClBr} \cdot 5 \mathrm{NH}_{3}\) Which of the three complexes can have (a) geometric isomers, (b) linkage isomers, (c) optical isomers, (d) coordination-sphere isomers?

Carbon monoxide, CO, is an important ligand in coordination chemistry. When CO is reacted with nickel metal, the product is \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right],\) which is a toxic, pale yellow liquid. (a) What is the oxidation number for nickel in this compound? (b) Given that \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) is a diamagnetic molecule with a tetrahedral geometry, what is the electron configuration of nickel in this compound? (c) Write the name for \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) using the nomenclature rules for coordination compounds.

Indicate the coordination number and the oxidation number of the metal for each of the following complexes: (a) \(\mathrm{Na}_{2}[\mathrm{Co}(\mathrm{EDTA})]\) (b) \(\mathrm{KMnO}_{4}\) (c) \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{2}\) (d) \(\mathrm{K}_{3} \mathrm{Fe}(\mathrm{CN})_{6}\) (e) \(\mathrm{Rh}\left(\mathrm{PPh}_{3}\right)_{3} \mathrm{Cl}\) (f) \(\mathrm{Zn}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\left(\mathrm{NH}_{3}\right)_{2}\)

Consider the following three complexes: \(\left(\right.\) Complex 1) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{Cl}\) 2) \(\left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{ONO})_{2}\right]\) (Complex (Complex 3) \(\left[\mathrm{V}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+},\) Which of the three complexes can have (a) geometric isomers, (b) linkage isomers, (c) optical isomers, (d) coordinationsphere isomers?

When Alfred Werner was developing the field of coordination chemistry, it was argued by some that the optical activity he observed in the chiral complexes he had prepared was due to the presence of carbon atoms in the molecule. To disprove this argument, Werner synthesized a chiral complex of cobalt that had no carbon atoms in it, and he was able to resolve it into its enantiomers. Design a cobalt(III) complex that would be chiral if it could be synthesized and that contains no carbon atoms. (It may not be possible to synthesize the complex you design, but we will not worry about that for now.)

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