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Complete and balance the nuclear equations for the following fission or fusion reactions: (a) \({ }_{92}^{235} \mathrm{U}+{ }_{0}^{1} \mathrm{n} \longrightarrow{ }_{36}^{92} \mathrm{Kr}+{ }_{56}^{141} \mathrm{Zn}+\) (b) \({ }_{1}^{2} \mathrm{H}+{ }_{1}^{3} \mathrm{H} \longrightarrow{ }_{2}^{4} \mathrm{He}+\)

Short Answer

Expert verified
The short answer is: (a) Completed and balanced fission reaction: \( {}_{92}^{235}U + {}_{0}^{1}n \longrightarrow {}_{36}^{92}Kr + {}_{56}^{141}Zn + {}_{0}^{3}n \) (b) Completed and balanced fusion reaction: \( {}_{1}^{2}H + {}_{1}^{3}H \longrightarrow {}_{2}^{4}He + {}_{0}^{1}n \)

Step by step solution

01

(a) Identify missing particles in the fission equation

: The fission equation is given as: \( {}_{92}^{235}U + {}_{0}^{1}n \longrightarrow {}_{36}^{92}Kr + {}_{56}^{141}Zn + ? \) There is one missing particle in this equation, represented by the question mark (?).
02

(a) Balance atomic number and mass number in the fission equation

: For the atomic number, we have on the left side of the equation: \( 92 + 0 = 92 \) On the right side, we currently have: \( 36 + 56 = 92 \) So, the atomic numbers are balanced. For the mass numbers, on the left side, we have: \( 235 + 1 = 236 \) On the right side, we have: \( 92 + 141 + ? \) So, we need to find the mass number of the missing particle such that it balances the equation: \( 92 + 141 + ? = 236 \) Solving for the missing mass number: \( ? = 236 - 92 - 141 = 3 \)
03

(a) Complete the fission equation

: Now that we know the mass number of the missing particle, we can complete the fission equation. The missing particle is a neutron with a mass number of 3: \( {}_{92}^{235}U + {}_{0}^{1}n \longrightarrow {}_{36}^{92}Kr + {}_{56}^{141}Zn + {}_{0}^{3}n \) The completed and balanced fission equation is: \( {}_{92}^{235}U + {}_{0}^{1}n \longrightarrow {}_{36}^{92}Kr + {}_{56}^{141}Zn + {}_{0}^{3}n \)
04

(b) Identify missing particles in the fusion equation

: The fusion equation is given as: \( {}_{1}^{2}H + {}_{1}^{3}H \longrightarrow {}_{2}^{4}He + ? \) There is one missing particle in this equation, represented by the question mark (?).
05

(b) Balance atomic number and mass number in the fusion equation

: For the atomic number, on the left side of the equation, we have: \( 1 + 1 = 2 \) On the right side, we currently have: \( 2 \) So, the atomic numbers are already balanced. For the mass numbers, on the left side of the equation, we have: \( 2 + 3 = 5 \) On the right side, we have: \( 4 + ? \) So, we need to find the mass number of the missing particle such that it balances the equation: \( 4 + ? = 5 \) Solving for the missing mass number: \( ? = 5 - 4 = 1 \)
06

(b) Complete the fusion equation

: Now that we know the mass number of the missing particle, we can complete the fusion equation. The missing particle is a neutron with a mass number of 1: \( {}_{1}^{2}H + {}_{1}^{3}H \longrightarrow {}_{2}^{4}He + {}_{0}^{1}n \) The completed and balanced fusion equation is: \( {}_{1}^{2}H + {}_{1}^{3}H \longrightarrow {}_{2}^{4}He + {}_{0}^{1}n \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fission Reactions
Fission reactions are a type of nuclear reaction where a heavy nucleus, like Uranium-235, splits into smaller nuclei, along with a few free neutrons and a large amount of energy. This process is what fuels nuclear power plants and certain types of bombs. In a typical fission reaction, a heavy nucleus absorbs a neutron, becomes unstable, and splits into two or more lighter nuclei.

The completed and balanced fission reaction from our problem involves Uranium-235 and a neutron. Initially, Uranium-235 (U) absorbs a neutron (), resulting in instability. It then splits into Krypton-92 and Barium-141, along with releasing additional neutrons. Balancing these equations is important to ensure that the number of protons and neutrons are equal on both sides, maintaining the fundamental law of mass conservation. The fission equation is given as:\[ {}_{92}^{235}U + {}_{0}^{1}n \longrightarrow {}_{36}^{92}Kr + {}_{56}^{141}Ba + {}_{0}^{3}n \]

In this balanced equation, Krypton (Kr) and Barium (Ba) are produced along with neutrons, which can further induce fission reactions in other Uranium-235 atoms, leading to a chain reaction.
Fusion Reactions
Fusion reactions occur when two light atomic nuclei combine to form a heavier nucleus, releasing energy in the process. This is the same reaction that powers the sun, where hydrogen nuclei (protons) fuse to form helium and release tremendous energy. Fusion reactions have the potential for clean energy production because they produce little radioactive waste.

In the balanced fusion reaction from our example, two isotopes of hydrogen, namely deuterium (H) and tritium (H), combine to form helium-4 and a neutron. Here's how the simplified fusion reaction appears:\[ {}_{1}^{2}H + {}_{1}^{3}H \longrightarrow {}_{2}^{4}He + {}_{0}^{1}n \]

To balance the nuclear equation, ensuring that both mass numbers and atomic numbers are equivalent on both sides of the reaction is essential. For example, both the number of protons and the net mass remain conserved, with two protons and three neutrons in total appearing on either side of the equation.
Balancing Equations
Balancing nuclear equations is crucial for representing the conservation of mass and atomic numbers during a nuclear reaction. In nuclear chemistry, just like in chemical reactions, the sum of mass numbers (overall number of nucleons) and atomic numbers (protons) must be the same on both sides.

For fission reactions, typically a heavy nucleus breaks down into lighter nuclei and neutrons. When working with fission equations, we must ensure the sum of atomic numbers (representing protons) and the sum of mass numbers are equal on both sides.

  • Left Side: Add up the atomic and mass numbers.
  • Right Side: Make sure their totals match with the left side.
  • Check and balance missing particles, like neutrons.
In the case of fusion reactions, light elements such as isotopes of hydrogen combine, and it is important to reflect accurately the particles interacting.
  • Verify that protons and neutrons are both preserved.
  • Always cross-check with expected output particles like helium and any free neutrons.
These balanced equations allow us to predict how many particles are produced and to understand the immense energy made available from nuclear reactions.

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Most popular questions from this chapter

The Sun radiates energy into space at the rate of \(3.9 \times 10^{26} \mathrm{~J} / \mathrm{s} .\) (a) Calculate the rate of mass loss from the Sun in kg/s. (b) How does this mass loss arise? (c) It is estimated that the Sun contains \(9 \times 10^{56}\) free protons. How many protons per second are consumed in nuclear reactions in the Sun?

Complete and balance the following nuclear equations by supplying the missing particle: (a) \({ }_{47}^{106} \mathrm{Ag}+{ }_{-1}^{0} \mathrm{e} \longrightarrow ?\) (b) \({ }_{106}^{263} \mathrm{Sg} \longrightarrow{ }_{2}^{4} \mathrm{He}+?\) (c) \({ }_{84}^{216} \mathrm{Po} \longrightarrow{ }_{82}^{212} \mathrm{~Pb}+?\) (d) \({ }_{5}^{10} \mathrm{~B}+? \longrightarrow{ }_{3} \mathrm{Li}+{ }_{2}^{4} \mathrm{He}\) (e) \({ }^{220} \mathrm{Rn} \longrightarrow{ }_{2}^{4} \mathrm{He}+?\)

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