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Trouton's rule states that for many liquids at their normal boiling points, the standard molar entropy of vaporization is about \(88 \mathrm{~J} / \mathrm{mol}-\mathrm{K} .(\) a) Estimate the normal boiling point of bromine, \(\mathrm{Br}_{2}\), by determining \(\Delta H_{\text {vap }}^{\circ}\) for \(\mathrm{Br}_{2}\) using data from Appendix \(C\). Assume that \(\Delta H_{\text {vap }}^{\circ}\) remains constant with temperature and that Trouton's rule holds. (b) Look up the normal boiling point of \(\mathrm{Br}_{2}\) in a chemistry handbook or at the WebElements website (www.webelements.com) and compare it to your calculation. What are the possible sources of error, or incorrect assumptions, in the calculation?

Short Answer

Expert verified
Using Trouton's rule and the given data, we estimated the normal boiling point of Br鈧 to be around 340.9 K. The actual value is 332 K. Errors in the calculation could arise from Trouton's rule being an approximation, the assumption that 鈭咹鈧愨倸掳 remains constant with temperature, and using rounded values for 鈭咹鈧愨倸掳 and 鈭哠鈧愨倸鈧. Despite these possible sources of errors, the estimated boiling point is still reasonably close to the actual value.

Step by step solution

01

Find 鈭咹鈧愨倸掳 for Br鈧

First, we need to find the standard molar enthalpy of vaporization (鈭咹鈧愨倸掳) for Br鈧. You can find this value in Appendix C of your textbook or other chemistry references. The value for 鈭咹鈧愨倸掳 for Br鈧 is approximately 30 kJ/mol.
02

Calculate the standard molar entropy of vaporization for Br鈧

According to Trouton's rule, the standard molar entropy of vaporization for many liquids at their normal boiling points is about 88 J/mol路K. Therefore, for Br鈧, we can assume: \[\Delta S_{\text{vap}}^{\circ} = 88\, \mathrm{J/mol} \cdot \mathrm{K}\]
03

Estimate the normal boiling point of Br鈧 using Trouton's rule

To estimate the normal boiling point of Br鈧, we can use the following relation between 鈭咹鈧愨倸掳 and 鈭哠鈧愨倸: \[\Delta H_{\text{vap}}^{\circ} = T_{\text{bp}} \cdot \Delta S_{\text{vap}}^{\circ}\] Now, we can rearrange the equation to solve for the normal boiling point (T鈧) of Br鈧: \[T_{\text{bp}} = \frac{\Delta H_{\text{vap}}^{\circ}}{\Delta S_{\text{vap}}^{\circ}}\] Plug in the values for 鈭咹鈧愨倸掳 and 鈭 S鈧愨倸: \[T_{\text{bp}} = \frac{30,000\, \mathrm{J/mol}}{88\, \mathrm{J/mol} \cdot \mathrm{K}}\] \[T_{\text{bp}} \approx 340.9\, \mathrm{K}\] So, using Trouton's rule, the estimated normal boiling point of Br鈧 is around 340.9 K.
04

Compare with the actual value and discuss possible sources of errors

Now, we need to compare our calculated value with the actual value for the normal boiling point of Br鈧, which can be found in a chemistry handbook or on the WebElements website. The actual value is 332 K. There is a difference between our estimated value and the actual value. Possible sources of error and incorrect assumptions include: 1. Trouton's rule is an approximation, and it might not hold true for all substances, including halogens such as bromine. 2. We assumed that 鈭咹鈧愨倸掳 remains constant with temperature, but it can vary for some substances. 3. Errors could also be introduced by using rounded values for 鈭咹鈧愨倸掳 and 鈭哠鈧愨倸鈧. Despite these possible sources of errors, the estimated boiling point is still reasonably close to the actual value, demonstrating the usefulness of Trouton's rule as an estimation tool.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Entropy of Vaporization
Entropy is a measure of disorder or randomness in a system, and the entropy of vaporization represents the change in disorder when a liquid becomes a gas. At the boiling point, molecules gain enough energy to overcome intermolecular forces and transition from a liquid to a vapor.

When a substance vaporizes, its entropy increases significantly because gas molecules have more freedom to move compared to their liquid state. According to Trouton's Rule, the standard molar entropy of vaporization (\( \Delta S_{\text{vap}}^{\circ} \)) for many liquids is approximately 88 J/mol路K.

This rule suggests a constant value due to the similarly random distribution of gas molecules at boiling points, across many different liquids. However, this estimation may vary slightly based on the specific characteristics and molecular interactions of a given substance.
Enthalpy of Vaporization
Enthalpy of vaporization (\( \Delta H_{\text{vap}}^{\circ} \)) is the amount of energy required to convert one mole of a liquid into a gas at its boiling point, under standard conditions. It reflects the strength of intermolecular forces in the liquid.

Substances with stronger intermolecular forces require more energy to vaporize, resulting in higher enthalpy of vaporization values. For bromine, the standard molar enthalpy of vaporization was found to be approximately 30 kJ/mol.
  • The enthalpy of vaporization can provide insights on the amount of heat needed for phase changes.
  • Knowing this value is crucial for estimating boiling points using Trouton's Rule.
Though this energy requirement can change slightly with temperature, for practical estimations, it is often assumed constant over small temperature ranges like those involved in calculating boiling points.
Boiling Point Estimation
Estimating the boiling point of a substance can be approached using the relationship between enthalpy of vaporization and entropy of vaporization. According to Trouton's Rule, this estimation involves dividing the enthalpy of vaporization by the entropy of vaporization:

\[ T_{\text{bp}} = \frac{\Delta H_{\text{vap}}^{\circ}}{\Delta S_{\text{vap}}^{\circ}} \]

In the case of bromine (\( \text{Br}_2 \)), plugging in the values:
  • \( \Delta H_{\text{vap}}^{\circ} = 30,000 \, \text{J/mol} \)
  • \( \Delta S_{\text{vap}}^{\circ} = 88 \, \text{J/mol} \cdot \text{K} \)
provides an estimated boiling point of approximately 340.9 K.

This predicted temperature is slightly higher than the actual boiling point of 332 K for bromine, indicating possible deviations due to simplifications in the calculation, such as:
  • Natural variance in Trouton's Rule applicability across different substances.
  • Assuming enthalpy remains constant with temperature, which might not hold true over larger ranges.
  • Use of average or rounded data values in calculation affecting precision.
Despite these potential errors, this method provides a useful estimation, especially when detailed data or alternative methods are not available.

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Most popular questions from this chapter

Consider the reaction \(2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g)\) (a) Using data from Appendix \(\mathrm{C},\) calculate \(\Delta G^{\circ}\) at \(298 \mathrm{~K}\). (b) Calculate \(\Delta G\) at \(298 \mathrm{~K}\) if the partial pressures of all gases are \(33.4 \mathrm{kPa}\).

For the isothermal expansion of a gas into a vacuum, \(\Delta E=0, q=0,\) and \(w=0 .\) (a) Is this a spontaneous process? (b) Explain why no work is done by the system during this process. \((\mathbf{c})\) What is the "driving force" for the expansion of the gas: enthalpy or entropy?

Indicate whether each of the following statements is trueor false. If it is false, correct it. (a) The feasibility of manufacturing \(\mathrm{NH}_{3}\) from \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2}\) depends entirely on the value of \(\Delta H\) for the process \(\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g) .\) (b) The reaction of \(\mathrm{Na}(s)\) with \(\mathrm{Cl}_{2}(g)\) to form \(\mathrm{NaCl}(s)\) is a spontaneous process. (c) A spontaneous process can in principle be conducted reversibly. (d) Spontaneous processes in general require that work be done to force them to proceed. (e) Spontaneous processes are those that are exothermic and that lead to a higher degree of order in the system.

For each of the following pairs, predict which substance has the higher entropy per mole at a given temperature: (a) \(\mathrm{I}_{2}(s)\) or \(\mathrm{I}_{2}(g)\) (b) \(\mathrm{O}_{2}(g)\) at \(50.7 \mathrm{kPa}\) or \(\mathrm{O}_{2}\) at \(101.3 \mathrm{kPa}\) (c) 1 molof \(\mathrm{N}_{2}\) in 22.4 Lor \(1 \mathrm{~mol}\) of \(\mathrm{N}_{2}\) in \(44.8 \mathrm{~L}\). (d) \(\mathrm{CH}_{3} \mathrm{OH}(I)\) or \(\mathrm{CH}_{3} \mathrm{OH}(s)\)

(a) What is the difference between a state and a microstate of a system? (b) As a system goes from state A to state B, its entropy decreases. What can you say about the number of microstates corresponding to each state? (c) In a particular spontaneous process, the number of microstates available to the system decreases. What can you conclude about the sign of \(\Delta S\) surr?

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