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Predict the stronger acid in each pair: (a) \(\mathrm{HCl}\) or HF; (b) \(\mathrm{H}_{3} \mathrm{PO}_{4}\) or \(\mathrm{H}_{3} \mathrm{AsO}_{4} ;\) (c) \(\mathrm{HBrO}_{3}\) or \(\mathrm{HBrO}_{2}\) (d) \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) or \(\mathrm{HC}_{2} \mathrm{O}_{4} \overline{;} ;(\mathbf{e})\) benzoic acid \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\right)\) or phenol \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right) .\)

Short Answer

Expert verified
The stronger acids among the given pairs are: (a) HCl (b) H鈧傾sO鈧 (c) HBrO鈧 (d) HC鈧侽鈧勨伝 (e) Benzoic acid (C鈧咹鈧匔OOH)

Step by step solution

01

Evaluate Electronegativity Difference

In this case, it is helpful to compare the electronegativity difference between the central atoms, Cl and F. The general trend of the periodic table is that electronegativity increases as we move right across a period and decreases as we move down a group. Since chlorine is lower in the periodic table, it is less electronegative than fluorine.
02

Determine the Stronger Acid

Fluorine is more electronegative, so it holds the shared electrons more tightly. But this makes it less willing to give up a proton, and therefore, HF is a weaker acid than HCl. #b) H鈧働O鈧 vs H鈧傾sO鈧#
03

Evaluate Atomic Size

Phosphorous and arsenic are in the same group but differ in the period they belong to. Since arsenic lies in a lower period, it is a larger atom compared to phosphorous.
04

Determine the Stronger Acid

A larger size atom stabilizes the negative charge on the conjugate base better. Therefore, H鈧傾sO鈧 is a stronger acid than H鈧働O鈧. #c) HBrO鈧 vs HBrO鈧#
05

Evaluate the Number of Oxygen Atoms

Start by counting the number of oxygen atoms surrounding the central bromine atom. In HBrO鈧, there are three oxygen atoms, whereas, in HBrO鈧, there are only two oxygen atoms.
06

Determine the Stronger Acid

More oxygen atoms increase the electron-withdrawing nature of the molecule, which stabilizes the resulting negative charge on the conjugate base. Therefore, HBrO鈧 is a stronger acid than HBrO鈧. #d) H鈧侰鈧侽鈧 vs HC鈧侽鈧勨垝 #
07

Compare the number of acidic protons

H鈧侰鈧侽鈧 has two acidic protons, whereas its counterpart HC鈧侽鈧勨伝 has only one acidic proton.
08

Determine the Stronger Acid

H鈧侰鈧侽鈧 can donate two protons, and therefore its conjugate base has a higher charge (2-) compared to HC鈧侽鈧勨伝, which has one proton to donate and has a conjugate base with a charge of 1-. Due to the higher charge stabilization needed for the H鈧侰鈧侽鈧 conjugate base, HC鈧侽鈧勨伝 is the stronger acid. #e) Benzoic acid (C鈧咹鈧匔OOH) vs Phenol (C鈧咹鈧匫H)#
09

Examine the functional groups

Look at the functional groups of the two compounds. Benzoic acid has a carboxyl group (COOH), and phenol has a hydroxyl group (OH).
10

Evaluate resonance structures

For benzoic acid, the resulting negative charge from donating a proton is stabilized through resonance with the aromatic ring. In the case of phenol, the negative charge formed after donating a proton can also be stabilized through resonance, but to a lesser extent because the anion is less delocalized compared to benzoic acid.
11

Determine the Stronger Acid

Due to the higher stabilization of the negative charge through resonance in the carboxyl group, benzoic acid (C鈧咹鈧匔OOH) is a stronger acid compared to phenol (C鈧咹鈧匫H).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electronegativity
Electronegativity is a measure of an atom's ability to attract and hold onto electrons. This property is crucial in determining the strength of acids. When you look at the periodic table, electronegativity increases from left to right across a period and decreases from top to bottom in a group. This trend is necessary to understand when comparing acids such as HCl and HF.

Fluorine is the most electronegative element, meaning it tightly holds onto electrons. This tight hold on the shared electrons in HF makes it harder for the compound to give up a proton, which is a necessary function for acid strength. Consequently, HF is a weaker acid than HCl, where chlorine, with lesser electronegativity, allows for easier proton donation and thus greater acid strength. Understanding these trends in electronegativity helps predict the reactivity and strength of acids effectively.
Conjugate Base Stabilization
The strength of an acid can also be determined by how well its conjugate base stabilizes the charge once a proton is donated. This principle plays a significant role in comparing acids like H extsubscript{3}PO extsubscript{4} and H extsubscript{3}AsO extsubscript{4}.

In this example, arsenic in H extsubscript{3}AsO extsubscript{4} is larger than phosphorous in H extsubscript{3}PO extsubscript{4}, allowing the arsenate ion to better stabilize the negative charge that forms after the acid donates a proton. The ability of a larger atom to distribute the negative charge effectively across its surface makes H extsubscript{3}AsO extsubscript{4} a stronger acid. Understanding how size and electron distribution improve charge stabilization in conjugate bases helps explain why certain acids are stronger than others.
Resonance Structures
Resonance structures are a way of describing delocalized electrons within a molecule. They play a significant role in the stability of molecules and their ability to act as acids. In the example of benzoic acid (C extsubscript{6}H extsubscript{5}COOH) versus phenol (C extsubscript{6}H extsubscript{5}OH), resonance greatly influences acid strength.

When benzoic acid donates a proton, the negative charge on the oxygen is delocalized over the aromatic ring, stabilizing the resulting anion. This resonance stabilization makes benzoic acid a stronger acid.

In phenol, though there is also resonance, the extent is less as the anion isn't as effectively delocalized, resulting in weaker stabilization. Having a solid grasp of resonance helps you understand why certain molecules stabilize their charges better upon losing a proton, resulting in higher acid strength.
Functional Groups
Functional groups are specific groups of atoms within molecules that determine the characteristic reactions of those molecules. They are important in evaluating the chemical behaviors, such as acidity, of molecules like benzoic acid and phenol.

In comparing C extsubscript{6}H extsubscript{5}COOH (benzoic acid) and C extsubscript{6}H extsubscript{5}OH (phenol), the carboxyl group (COOH) of benzoic acid is a key player in its acid strength. This group tends to donate protons readily, and the negative charge left behind is stabilized by resonance, as previously discussed.

On the other hand, phenol contains a hydroxyl group (OH), which is not as effective in stabilizing the negative charge after proton donation. Having a good understanding of functional groups and how they affect molecular stability and reactivity can provide deeper insights into acid strength and behavior.

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Most popular questions from this chapter

Calculate \(\left[\mathrm{OH}^{-}\right]\) and \(\mathrm{pH}\) for (a) \(1.5 \times 10^{-3} \mathrm{MSr}(\mathrm{OH})_{2},\) (b) \(2.250 \mathrm{~g}\) of \(\mathrm{LiOH}\) in \(250.0 \mathrm{~mL}\) of solution, \((\mathbf{c}) 1.00\) \(\mathrm{mL}\) of \(0.175 \mathrm{M} \mathrm{NaOH}\) diluted to \(2.00 \mathrm{~L},(\mathbf{d})\) a solution formed by adding \(5.00 \mathrm{~mL}\) of \(0.105 \mathrm{M} \mathrm{KOH}\) to \(15.0 \mathrm{~mL}\) of \(9.5 \times 10^{-2} \mathrm{MCa}(\mathrm{OH})_{2}\)

The amino acid glycine \(\left(\mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}\right)\) can participate in the following equilibria in water: \(\mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons\) $$ \mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COO}^{-}+\mathrm{H}_{3} \mathrm{O}^{+} \quad K_{\mathrm{a}}=4.3 \times 10^{-3} $$ $$ \begin{aligned} \mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}+\mathrm{H}_{2} \mathrm{O} & \rightleftharpoons \\ &{ }^{+} \mathrm{H}_{3} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}+\mathrm{OH}^{-} \quad K_{\mathrm{b}}=6.0 \times 10^{-5} \end{aligned} $$ (a) Use the values of \(K_{a}\) and \(K_{b}\) to estimate the equilibrium constant for the intramolecular proton transfer to form a zwitterion: $$ \mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH} \rightleftharpoons{ }^{+} \mathrm{H}_{3} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COO}^{-} $$ (b) What is the pH of a 0.050 Maqueous solution of glycine? (c) What would be the predominant form of glycine in a solution with \(\mathrm{pH} 13\) ? With \(\mathrm{pH}\) ?

Succinic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{4}\right),\) which we will denote \(\mathrm{H}_{2} \mathrm{Suc}\) is a biologically relevant diprotic acid with the structure shown below. At \(25^{\circ} \mathrm{C}\), the acid-dissociation constants for succinic acid are \(K_{a 1}=6.9 \times 10^{-5}\) and \(K_{a 2}=2.5 \times 10^{-6} .\) (a) Determine the pH of a \(0.32 \mathrm{M}\) solution of \(\mathrm{H}_{2} \mathrm{Suc}\) at \(25^{\circ} \mathrm{C}\), assuming that only the first dissociation is relevant. (b) Determine the molar concentration of \(\mathrm{Suc}^{2-}\) in the solution in part (a). (c) Is the assumption you made in part (a) justified by the result from part (b)? (d) Will a solution of the salt NaHSuc be acidic, neutral, or basic?

Which of the following statements is false? (a) An Arrhenius base increases the concentration of \(\mathrm{OH}^{-}\) in water. (b) A Br酶nsted-Lowry base is a proton acceptor. (c) Water can act as a Br酶nsted-Lowry acid. (d) Water can act as a Br酶nsted-Lowry base. (e) Any compound that contains an -OH group acts as a Br酶nsted-Lowry base.

A \(0.100 \mathrm{M}\) solution of bromoacetic acid \(\left(\mathrm{BrCH}_{2} \mathrm{COOH}\right)\) is 13.2\% ionized. Calculate \(\left[\mathrm{H}^{+}\right],\left[\mathrm{BrCH}_{2} \mathrm{COO}^{-}\right],\left[\mathrm{BrCH}_{2} \mathrm{COOH}\right]\) and \(K_{a}\) for bromoacetic acid.

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