/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 \(\mathrm{NH}_{3}(g)\) and \(\ma... [FREE SOLUTION] | 91影视

91影视

\(\mathrm{NH}_{3}(g)\) and \(\mathrm{HCl}(g)\) react to form the ionic solid \(\mathrm{NH}_{4} \mathrm{Cl}(s) .\) Which substance is the Br酶nsted-Lowry acid in this reaction? Which is the Br酶nsted-Lowry base?

Short Answer

Expert verified
In the reaction \(\mathrm{NH}_3(g) + \mathrm{HCl}(g) \rightarrow \mathrm{NH}_4\mathrm{Cl}(s)\), the Br酶nsted-Lowry acid is hydrogen chloride (HCl), which donates a proton, and the Br酶nsted-Lowry base is ammonia (NH鈧), which accepts a proton.

Step by step solution

01

Recall the definitions of Br酶nsted-Lowry acids and bases

A Br酶nsted-Lowry acid is a substance that donates a proton, or hydrogen ion (H鈦), to another substance. A Br酶nsted-Lowry base, on the other hand, is a substance that accepts a proton, or hydrogen ion (H鈦), from another substance.
02

Write down the given reaction

The given reaction is: \[\mathrm{NH}_3(g) + \mathrm{HCl}(g) \rightarrow \mathrm{NH}_4\mathrm{Cl}(s)\]
03

Identify the proton donor (Acid) and proton acceptor (Base)

In the given reaction, ammonia (NH鈧) has a lone pair of electrons, which allows it to accept a hydrogen ion (proton) from hydrogen chloride (HCl). As the proton donor, hydrogen chloride (HCl) is the Br酶nsted-Lowry acid. Ammonia (NH鈧), which accepts the proton from HCl, is the Br酶nsted-Lowry base. After accepting the proton, NH鈧 becomes NH鈧勨伜, which then combines with Cl鈦 to form the ionic compound ammonium chloride (NH鈧凜l).
04

State the Br酶nsted-Lowry acid and base for this reaction

In the reaction between ammonia (NH鈧) and hydrogen chloride (HCl) gases to form the ionic solid ammonium chloride (NH鈧凜l), the Br酶nsted-Lowry acid is hydrogen chloride (HCl) and the Br酶nsted-Lowry base is ammonia (NH鈧).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reactions
Acid-base reactions are fundamental chemical processes where acids and bases interact, often resulting in the formation of water and a salt. In this type of reaction, an acid donates a proton (H鈦) to a base, which accepts the proton. This process can occur in various states鈥攇ases, liquids, or solids. The reaction between ammonia (NH鈧) and hydrogen chloride (HCl) is a classic example. When these gases combine, a proton transfer takes place, leading to the formation of the solid ammonium chloride (NH鈧凜l).
This simple proton exchange highlights the versatility of acid-base reactions beyond liquid solutions, showcasing their presence in gaseous states as well. Such interactions are vital in understanding chemical behavior in different environments.
Understanding acid-base reactions allows chemists to manipulate chemical processes, predict reaction outcomes, and synthesize desired compounds effectively.
Proton Donor
In the Br酶nsted-Lowry theory of acids and bases, an acid is known as a proton donor. This means that during a reaction, the acid relinquishes a hydrogen ion (H鈦) to another substance. Proton donation is crucial in the identification of acids in chemical reactions.
For instance, in the reaction between NH鈧 and HCl, hydrogen chloride (HCl) serves as the proton donor. It gives up its proton to NH鈧, leading to the formation of NH鈧勨伜, the ammonium ion. This ability to release a proton is what classifies HCl as a Br酶nsted-Lowry acid.
Understanding proton donors in reactions helps in determining how substances interact and transform, providing insight into the nature and structure of the resulting compounds.
Proton Acceptor
The concept of a proton acceptor is central to the Br酶nsted-Lowry definition of bases. A base is a substance that receives a proton (H鈦) from an acid. Proton acceptance enables the identification and classification of bases in numerous chemical reactions.
In the interaction between ammonia (NH鈧) and hydrogen chloride (HCl), NH鈧 acts as the proton acceptor. By accepting a proton from HCl, NH鈧 transforms into the ammonium ion (NH鈧勨伜). This process underscores NH鈧's role as the Br酶nsted-Lowry base in this reaction.
Identifying proton acceptors is essential in understanding reaction mechanisms, as it highlights how molecules adjust their structures and bonding characteristics during chemical interactions.
Ionic Compounds
Ionic compounds consist of positively and negatively charged ions held together by electrostatic forces, known as ionic bonds. These compounds often form from reactions between elements or compounds that transfer electrons to achieve stability.
In the case of the reaction between NH鈧 and HCl, the resulting compound is ammonium chloride (NH鈧凜l). Here, NH鈧勨伜 (ammonium ion) and Cl鈦 (chloride ion) combine to form the solid ionic compound.
The properties of ionic compounds, such as high melting and boiling points, conductivity when molten or dissolved in water, and distinctive crystalline structures, are directly linked to their ionic bonds. Understanding ionic compounds is pivotal in fields such as material science and industrial chemistry, where they are used in various applications, from salt production to electrolyte solutions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the chemical equation and the \(K_{a}\) expression for the acid dissociation of each of the following acids in aqueous solution. First show the reaction with \(\mathrm{H}^{+}(a q)\) as a product and then with the hydronium ion: (a) \(\mathrm{HSO}_{4}^{-}\), (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\).

Calculate the molar concentration of \(\mathrm{OH}^{-}\) in a \(0.724 \mathrm{M}\) solution of hypobromite ion \(\left(\mathrm{BrO}^{-} ; K_{b}=4.0 \times 10^{-6}\right) .\) What is the \(\mathrm{pH}\) of this solution?

Identify the Br酶nsted-Lowry acid and the Br酶nsted-Lowry base on the left side of each of the following equations, and also identify the conjugate acid and conjugate base of each on the right side: (a) \(\mathrm{NH}_{4}^{+}(a q)+\mathrm{CN}^{-}(a q) \rightleftharpoons \mathrm{HCN}(a q)+\mathrm{NH}_{3}(a q)\) (b) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons\) $$ \left(\mathrm{CH}_{3}\right)_{3} \mathrm{NH}^{+}(a q)+\mathrm{OH}^{-}(a q) $$ (c) \(\mathrm{HCOOH}(a q)+\mathrm{PO}_{4}^{3-}(a q) \rightleftharpoons\) $$ \mathrm{HCOO}^{-}(a q)+\mathrm{HPO}_{4}^{2-}(a q) $$

Atmospheric \(\mathrm{CO}_{2}\) levels have risen by nearly \(20 \%\) over the past 40 years from 320 ppm to 400 ppm. (a) Given that the average \(\mathrm{pH}\) of clean, unpolluted rain today is 5.4 , determine the \(\mathrm{pH}\) of unpolluted rain 40 years ago. Assume that carbonic acid \(\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right)\) formed by the reaction of \(\mathrm{CO}_{2}\) and water is the only factor influencing \(\mathrm{pH}\). $$ \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{H}_{2} \mathrm{CO}_{3}(a q) $$ (b) What volume of \(\mathrm{CO}_{2}\) at \(25^{\circ} \mathrm{C}\) and \(101.3 \mathrm{kPa}\) is dissolved in a 20.0-L bucket of today's rainwater?

Oxalic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right)\) is a diprotic acid. By using data in Appendix \(\mathrm{D}\) as needed, determine whether each of the following statements is true: (a) \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) can serve as both a Bronsted-Lowry acid and a Br酶nsted-Lowry base. (b) \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\) is the conjugate base of \(\mathrm{HC}_{2} \mathrm{O}_{4}^{-}\). (c) An aqueous solution of the strong electrolyte \(\mathrm{KHC}_{2} \mathrm{O}_{4}\) will have \(\mathrm{pH}<7\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.