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What is the molecularity of each of the following elementary reactions? Write the rate law for each. (a) \(2 \mathrm{NO}(g) \longrightarrow \mathrm{N}_{2} \mathrm{O}_{2}(g)\) (b) (c) \(\mathrm{SO}_{3}(g) \longrightarrow \mathrm{SO}_{2}(g)+\mathrm{O}(g)\)

Short Answer

Expert verified
The molecularity and rate laws for the given elementary reactions are: (a) The reaction is bimolecular (molecularity = 2) with two molecules of NO reacting. The rate law is: Rate = k[NO]^2. (b) No reaction provided. (c) The reaction is unimolecular (molecularity = 1) with one molecule of SO3 reacting. The rate law is: Rate = k[SO3].

Step by step solution

01

a) Determining the molecularity of the reaction

The given reaction is: \( 2 \mathrm{NO}(g) \longrightarrow \mathrm{N}_{2} \mathrm{O}_{2}(g) \) There are 2 molecules of NO reacting in this elementary reaction. Therefore, the molecularity of the reaction is 2 (bimolecular).
02

a) Writing the rate law for the reaction

Since this is a bimolecular reaction with two molecules of NO reacting, the rate law is written as: Rate = k[NO]^2
03

b) Not provided

There's no reaction provided for part (b). Please provide the reaction to solve the problem.
04

c) Determining the molecularity of the reaction

The given reaction is: \( \mathrm{SO}_{3}(g) \longrightarrow \mathrm{SO}_{2}(g) + \mathrm{O}(g) \) There is 1 molecule of SO3 reacting in this elementary reaction. Therefore, the molecularity of the reaction is 1 (unimolecular).
05

c) Writing the rate law for the reaction

Since this is a unimolecular reaction with one molecule of SO3 reacting, the rate law is written as: Rate = k[SO3]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elementary Reactions
Elementary reactions are the simplest form of chemical reactions. These are singular steps that occur at the molecular level involving the actual collision and transformation of reactant molecules. In an elementary reaction, all reactants transform directly into products in a single event, or step. This makes them different from complex reactions, which involve multiple elementary steps.
For example, in the given exercise, the reaction \(2 \mathrm{NO}(g) \longrightarrow \mathrm{N}_{2} \mathrm{O}_{2}(g)\) is an elementary reaction. This means that two molecules of NO collide and immediately form one molecule of \(\mathrm{N}_{2} \mathrm{O}_{2}\).
Understanding elementary reactions is crucial, as they allow us to establish a direct relationship between reaction mechanisms and rate laws. Furthermore, since these reactions occur in one step, their reaction orders are derived directly from their stoichiometry.
Rate Law
The rate law provides an equation that relates the rate of a chemical reaction to the concentration of its reactants. Specifically, it describes how the concentration of each reactant affects the reaction rate.
For elementary reactions, the rate law is particularly straightforward since it directly follows the stoichiometry of the reaction. This means that the coefficients in the balanced chemical equation directly become the exponents in the rate law's expression.
Taking one of our examples, for the reaction \(2 \mathrm{NO}(g) \longrightarrow \mathrm{N}_{2} \mathrm{O}_{2}(g)\), the rate law is expressed as:
  • Rate = \(k[\mathrm{NO}]^2\)
This indicates a second-order reaction with respect to NO because it involves two molecules of NO reacting. Similarly, for the reaction \(\mathrm{SO}_{3}(g) \longrightarrow \mathrm{SO}_{2}(g)+\mathrm{O}(g)\), the rate law is:
  • Rate = \(k[\mathrm{SO}_{3}]\)
This represents a first-order reaction since it involves just one molecule of \(\mathrm{SO}_{3}\) reacting.
Unimolecular and Bimolecular Reactions
Molecularity refers to the number of reactant molecules involved in an elementary step. It helps categorize reactions based on the number of molecules required to initiate the reaction. Molecularity is always a whole number, and here are some common types:
  • Unimolecular reactions: In these reactions, only one molecule is needed to proceed. It usually involves a single compound breaking down into two or more products. An example is \(\mathrm{SO}_{3}(g) \longrightarrow \mathrm{SO}_{2}(g) + \mathrm{O}(g)\), where the molecularity is 1, thus termed unimolecular.
  • Bimolecular reactions: These involve two reacting molecules. This might include two identical or two different molecules colliding to form products. For instance, \(2 \mathrm{NO}(g) \longrightarrow \mathrm{N}_{2} \mathrm{O}_{2}(g)\), is a bimolecular reaction because it involves two NO molecules.
Understanding molecularity aids in predicting the mechanisms of reactions as well as their likely rates under varying conditions.

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Most popular questions from this chapter

Consider the following hypothetical aqueous reaction: \(\mathrm{A}(a q) \rightarrow \mathrm{B}(a q)\). A flask is charged with \(0.065 \mathrm{~mol}\) of \(\mathrm{A}\) in a total volume of \(100.0 \mathrm{~mL}\). The following data are collected: $$ \begin{array}{lccccc} \hline \text { Time (min) } & 0 & 10 & 20 & 30 & 40 \\ \hline \text { Moles of A } & 0.065 & 0.051 & 0.042 & 0.036 & 0.031 \\ \hline \end{array} $$ (a) Calculate the number of moles of \(\mathrm{B}\) at each time in the table, assuming that there are no molecules of \(\mathrm{B}\) at time zero and that A cleanly converts to B with no intermediates. (b) Calculate the average rate of disappearance of A for each 10 -min interval in units of \(M /\) s. (c) Between \(t=0 \mathrm{~min}\) and \(t=30 \mathrm{~min},\) what is the average rate of appearance of \(\mathrm{B}\) in units of \(\mathrm{M} / \mathrm{s}\) ? Assume that the volume of the solution is constant.

Consider the following reaction between mercury(II) chloride and oxalate ion: $$ 2 \mathrm{HgCl}_{2}(a q)+\mathrm{C}_{2} \mathrm{O}_{4}^{2-}(a q) \longrightarrow 2 \mathrm{Cl}^{-}(a q)+2 \mathrm{CO}_{2}(g)+\mathrm{Hg}_{2} \mathrm{Cl}_{2}(s) $$ The initial rate of this reaction was determined for several concentrations of \(\mathrm{HgCl}_{2}\) and \(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}\), and the following rate data were obtained for the rate of disappearance of \(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}\) : $$ \begin{array}{llll} \hline \text { Experiment } & {\left[\mathrm{HgCl}_{2}\right](M)} & {\left[\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\right](M)} & \text { Rate }(M / \mathrm{s}) \\ \hline 1 & 0.164 & 0.15 & 3.2 \times 10^{-5} \\ 2 & 0.164 & 0.45 & 2.9 \times 10^{-4} \\ 3 & 0.082 & 0.45 & 1.4 \times 10^{-4} \\ 4 & 0.246 & 0.15 & 4.8 \times 10^{-5} \\ \hline \end{array} $$ (a) What is the rate law for this reaction? (b) What is the value of the rate constant with proper units? (c) What is the reaction rate when the initial concentration of \(\mathrm{HgCl}_{2}\) is \(0.100 \mathrm{M}\) and that of \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\) is \(0.25 \mathrm{M}\) if the temperature is the same as that used to obtain the data shown?

(a) What factors determine whether a collision between two molecules will lead to a chemical reaction? (b) Does the rate constant for a reaction generally increase or decrease with an increase in reaction temperature? (c) Which factor is most sensitive to changes in temperature-the frequency of collisions, the orientation factor, or the fraction of molecules with energy greater than the activation energy?

The enzyme urease catalyzes the reaction of urea, \(\left(\mathrm{NH}_{2} \mathrm{CONH}_{2}\right)\), with water to produce carbon dioxide and ammonia. In water, without the enzyme, the reaction proceeds with a first-order rate constant of \(4.15 \times 10^{-5} \mathrm{~s}^{-1}\) at \(100^{\circ} \mathrm{C}\). In the presence of the enzyme in water, the reaction proceeds with a rate constant of \(3.4 \times 10^{4} \mathrm{~s}^{-1}\) at \(21^{\circ} \mathrm{C}\). (a) Write out the balanced equation for the reaction catalyzed by urease. \((\mathbf{b})\) If the rate of the catalyzed reaction were the same at \(100^{\circ} \mathrm{C}\) as it is at \(21^{\circ} \mathrm{C}\), what would be the difference in the activation energy between the catalyzed and uncatalyzed reactions? (c) In actuality, what would you expect for the rate of the catalyzed reaction at \(100^{\circ} \mathrm{C}\) as compared to that at \(21^{\circ} \mathrm{C} ?(\mathbf{d})\) On the basis of parts (c) and (d), what can you conclude about the difference in activation energies for the catalyzed and uncatalyzed reactions?

The gas-phase decomposition of ozone is thought to occur by the following two- step mechanism. Step \(1: \quad \mathrm{O}_{3}(g) \rightleftharpoons \mathrm{O}_{2}(g)+\mathrm{O}(g)\) (fast) Step \(2: \quad \mathrm{O}(g)+\mathrm{O}_{3}(\mathrm{~g}) \longrightarrow 2 \mathrm{O}_{2}(g)\) (slow) (a) Write the balanced equation for the overall reaction. (b) Derive the rate law that is consistent with this mechanism. (Hint: The product appears in the rate law.) (c) Is \(\mathrm{O}\) a catalyst or an intermediate? (d) If instead the reaction occurred in a single step, would the rate law change? If so, what would it be?

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