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Consider a hypothetical reaction between \(\mathrm{A}, \mathrm{B},\) and \(\mathrm{C}\) that is zero order in A, second order in B, and first order in C. (a) Write the rate law for the reaction. (b) How does the rate change when [A] is tripled and the other reactant concentrations are held constant? (c) How does the rate change when [B] is doubled and the other reactant concentrations are held constant? (d) How does the rate change when [C] is tripled and the other reactant concentrations are held constant? (e) By what factor does the rate change when the concentrations of all three reactants are doubled? (f) By what factor does the rate change when the concentrations of all three reactants are cut in half?

Short Answer

Expert verified
Solution: (a) The rate law is given by Rate = k * [B]^2 * [C]. (b) The rate remains unchanged when [A] is tripled. (c) The new rate is 4 times the initial rate when [B] is doubled. (d) The new rate is 3 times the initial rate when [C] is tripled. (e) The rate changes by a factor of 8 when all three reactants' concentrations are doubled. (f) The rate changes by a factor of \(\frac{1}{8}\) when all three reactants' concentrations are cut in half.

Step by step solution

01

(a) Write the rate law for the reaction

The rate law for a reaction can be expressed as: Rate = k * [A]^m * [B]^n * [C]^p where m, n, and p are the orders of the reactants A, B, and C respectively, and k is the rate constant. In this case, the reaction is zero order in A, second order in B, and first order in C. Therefore, the rate law is: Rate = k * [A]^0 * [B]^2 * [C]^1 This simplifies to: Rate = k * [B]^2 * [C]
02

(b) How does the rate change when [A] is tripled and the other reactant concentrations are held constant?

Since the reaction is zero order in A, tripling the concentration of A will not have any impact on the rate of the reaction. Thus, the rate remains unchanged.
03

(c) How does the rate change when [B] is doubled and the other reactant concentrations are held constant?

The reaction is second order in B, so if the concentration of B doubles, we can represent this change in the rate law: New Rate = k * [2B]^2 * [C] New Rate = k * (2^2) * [B]^2 * [C] New Rate = 4 * (k * [B]^2 * [C]) The new rate is 4 times the initial rate.
04

(d) How does the rate change when [C] is tripled and the other reactant concentrations are held constant?

The reaction is first order in C, so if the concentration of C triples, we can represent this change in the rate law: New Rate = k * [B]^2 * [3C] New Rate = 3 * (k * [B]^2 * [C]) The new rate is 3 times the initial rate.
05

(e) By what factor does the rate change when the concentrations of all three reactants are doubled?

We will have the concentrations of A, B, and C doubled: New Rate = k * [2A]^0 * [2B]^2 * [2C]^1 New Rate = k * [B]^2 * [C] * (2^2) * 2 The factor by which the rate changes is (2^2) * 2 = 8.
06

(f) By what factor does the rate change when the concentrations of all three reactants are cut in half?

We will have the concentrations of A, B, and C halved: New Rate = k * [\(\frac{1}{2}\)A]^0 * [\(\frac{1}{2}\)B]^2 * [\(\frac{1}{2}\)C]^1 New Rate = k * [B]^2 * [C] * (\(\frac{1}{2}\))^2 * \(\frac{1}{2}\) The factor by which the rate changes is (\(\frac{1}{2}\))^2 * \(\frac{1}{2}\) = \(\frac{1}{8}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Order of Reaction
The order of a reaction is a key concept used in chemistry to describe how the rate of a chemical reaction depends on the concentration of the reactants. Essentially, it determines the reaction's sensitivity to changes in concentration.
For example, consider a reaction involving substances A, B, and C. If this reaction is zero order in A, it means that changes in the concentration of A do not affect the reaction rate whatsoever. That's a superpower of sorts for the reaction involving A - the rate is independent of how much A you have around.
However, the reaction is second order in B and first order in C. This means, respectively, that the rate of the reaction will change if the concentration of B or C is changed. Specifically, doubling the concentration of B will lead to a fourfold increase in the rate, while tripling the concentration of C will result in a threefold increase in the rate of reaction.
This understanding of the order of reaction is crucial in predicting how altering reactant concentrations will affect the speed of reactions. It's like knowing the unique recipe that determines how the reaction takes place at different speeds.
Chemical Kinetics
Chemical kinetics is the branch of chemistry focused on the speed, or rate, at which reactions occur. It allows chemists to understand the factors that accelerate or decelerate a reaction, which is vital in both laboratory and industrial settings.
Kinetics involves studying the concentration of reactants and how they influence the rate of reactions. By using different orders of reactions — such as zero order for A, second order for B, and first order for C as in our exercise — kinetics helps us identify and predict the behavior of reactions over time.
Importantly, chemical kinetics also considers other factors beyond concentrations, such as temperature and catalysts, which can significantly affect reaction rates. By integrating these factors, chemists can control a reaction much like a maestro conducting an orchestra, ensuring events unfold with perfect timing.
  • Zero Order: Reaction rate is constant, regardless of concentration.
  • First Order: Reaction rate changes linearly with concentration.
  • Second Order: Rate increases exponentially as concentration rises.
Understanding these principles helps create more efficient industrial processes, optimize reactions for desired outcomes, and innovate in fields ranging from pharmaceuticals to materials science.
Rate Constant
The rate constant, often denoted as \(k\), is a crucial parameter in the rate law equation of a chemical reaction. It essentially acts like a dial that adjusts the speed at which a reaction proceeds.
In mathematical terms, the rate law for a reaction is expressed as:\[\text{Rate} = k \times [\text{A}]^m \times [\text{B}]^n \times [\text{C}]^p\]where \(m, n,\) and \(p\) represent the orders of reactants A, B, and C, respectively. This formula shows how the concentration of reactants and the rate constant together determine the reaction rate.
The beauty of the rate constant is that it is unique to every reaction at a given temperature. It doesn't just hover there; it's a key player influenced by environmental factors such as temperature, pressure, and presence of catalysts.
For example, in our exercise, the rate constant \(k\) stays the same regardless of changes in the reactant concentrations — unless external conditions vary. Think of \(k\) as the heart of the reaction's rate law equation; it beats at a rhythm set by the chemical and environmental surroundings, affecting how vigorously the reaction proceeds.

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Most popular questions from this chapter

The oxidation of \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{3}\) is accelerated by \(\mathrm{NO}_{2}\). The reaction proceeds according to: $$ \begin{array}{l} \mathrm{NO}_{2}(g)+\mathrm{SO}_{2}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{SO}_{3}(g) \\ 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) \end{array} $$ (a) Show that, with appropriate coefficients, the two reactions can be summed to give the overall oxidation of \(\mathrm{SO}_{2}\) by \(\mathrm{O}_{2}\) to give \(\mathrm{SO}_{3} .\) (b) Do we consider \(\mathrm{NO}_{2}\) a catalyst or an intermediate in this reaction? (c) Would you classify NO as a catalyst or as an intermediate? (d) Is this an example of homogeneous catalysis or heterogeneous catalysis?

The decomposition of hydrogen peroxide is catalyzed by iodide ion. The catalyzed reaction is thought to proceed by a two-step mechanism: $$ \begin{aligned} \mathrm{H}_{2} \mathrm{O}_{2}(a q)+\mathrm{I}^{-}(a q) & \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{IO}^{-}(a q)(\text { slow }) \\ \mathrm{IO}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}_{2}(a q) & \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{O}_{2}(g)+\mathrm{I}^{-}(a q) \quad(\text { fast }) \end{aligned} $$ (a) Write the chemical equation for the overall process. (b) Identify the intermediate, if any, in the mechanism. (c) Assuming that the first step of the mechanism is rate determining, predict the rate law for the overall process.

(a) What is a catalyst? (b) What is the difference between a homogeneous and a heterogeneous catalyst? (c) Do catalysts affect the overall enthalpy change for a reaction, the activation energy, or both?

Indicate whether each statement is true or false. (a) If you measure the rate constant for a reaction al different temperatures, you can calculate the overall enthalpy change for the reaction. (b) Exothermic reactions are faster than endothermic reactions. (c) If you double the temperature for a reaction, you cut the activation energy in half.

Indicate whether each statement is true or false. (a) If you compare two reactions with similar collision factors, the one with the larger activation energy will be faster. (b) A reaction that has a small rate constant must have a small frequency factor. (c) Increasing the reaction temperature increases the fraction of successful collisions between reactants.

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