/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 What is the osmotic pressure for... [FREE SOLUTION] | 91影视

91影视

What is the osmotic pressure formed by dissolving \(50.0 \mathrm{mg}\) of acetylsalicylic acid \(\left(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\right)\) in \(0.100 \mathrm{~L}\) of water at \(37^{\circ} \mathrm{C} ?\)

Short Answer

Expert verified
The osmotic pressure formed by dissolving 50.0 mg of acetylsalicylic acid in 0.100 L of water at 37掳C is approximately \(7.08 脳 10鈦宦瞈) atm.

Step by step solution

01

Calculate the molar mass of acetylsalicylic acid

To calculate the molar mass, we sum up the molar masses of all the atoms in acetylsalicylic acid (\(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\)). Molar mass of C: 12.01 g/mol Molar mass of H: 1.01 g/mol Molar mass of O: 16.00 g/mol Molar mass of acetylsalicylic acid = 9(12.01) + 8(1.01) + 4(16.00) = 180.16 g/mol
02

Determine the number of moles in the 50.0 mg sample

First, convert 50.0 mg to grams: 50.0 mg 脳 1 g/1000 mg = 0.0500 g Now, use the molar mass to find the number of moles: Number of moles = mass / molar mass = 0.0500 g / 180.16 g/mol = 2.77 脳 10鈦烩伌 mol
03

Calculate the molarity of the solution

Molarity (M) = number of moles / volume of solution in liters M = 2.77 脳 10鈦烩伌 mol / 0.100 L = 2.77 脳 10鈦宦 mol/L
04

Convert temperature from Celsius to Kelvin

To convert temperature from Celsius to Kelvin, we add 273.15 to the Celsius temperature: T(K) = 37掳C + 273.15 = 310.15 K
05

Calculate the osmotic pressure

Use the osmotic pressure formula, remembering that van't Hoff factor (i) is 1 for non-electrolyte substances like acetylsalicylic acid: \( \Pi = iMRT \) Plug in the values: (M = 2.77 脳 10鈦宦 mol/L, R = 0.0821 L atm/mol K, and T = 310.15 K) \( \Pi = 1 脳 (2.77 脳 10鈦宦 \: \text{mol/L}) 脳 (0.0821 \: \text{L atm/mol K}) 脳 (310.15 \: \text{K}) \) \( \Pi = 7.08 脳 10鈦宦 \: \text{atm} \) The osmotic pressure formed by dissolving 50.0 mg of acetylsalicylic acid in 0.100 L of water at 37掳C is approximately 7.08 脳 10鈦宦 atm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
When calculating the molar mass of a compound such as acetylsalicylic acid, it is crucial to understand the atomic composition of the substance. Each element in the molecule contributes to the total molar mass. For acetylsalicylic acid ( C鈧塇鈧圤鈧), we calculate it as follows:
  • Carbon (C): 9 atoms 脳 12.01 g/mol = 108.09 g/mol
  • Hydrogen (H): 8 atoms 脳 1.01 g/mol = 8.08 g/mol
  • Oxygen (O): 4 atoms 脳 16.00 g/mol = 64.00 g/mol
Adding these values together gives a total molar mass of 180.16 g/mol. This basic calculation is essential for converting between mass and moles, which is a common need in chemistry.
By breaking down the molecular formula into individual atoms and using their molar masses, you can calculate the molar mass of any substance.
Molarity Determination
Molarity, an important concept in chemistry, refers to the concentration of a solute in a solution. It is expressed as the number of moles of solute per liter of solution (mol/L). Calculating molarity involves knowing both the amount of solute and the total volume of the solution.
In our example:
  • Number of moles of acetylsalicylic acid: After converting the mass from mg to g, the number of moles is calculated using the formula: \[ \text{Number of moles} = \frac{\text{mass in grams}}{\text{molar mass}} \]
  • Volume of solution: Given in liters, in this case, it is 0.100 L.
  • Molarity (M): Calculated using: \[ M = \frac{\text{number of moles}}{\text{volume in liters}} \]
This gives us a molarity of 2.77 脳 10鈦宦 mol/L. Accurately determining molarity is essential for predicting the behavior of substances in solutions.
Temperature Conversion
Temperature conversion is often necessary when dealing with scientific formulas that require absolute temperature values, usually in Kelvin. Converting Celsius to Kelvin is straightforward. The Celsius scale needs to be adjusted by adding 273.15 to align with the absolute scale of Kelvin, which begins at absolute zero.
In this example, we convert 37掳C to Kelvin as follows:
  • Formula: \[ T(\text{K}) = T(\text{掳C}) + 273.15 \]
Applying this conversion: 37掳C + 273.15 = 310.15 K
Using the Kelvin temperature is crucial when applying it to calculations, such as those involving the gas constant in physical chemistry.
Osmotic Pressure Formula
Osmotic pressure is the pressure required to prevent the flow of solvent into a solution through a semipermeable membrane. It is a fundamental concept in solutions, particularly biology and chemistry. The osmotic pressure ( \( \Pi \)) can be calculated using van't Hoff's formula:
  • Formula: \[ \Pi = iMRT \]
  • Van't Hoff factor (i): Represents the number of particles the solute forms in solution. For acetylsalicylic acid, it is 1 because it doesn't dissociate.
  • Molarity (M): As calculated, 2.77 脳 10鈦宦 mol/L.
  • Gas Constant (R): 0.0821 L atm/mol K, a universal constant used for ideal gas calculations.
  • Temperature (T): The absolute temperature in Kelvin (310.15 K).
Substituting the values into the formula, we find:\[ \Pi = 1 \times (2.77 \times 10^{-3} \text{ mol/L}) \times (0.0821 \text{ L atm/mol K}) \times (310.15 \text{ K}) \]
This results in an osmotic pressure of approximately 7.08 脳 10鈦宦 atm, demonstrating how solute concentration and temperature affect it.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Describe how you would prepare each of the following aqueous solutions, starting with solid \(\mathrm{KBr}\) : (a) \(0.75 \mathrm{~L}\) of \(1.5 \times 10^{-2} M \mathrm{KBr},(\mathbf{b}) 125 \mathrm{~g}\) of \(0.180 \mathrm{~m} \mathrm{KBr},(\mathbf{c}) 1.85 \mathrm{~L}\) of a solution that is \(12.0 \% \mathrm{KBr}\) by mass (the density of the solution is \(1.10 \mathrm{~g} / \mathrm{mL}),\) (d) a \(0.150 \mathrm{M}\) solution of \(\mathrm{KBr}\) that contains just enough \(\mathrm{KBr}\) to precipitate \(16.0 \mathrm{~g}\) of AgBr from a solution containing \(0.480 \mathrm{~mol}\) of \(\mathrm{AgNO}_{3}\).

Calculate the number of moles of solute present in each of the following solutions: (a) \(255 \mathrm{~mL}\) of \(1.50 \mathrm{M} \mathrm{HNO}_{3}(a q)\) (b) \(50.0 \mathrm{mg}\) of an aqueous solution that is \(1.50 \mathrm{~m} \mathrm{NaCl}\), (c) \(75.0 \mathrm{~g}\) of an aqueous solution that is \(1.50 \%\) sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\) by mass.

Ascorbic acid (vitamin C, \(\left.\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{6}\right)\) is a water-soluble vitamin. A solution containing \(80.5 \mathrm{~g}\) of ascorbic acid dissolved in \(210 \mathrm{~g}\) of water has a density of \(1.22 \mathrm{~g} / \mathrm{mL}\) at \(55^{\circ} \mathrm{C}\). Calculate (a) the mass percentage, (b) the mole fraction, \((\mathbf{c})\) the molality, \((\mathbf{d})\) the molarity of ascorbic acid in this solution.

Calculate the number of moles of solute present in each of the following aqueous solutions: (a) \(750 \mathrm{~mL}\) of \(0.120 \mathrm{M}\) \(\operatorname{SrBr}_{2},(\mathbf{b}) 70.0 \mathrm{~g}\) of \(0.200 \mathrm{~m} \mathrm{KCl},(\mathbf{c}) 150.0 \mathrm{~g}\) of a solution that is \(5.75 \%\) glucose \(\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)\) by mass.

Indicate whether each statement is true or false: (a) A solute will dissolve in a solvent if solute-solute interactions are stronger than solute-solvent interactions. (b) In making a solution, the enthalpy of mixing is always a positive number. (c) An increase in entropy favors mixing.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.