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Water has a density of \(0.997 \mathrm{~g} / \mathrm{cm}^{3}\) at \(25^{\circ} \mathrm{C}\); ice has a density of \(0.917 \mathrm{~g} / \mathrm{cm}^{3}\) at \(-10^{\circ} \mathrm{C}\). (a) If a soft-drink bottle whose volume is \(1.50 \mathrm{~L}\) is completely filled with water and then frozen to \(-10^{\circ} \mathrm{C},\) what volume does the ice occupy? (b) Can the ice be contained within the bottle?

Short Answer

Expert verified
(a) The ice occupies a volume of \(1630.74 \, \text{cm}^3\). (b) No, the ice cannot be contained within the bottle as its volume is larger than the bottle's volume.

Step by step solution

01

Calculate the mass of the water

The volume of the soft-drink bottle is 1.50 L. First, convert the volume to cubic centimeters: \(1.50 \,\text{L} \times \frac{1000 \,\text{cm}^3}{1\,\text{L}} = 1500 \,\text{cm}^3\) Using the formula for density, which is, \(\text{density} = \frac{\text{mass}}{\text{volume}}\), we can calculate the mass of the water in the bottle: \(\text{mass}_{\text{water}} = \text{density}_{\text{water}} \times \text{volume}_{\text{water}}\) Where \(\text{density}_{\text{water}} = 0.997\frac{\text{g}}{\text{cm}^3}\) and \(\text{volume}_{\text{water}} = 1500 \,\text{cm}^3\) \(\text{mass}_{\text{water}}= (0.997\frac{\text{g}}{\text{cm}^3})(1500 \, \text{cm}^3) = 1495.50\, \text{g} \)
02

Calculate the volume of the ice

Now, we can calculate the volume of the ice that would be formed from this mass of water. Using the formula for density, we have: \(\text{volume}_{\text{ice}} = \frac{\text{mass}_{\text{water}}}{\text{density}_{\text{ice}}}\) Where \(\text{density}_{\text{ice}} = 0.917\frac{\text{g}}{\text{cm}^3}\) (Note: we use ice density since we're calculating ice volume) \(\text{volume}_{\text{ice}} = \frac{1495.50\,\text{g}}{0.917\frac{\text{g}}{\text{cm}^3}} = 1630.74 \, \text{cm}^3 \)
03

Compare the volume of the ice in the bottle

Now, let's compare the volume of the ice formed (\(1630.74 \, \text{cm}^3\)) to the volume of the bottle (\(1500 \, \text{cm}^3\)): \(1630.74 \, \text{cm}^3\) is larger than \(1500 \, \text{cm}^3\). This means that the volume of ice formed is greater than the volume of the bottle.
04

Answer

(a) The ice occupies a volume of \(1630.74 \, \text{cm}^3\). (b) No, the ice cannot be contained within the bottle as its volume is larger than the bottle's volume.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volume Calculation
Understanding volume calculations is a fundamental skill in dealing with various substances. In the case of our soft-drink bottle, knowing its volume is key to predicting how much space the contents occupy. The problem gives us a volume of 1.50 liters, which we convert to cubic centimeters (as it's standard in density calculations) using the conversion factor: 1 liter = 1000 cm³.

This gives us a total volume of 1500 cm³ for the container. Volume is the amount of space occupied by a substance, and in the context of this problem, it dictates whether the ice will fit within the bottle. By using these units, we lay the groundwork for comparing the substance's pre- and post-freezing states.
  • Volume calculations help determine spatial requirements.
  • Understanding unit conversions ensures accuracy in scientific calculations.
Phase Change
Phase change refers to the transformation from one state of matter to another, like when water turns into ice. This change takes place due to temperature or pressure alterations. In our problem, water at 25°C freezes to become ice at -10°C.

During a phase change, particularly from liquid to solid, the structure of molecules shifts. The density typically decreases as water molecules expand in ice formation, which affects volume. Recognizing phase changes is crucial as they explain how the physical properties such as volume and density impact each other when a substance transitions states.
  • Ice formation showcases a phase change from liquid to solid.
  • Phase change impacts the density and spatial occupation of the substance.
Water and Ice Properties
Water and ice, despite being different states of the same substance, have distinct properties. Water, at 25°C, has a density of 0.997 g/cm³, while ice, formed at -10°C, has a lower density of 0.917 g/cm³. The decreased density of ice is due to the unique hexagonal structure it forms in its solid state, making it less compact than liquid water.
This difference in density explains why ice floats on water and why it occupies more volume. In our example, the ice resulting from the frozen water can't fit back into the same space because of its increased volume.
Understanding these properties is vital in real-world scenarios where phase changes and volume calculations must be accurately anticipated. It also emphasizes why density is a critical factor in predicting behaviors of substances when they are exposed to temperature changes.
  • Ice's lower density causes it to expand and float.
  • Knowing the density assists in making predictions about substance behaviors post-freeze.

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Most popular questions from this chapter

A watt is a measure of power (the rate of energy change) equal to \(1 \mathrm{~J} / \mathrm{s}\). (a) Calculate the number of joules in a kilowatt- hour. (b) An adult person radiates heat to the surroundings at about the same rate as a 100 -watt electric incandescent light bulb. What is the total amount of energy in kcal radiated to the surroundings by an adult over a 24 h period?

(a) What is the mass of a silver cube whose edges measure 2.00 \(\mathrm{cm}\) each at \(25^{\circ} \mathrm{C} ?\) The density of silver is \(10.49 \mathrm{~g} / \mathrm{cm}^{3}\) at \(25^{\circ} \mathrm{C}\). (b) The density of aluminum is \(2.70 \mathrm{~g} / \mathrm{cm}^{3}\) at \(25^{\circ} \mathrm{C}\). What is the weight of the aluminum foil with an area of \(0.5 \mathrm{~m}^{2}\) and a thickness of \(0.5 \mathrm{~mm} ?\) (c) The density of hexane is \(0.655 \mathrm{~g} / \mathrm{mL}\) at \(25^{\circ} \mathrm{C} .\) Calculate the mass of \(1.5 \mathrm{~L}\) of hexane at this temperature.

Using your knowledge of metric units, English units, and the information on the back inside cover, write down the conversion factors needed to convert (a) in. to \(\mathrm{cm}(\mathbf{b}) \mathrm{lb}\) to \(\mathrm{g}\) (c) \(\mu g\) to \(g\) (d) \(\mathrm{ft}^{2}\) to \(\mathrm{cm}^{2}\).

(a) A bumblebee flies with a ground speed of \(15.2 \mathrm{~m} / \mathrm{s}\). Calculate its speed in \(\mathrm{km} / \mathrm{hr}\). (b) The lung capacity of the blue whale is \(5.0 \times 10^{3} \mathrm{~L}\). Convert this volume into gallons. (c) The Statue of Liberty is \(151 \mathrm{ft}\) tall. Calculate its height in meters. (d) Bamboo can grow up to \(60.0 \mathrm{~cm} /\) day, Convert this growth rate into inches per hour.

The distance from Earth to the Moon is approximately \(240,000 \mathrm{mi}\). (a) What is this distance in meters? (b) The peregrine falcon has been measured as traveling up to \(350 \mathrm{~km} /\) hr in a dive. If this falcon could fly to the Moon at this speed, how many seconds would it take? (c) The speed of light is \(3.00 \times 10^{8} \mathrm{~m} / \mathrm{s}\). How long does it take for light to travel from Earth to the Moon and back again? (d) Earth travels around the Sun at an average speed of \(29.783 \mathrm{~km} / \mathrm{s}\). Convert this speed to miles per hour.

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