/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 95 Consider the hypothetical molecu... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider the hypothetical molecule \(\mathrm{A}-\mathrm{A}=\mathrm{A}\) with a bent shape. Are the following statements true or false? (a) This molecule cannot exist. (b) If this molecule exists, it must possess an odd electron.

Short Answer

Expert verified
Statement (a) is false; statement (b) is false, based on lack of specific details.

Step by step solution

01

Understand Molecular Structure

The given molecule is hypothetically \(A-A=A\) with a bent shape. This suggests a triatomic structure where the central atom may be forming two single bonds with terminal atoms, one of which might be a double bond.
02

Analyze Statement (a)

Statement (a) claims that the molecule cannot exist. Consider classical triatomic molecules such as ozone (O3), which exist with a bent structure. Theoretical structures like \(A-A=A\) can exist if suitable elements are chosen for A, allowing for such bonding formations. Thus, the statement is false as we can't definitively conclude non-existence without specifics on A.
03

Analyze Statement (b)

Statement (b) suggests the molecule must possess an odd electron if it exists. A molecule with an odd number of total electrons often has unpaired electrons, resulting in radical species. However, whether \(A-A=A\) must have an odd electron depends on the electron configuration and bonding. Without specific details on valence electrons or bond types (e.g., radicals or resonance-stabilized structures), this statement cannot be validated and is potentially false.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Geometry
Molecular geometry is all about the shape that molecules make. It plays a crucial role in determining how molecules behave and interact. In the hypothetical molecule configuration of \(A-A=A\), the description of a 'bent shape' is important. A bent shape indicates that the atoms are not all in a straight line, but instead are angled, similar to the famous molecule water (Hâ‚‚O).
Molecular shapes are influenced by the Valence Shell Electron Pair Repulsion (VSEPR) theory. This theory helps predict the 3D arrangement of atoms. It states that electron pairs, whether bonding or non-bonding, repel each other. So, they adjust themselves as far apart as possible around a central atom to minimize repulsion. Thus, if a molecule like \(A-A=A\) has lone pairs around its middle atom, it might possess a bent geometry much like Hâ‚‚O.
For triatomic molecules, having a central atom with lone pairs can cause the bonding atoms to push closer together, resulting in a bent geometry. This shape greatly affects the molecule's properties like polarity, which in turn influences how it interacts with other molecules.
Bonding Theory
Bonding theory explains how atoms come together to form molecules and describes different types of chemical bonds. In the molecule \(A-A=A\), we might be dealing with single and double bonds, signifying different types of connectivity between atoms.
  • Single Bond: This involves a pair of shared electrons between two atoms. Single bonds allow for freedom of rotation around the bond axis.
  • Double Bond: Here, two pairs of electrons are shared. This bond is stronger and shorter than a single bond, offering less flexibility.
In the context of \(A-A=A\), bonding theory suggests the possibility of one single bond and one double bond with the central atom, creating a situation reminiscent of resonance structures as seen in ozone (O₃). This means that the distribution of electrons can be delocalized across the atoms, stabilizing the molecule.
Bonding pairs of electrons and lone pairs influence molecular geometry, as described by VSEPR theory. Furthermore, the presence of double or multiple bonds can affect the molecule's chemical reactivity and physical properties, which is essential to understand especially in hypothetical molecules like \(A-A=A\).
Electron Configuration
Electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. This concept is key in understanding how bonds form in molecules like \(A-A=A\).
Each atom has a unique electron configuration based on the number of electrons that occupy its orbitals. These configurations determine the potential for forming bonds and influence molecular geometry. For example, an atom might exist as a neutral entity with paired electrons or as a radical, possessing an unpaired electron, leading to unique bonding situations.
In the hypothetical molecule \(A-A=A\), without specific elements identified as A, we cannot definitively ascertain the molecule's electron configuration. However, it is vital to consider that if \(A\) has an odd number of electrons, the molecule's overall electron count can lead to radicals or unpaired electrons.
  • Paired Electrons: Usually result in stable molecules with no net magnetic dipole.
  • Unpaired Electrons: Can lead to paramagnetic systems often referred to as radical species.
Understanding how electrons are configured provides insights into molecular stability, potential reactivity, and other chemical properties. Thus, electron configuration is essential in evaluating the existence and nature of unconventional molecular structures like \(A-A=A\).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A major challenge in implementing the "hydrogen economy" is finding a safe, lightweight, and compact way of storing hydrogen for use as a fuel. The hydrides of light metals are attractive for hydrogen storage because they can store a high weight percentage of hydrogen in a small volume. For example, \(\mathrm{NaAlH}_{4}\) can release \(5.6 \%\) of its mass as \(\mathrm{H}_{2}\) upon decomposing to \(\mathrm{NaH}(s), \mathrm{Al}(s),\) and \(\mathrm{H}_{2}(g) . \mathrm{NaAlH}_{4}\) pos- sesses both covalent bonds, which hold polyatomic anions together, and ionic bonds. (a) Write a balanced equation for the decomposition of \(\mathrm{NaAlH}_{4}\). (b) Which element in \(\mathrm{NaAlH}_{4}\) is the most electronegative? Which one is the least electronegative? (c) Based on electronegativity differences, predict the identity of the polyatomic anion. Draw a Lewis structure for this ion. (d) What is the formal charge on hydrogen in the polyatomic ion?

Consider the formate ion, \(\mathrm{HCO}_{2}^{-}\), which is the anion formed when formic acid loses an \(\mathrm{H}^{+}\) ion. The \(\mathrm{H}\) and the two \(\mathrm{O}\) atoms are bonded to the central C atom. (a) Draw the best Lewis structure(s) for this ion. (b) Are resonance structures needed to describe the structure? (c) Would you predict that the \(\mathrm{C}-\mathrm{O}\) bond lengths in the formate ion would be longer or shorter relative to those in \(\mathrm{CO}_{2}\) ?

Which ionic compound is expected to form from combining the following pairs of elements? (a) calcium and nitrogen, (b) cesium and bromine, (c) strontium and sulfur, (d) aluminum and selenium.

By referring only to the periodic table, select \((\mathbf{a})\) the most electronegative element in group \(13 ;(\mathbf{b})\) the least electronegative element in the group As, Se and Br; (c) the most electronegative element in the group K, Mg, Al and In; (d) the element in the group \(\mathrm{Na}\), Be, \(\mathrm{Si}\), Ar, that is most likely to form an ionic compound with \(B \mathrm{r}\).

Arrange the bonds in each of the following sets in order of increasing polarity: \((\mathbf{a}) \mathrm{C}-\mathrm{F}, \mathrm{O}-\mathrm{F}, \mathrm{Be}-\mathrm{F} ;\) (b) \(\mathrm{O}-\mathrm{Cl}, \mathrm{S}-\mathrm{Br}, \mathrm{C}-\mathrm{P} ;(\mathbf{c}) \mathrm{C}-\mathrm{S}, \mathrm{B}-\mathrm{F}, \mathrm{N}-\mathrm{O}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.