/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Predict whether each of the foll... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Predict whether each of the following oxides is ionic or molecular: \(\mathrm{ZnO}, \mathrm{K}_{2} \mathrm{O}, \mathrm{SO}_{2}, \mathrm{OF}_{2}, \mathrm{TiO}_{2}\)

Short Answer

Expert verified
ZnO, Kâ‚‚O, and TiOâ‚‚ are ionic; SOâ‚‚ and OFâ‚‚ are molecular.

Step by step solution

01

Understanding Ionic vs. Molecular Oxides

Ionic oxides are formed when a metal from groups 1 or 2 in the periodic table bonds with oxygen. These oxides typically involve the transfer of electrons resulting in a bond between metal cations and oxygen anions. Molecular oxides, on the other hand, are formed by the sharing of electrons between non-metal atoms or transition metals and oxygen.
02

Analyze Each Compound

To determine whether each oxide is ionic or molecular, check the elements in each compound: - **ZnO**: Zinc is a transition metal; therefore, ZnO is likely more ionic. - **Kâ‚‚O**: Potassium is a Group 1 metal; thus Kâ‚‚O is ionic. - **SOâ‚‚**: Sulfur is a non-metal; hence SOâ‚‚ is molecular. - **OFâ‚‚**: Oxygen and Fluorine are both non-metals; thus OFâ‚‚ is molecular. - **TiOâ‚‚**: Titanium is a transition metal, so it forms compounds that are more ionic.
03

Conclusion

Based on the analysis of the elements involved: - ZnO is ionic. - Kâ‚‚O is ionic. - SOâ‚‚ is molecular. - OFâ‚‚ is molecular. - TiOâ‚‚ is ionic.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Compounds
Ionic compounds form through the transfer of electrons. Generally, this occurs between a metal and a non-metal. Metals from groups 1 and 2 on the periodic table, like sodium or potassium, often form ionic bonds when they react with non-metals, including oxygen. For example, in potassium oxide ( K_2O ), electrons from potassium atoms are transferred to oxygen atoms. This results in the formation of positively charged potassium ions and negatively charged oxide ions, held together by electrostatic forces.

Key characteristics of ionic compounds include their high melting and boiling points. This is due to the strong attraction between ions. They are usually soluble in water, and they conduct electricity when dissolved or in molten form.
  • Formation: Metal + Non-metal
  • Electron transfer creating ions
  • High melting and boiling points
  • Conduct electricity in solution
Molecular Compounds
Molecular compounds are formed when two or more non-metal atoms share electrons. Unlike ionic compounds, no electron transfer occurs here. Instead, atoms bond together by sharing pairs of electrons, leading to the formation of molecules. A typical example is sulfur dioxide ( SO_2 ), where sulfur and oxygen atoms share electrons.

Molecular compounds often have lower melting and boiling points compared to ionic compounds, because the forces holding molecules together are generally weaker than ionic bonds. They are typically poor conductors of electricity because they do not form ions when dissolved in water.
  • Formation: Non-metal + Non-metal
  • Sharing of electrons
  • Lower melting and boiling points
  • Poor conductors of electricity
Periodic Table
The periodic table is a powerful tool for understanding chemical bonding. It organizes elements by increasing atomic number and groups them based on similar chemical properties. Elements are categorized into groups (vertical columns) and periods (horizontal rows).

Groups 1 and 2 include alkali and alkaline earth metals respectively, which commonly form ionic bonds. Groups 16 and 17 typically involve in forming molecular compounds as they contain non-metals like oxygen and fluorine. Transition metals, found in groups 3 through 12, can form either type of bond, becoming more complex in their chemistry.

Understanding group trends helps predict the behavior of unknown compounds. For example, knowing potassium ( K ) belongs to group 1 (alkali metals) helps predict it tends to form ionic compounds.
  • Groups: Vertical columns
  • Periods: Horizontal rows
  • Helps predict bonding types
  • Shows trends in reactivity
Transition Metals
Transition metals are elements found in the d-block of the periodic table and include metals like zinc ( Zn ) and titanium ( Ti ). These metals can form both ionic and covalent bonds. Transition metals exhibit variable oxidation states, which means they can lose different numbers of electrons depending on the chemical environment.

In the case of zinc oxide ( ZnO ) and titanium dioxide ( TiO_2 ), these metals often behave more ionically. This is due to their ability to form stable oxidation states when they lose electrons.

Transition metals are renowned for their vibrant colors and multiple oxidation states, making them crucial in forming complex compounds.
  • D-block elements
  • Variable oxidation states
  • Form both ionic and covalent bonds
  • Known for vibrant colors in compounds

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write equations that show the processes that describe the first, second, and third ionization energies of a chlorine atom. Which process would require the least amount of energy?

Provide a brief explanation for each of the following: \((\mathbf{a}) \mathrm{Cl}^{-}\) is larger than Ar. (b) \(\mathrm{P}^{3-}\) is larger than \(\mathrm{S}^{2-}\). (c) \(\mathrm{K}^{+}\) is larger than \(\mathrm{Na}^{+} .(\mathbf{d}) \mathrm{F}^{-}\) is larger than \(\mathrm{F}\).

(a) What is the general relationship between the size of an atom and its first ionization energy? (b) Which element in the periodic table has the largest ionization energy? Which has the smallest?

Hydrogen is an unusual element because it behaves in some ways like the alkali metal elements and in other ways like nonmetals. Its properties can be explained in part by its electron configuration and by the values for its ionization energy and electron affinity. (a) Explain why the electron affinity of hydrogen is much closer to the values for the alkali elements than for the halogens. (b) Is the following statement true? "Hydrogen has the smallest bonding atomic radius of any element that forms chemical compounds." If not, correct it. If it is, explain in terms of electron configurations. (c) Explain why the ionization energy of hydrogen is closer to the values for the halogens than for the alkali metals. (d) The hydride ion is \(\mathrm{H}^{-}\). Write out the process corresponding to the first ionization energy of the hydride ion. (e) How does the process in part (d) compare to the process for the electron affinity of a neutral hydrogen atom?

Give examples of transition metal ions with +3 charge that have an electron configuration of \(n d^{5}(n=3,4,5 \ldots)\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.