/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Give three examples of +2 ions t... [FREE SOLUTION] | 91Ó°ÊÓ

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Give three examples of +2 ions that have an electron configuration of \(n d^{10}(n=3,4,5 \ldots)\).

Short Answer

Expert verified
Examples: \(Zn^{2+}\), \(Cd^{2+}\), \(Hg^{2+}\).

Step by step solution

01

Understand the Problem

We need to find three ions with a +2 charge that achieves the electron configuration of a completely filled d-orbital, specifically denoted by \(nd^{10}\). The subscript \(n\) represents the principal quantum number denoting energy levels beyond 3.
02

Identify Elements with Filled D-Subshells

Elements that typically end in \(d^{10}\) configurations are the group 12 transition metals: Zinc (Zn), Cadmium (Cd), and Mercury (Hg). These elements naturally end with a \(d^{10}\) configuration because they fill their d-orbitals completely in their neutral state as Zn:\([Ar] 3d^{10} 4s^2\), Cd: \([Kr] 4d^{10} 5s^2\), and Hg: \([Xe] 4f^{14} 5d^{10} 6s^2\).
03

Form Their +2 Ions

Upon forming a +2 ion, these elements lose two electrons usually from the s-orbital. This results in \(Zn^{2+}\), \(Cd^{2+}\), and \(Hg^{2+}\) all of whom have the electron configurations: Zn: \([Ar] 3d^{10}\), Cd: \([Kr] 4d^{10}\), Hg: \([Xe] 4f^{14} 5d^{10}\). In each +2 state, the \(d\)-orbital remains completely filled.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Electron configuration is an essential concept in chemistry. It defines how electrons are arranged in an atom or ion. Electrons fill available energy levels around the nucleus from lower to higher energies. This order follows the Aufbau principle.

The s, p, d, and f orbitals represent different energy levels and sublevels. Each orbital type has a specific capacity for holding electrons:
  • s-orbital: can hold up to 2 electrons.
  • p-orbital: can hold up to 6 electrons.
  • d-orbital: can hold up to 10 electrons.
  • f-orbital: can hold up to 14 electrons.
In transition metals, the electron configuration gets intriguing. For example, in an atom like zinc (Zn), you first fill the 4s orbital before the 3d orbital. However, when forming positive ions, electrons are often removed from the s-orbital first. This is why a zinc ion ( Zn^{2+} ) ends with a 3d configuration.
D-Orbital
The d-orbital plays a crucial role in transition metals. It is responsible for some of their unique properties, such as high melting and boiling points, as well as their ability to form brightly colored compounds.

A single d-orbital can hold a maximum of 10 electrons, which leads to different electron configurations based on the number of electrons they actually contain.

When a transition metal forms an ion, typically, it will lose electrons from an outer s-orbital first, which keeps the d-orbital fully or partially filled. Having a filled d-orbital can stabilize the ion because lower energy configurations are more stable. An example of this is seen in the group 12 metal ions like Zn^{2+} or Hg^{2+}, which maintains a filled d subshell by the loss of outer shell s electrons.
Group 12 Elements
Group 12 elements are a special set of transition metals. These include Zinc (Zn), Cadmium (Cd), and Mercury (Hg). They lie in the d-block of the periodic table and are known for having a fully filled d orbital even in their elemental forms.

These metals have unique properties:
  • They are typically not very reactive compared to other transition metals.
  • They generally form stable +2 oxidation states.
  • They have practical uses in industries - for example, mercury in thermometers and zinc for galvanizing to prevent corrosion.
The neutral atoms of Zn, Cd, and Hg have the electron configurations closing in a filled d-orbital: Zn is [Ar] 3d^{10} 4s^{2}, Cd is [Kr] 4d^{10} 5s^{2}, and Hg is [Xe] 4f^{14} 5d^{10} 6s^{2}. Upon ionization to Zn^{2+}, Cd^{2+}, and Hg^{2+}, they lose their s electrons but maintain totally filled d orbitals. This keeps their configurations stable, making these ions unique and predictable in chemical reactions.

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Most popular questions from this chapter

Tungsten has the highest melting point of any metal in the periodic table: \(3422^{\circ} \mathrm{C}\). The distance between \(\mathrm{W}\) atoms in tungsten metal is \(274 \mathrm{pm}\). (a) What is the atomic radius of a tungsten atom in this environment? (This radius is called the metallic radius.) (b) If you put tungsten metal under high pressure, predict what would happen to the distance between \(\mathrm{W}\) atoms.

Consider the stable elements through lead \((Z=82) .\) In how many instances are the atomic weights of the elements out of order relative to the atomic numbers of the elements?

Write the electron configurations for the following ions, and determine which have noble-gas configurations: (a) \(\mathrm{Cu}^{2+}\), (b) \(\mathrm{Ca}^{2+},(\mathbf{c}) \mathrm{N}^{3-}\), (d) \(\mathrm{Ru}^{2+}\), (e) \(\mathrm{H}^{-}\).

Write balanced equations for the following reactions: (a) sulfur dioxide with water, (b) lithium oxide in water, \((\mathbf{c})\) zinc oxide with dilute hydrochloric acid, \((\mathbf{d})\) arsenic trioxide with aqueous potassium hydroxide.

The electron affinities, in \(\mathrm{kJ} / \mathrm{mol}\), for the group 11 and group 12 metals are as follows: $$ \begin{array}{|c|l|} \hline \mathrm{Cu} & \mathrm{Zn} \\ -119 & >0 \\ \hline \mathrm{Ag} & \mathrm{Cd} \\ -126 & >0 \\ \hline \mathrm{Au} & \mathrm{Hg} \\ -223 & >0 \\ \hline \end{array} $$ (a) Why are the electron affinities of the group 12 elements greater than zero? (b) Why do the electron affinities of the group 11 elements become more negative as we move down the group?

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