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Write "true" or "false" for each statement. (a) We balance chemical equations as we do because energy must be conserved. (b) If the reaction \(2 \mathrm{O}_{3}(g) \rightarrow 3 \mathrm{O}_{2}(g)\) goes to completion and all \(\mathrm{O}_{3}\) is converted to \(\mathrm{O}_{2}\), then the mass of \(\mathrm{O}_{3}\) at the beginning of the reaction must be the same as the mass of \(\mathrm{O}_{2}\) at the end of the reaction. (c) You can balance the "water-splitting" reaction \(\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)\) by writing it this way: \(\mathrm{H}_{2} \mathrm{O}_{2}(l) \rightarrow \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)\).

Short Answer

Expert verified
(a) False, (b) True, (c) False.

Step by step solution

01

Evaluate Statement (a)

This statement claims we balance chemical equations to conserve energy. In fact, the primary reason for balancing chemical equations is to obey the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. Although energy conservation is important, it is not the principal reason chemical equations are balanced. Hence, statement (a) is false.
02

Evaluate Statement (b)

This statement considers the mass of reactants and products before and after a reaction. The law of conservation of mass states that the mass of the reactants must equal the mass of the products in a chemical reaction. Thus, if all \( \mathrm{O}_3 \) is converted to \( \mathrm{O}_2 \), their masses must be equal. Hence, statement (b) is true.
03

Evaluate Statement (c)

This statement provides an incorrect way of balancing the water-splitting reaction. The correct decomposition of water \( \mathrm{H}_2 \mathrm{O} \) into \( \mathrm{H}_2 \) and \( \mathrm{O}_2 \) involves writing \( 2 \mathrm{H}_2 \mathrm{O}(l) \rightarrow 2 \mathrm{H}_2(g) + \mathrm{O}_2(g) \). Writing it with \( \mathrm{H}_2 \mathrm{O}_2 \) is incorrect, as this changes the substance involved in the reaction. Hence, statement (c) is false.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Mass
The law of conservation of mass is a fundamental principle in chemistry. This law asserts that during a chemical reaction, matter is not created or destroyed. Rather, it changes form. This means that the total mass of the reactants (the starting substances) must equal the mass of the products (the substances formed) in a chemical reaction.
For example, if you begin with 10 grams of reactants, you should have 10 grams of products after the reaction is complete. This concept is crucial because it ensures that atomic matter is accounted for at all stages of a chemical reaction.
Understanding this principle allows chemists to predict the amounts of products that will be generated from given reactants. It also enables chemists to ensure that chemical equations are accurately representative of what occurs in the real world. Remember, no atoms are lost; they are merely rearranged.
Balancing Chemical Equations
Balancing chemical equations is an essential skill in chemistry. The fundamental purpose is to reflect the law of conservation of mass. In a balanced chemical equation, the number of atoms for each element is the same on both sides of the equation. This ensures that matter is conserved throughout the chemical process.
To balance an equation, one often starts by writing the unbalanced equation based on the reactants and products of the reaction. Then, we adjust the coefficients (the numbers before the molecules) to make sure that each type of atom has the same quantity on both sides.
The coefficients represent the relative number of moles of a substance. By mastering balancing equations, students gain deeper insights into the stoichiometry and relationships between reactants and products. A balanced equation provides valuable information, such as the proportions of reactants needed and the amount of product that can be formed.
Chemical Equation Representation
Chemical equations are vital tools in representing chemical reactions. They provide a concise way of showing which substances react and what they transform into during the reaction.
A chemical equation consists of reactants on the left, products on the right, and an arrow pointing from reactants to products to show the direction of the reaction. For example, in the reaction \( 2 \mathrm{H}_2 + \mathrm{O}_2 \rightarrow 2 \mathrm{H}_2 \mathrm{O} \), hydrogen and oxygen are reactants, and water is the product.
Chemical equations must be correctly written and balanced to accurately reflect the law of conservation of mass. In some cases, additional symbols may be used to show the state of the substances, such as (s) for solids, (l) for liquids, (g) for gases, and (aq) for aqueous solutions. By understanding chemical equation representation, one can predict the outcomes of reactions and ensure that they are both feasible and accurately understood.

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Most popular questions from this chapter

Several brands of antacids use \(\mathrm{Al}(\mathrm{OH})_{3}\) to react with stomach acid, which contains primarily HCl: $$ \mathrm{Al}(\mathrm{OH})_{3}(s)+\mathrm{HCl}(a q) \longrightarrow \mathrm{AlCl}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l) $$ (a) Balance this equation. (b) Calculate the number of grams of HCl that can react with \(0.500 \mathrm{~g}\) of \(\mathrm{Al}(\mathrm{OH})_{3}\) (c) Calculate the number of grams of \(\mathrm{AlCl}_{3}\) and the number of grams of \(\mathrm{H}_{2} \mathrm{O}\) formed when \(0.500 \mathrm{~g}\) of \(\mathrm{Al}(\mathrm{OH})_{3}\) reacts. (d) Show that your calculations in parts (b) and (c) are consistent with the law of conservation of mass.

(a) Write "true" or "false" for each statement. (a) A mole of ducks contain a mole of feathers. (b) A mole of ammonia gas has a mass of 17.0 g. \((\mathbf{c})\) The mass of 1 ammonia molecule is 17.0 g. (d) A mole of \(\mathrm{MgSO}_{4}(s)\) contains 4 moles of oxygen atoms.

The fizz produced when an Alka-Seltzer tablet is dissolved in water is due to the reaction between sodium bicarbonate \(\left(\mathrm{NaHCO}_{3}\right)\) and citric acid \(\left(\mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}\right)\) $$ \begin{aligned} 3 \mathrm{NaHCO}_{3}(a q)+\mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}(a q) & \longrightarrow \\ & 3 \mathrm{CO}_{2}(g)+3 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Na}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}(a q) \end{aligned} $$ In a certain experiment \(1.00 \mathrm{~g}\) of sodium bicarbonate and \(1.00 \mathrm{~g}\) of citric acid are allowed to react.(a) Which is the limiting reactant? (b) How many grams of carbon dioxide form? (c) How many grams of the excess reactant remain after the limiting reactant is completely consumed?

Write a balanced chemical equation for the reaction that occurs when (a) titanium metal reacts with \(\mathrm{O}_{2}(g) ;(\mathbf{b})\) silver(I) oxide decomposes into silver metal and oxygen gas when heated; \((\mathbf{c})\) propanol, \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}(l)\) burns in air;(d) methyl tert-butyl ether, \(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}(l),\) burns in air.

Boron nitride, \(\mathrm{BN},\) is an electrical insulator with remarkable thermal and chemical stability. Its density is \(2.1 \mathrm{~g} / \mathrm{cm}^{3} .\) It can be made by reacting boric acid, \(\mathrm{H}_{3} \mathrm{BO}_{3}\), with ammonia. The other product of the reaction is water. (a) Write a balanced chemical equation for the synthesis of BN. (b) If you made \(225 \mathrm{~g}\) of boric acid react with \(150 \mathrm{~g}\) ammonia, what mass of BN could you make? (c) Which reactant, if any, would be left over, and how many moles of leftover reactant would remain? (d) One application of \(\mathrm{BN}\) is as thin film for electrical insulation. If you take the mass of BN from part (a) and make a \(0.4 \mathrm{~mm}\) thin film from it, what area, in \(\mathrm{cm}^{2}\), would it cover?

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