Chapter 3: Problem 25
Calculate the percentage by mass of oxygen in the following compounds: (a) vanillin, \(\mathrm{C}_{8} \mathrm{H}_{8} \mathrm{O}_{3} ;(\mathbf{b})\) isopropyl alcohol, \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\); (c) acetaminophen, \(\mathrm{C}_{8} \mathrm{H}_{9} \mathrm{NO}_{2}\); (d) cyclopropanone, \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O} ;\) (e) dioxin, \(\mathrm{C}_{12} \mathrm{H}_{4} \mathrm{Cl}_{4} \mathrm{O}_{2} ;(\mathbf{f})\) penicillin, \(\mathrm{C}_{16} \mathrm{H}_{18} \mathrm{~N}_{2} \mathrm{O}_{4} \mathrm{~S}\).
Short Answer
Step by step solution
Understand the Formula for Mass Percentage
Calculate Molar Mass of Vanillin, \(\mathrm{C}_{8} \mathrm{H}_{8} \mathrm{O}_{3}\)
Calculate Oxygen Percentage in Vanillin
Calculate Molar Mass of Isopropyl Alcohol, \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\)
Calculate Oxygen Percentage in Isopropyl Alcohol
Calculate Molar Mass of Acetaminophen, \(\mathrm{C}_{8} \mathrm{H}_{9} \mathrm{NO}_{2}\)
Calculate Oxygen Percentage in Acetaminophen
Calculate Molar Mass of Cyclopropanone, \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\)
Calculate Oxygen Percentage in Cyclopropanone
Calculate Molar Mass of Dioxin, \(\mathrm{C}_{12} \mathrm{H}_{4} \mathrm{Cl}_{4} \mathrm{O}_{2}\)
Calculate Oxygen Percentage in Dioxin
Calculate Molar Mass of Penicillin, \(\mathrm{C}_{16} \mathrm{H}_{18} \mathrm{N}_{2} \mathrm{O}_{4} \mathrm{S}\)
Calculate Oxygen Percentage in Penicillin
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Percentage by Mass
- \[\text{Percentage by mass of element} = \left( \frac{\text{Mass of the element in 1 mole of compound}}{\text{Molar mass of compound}} \right) \times 100\]
Chemical Compounds
- Vanillin, for instance, is composed of carbon, hydrogen, and oxygen.
- Each compound has a distinct formula, like \( \mathrm{C}_{8} \mathrm{H}_{8} \mathrm{O}_{3} \) for vanillin, denoting how many atoms of each element exists in it.
- The elements in these compounds are often held together by covalent or ionic bonds.
Oxygen Contribution
- The compound has 3 oxygen atoms, each weighing about 16.00 g/mol.
- The collective weight of oxygen in the compound is thus \( 3 \times 16.00 \text{ g} = 48.00 \text{ g} \).
- This is then divided by the entire compound's molar mass (152.15 g/mol for vanillin) and multiplied by 100 to find the percentage.
- Thus, the oxygen contributes significantly, for example, 31.56% by mass for vanillin.