/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Determine if each of the followi... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine if each of the following metal complexes is chiral and therefore has an optical isomer: (a) square planar \(\left[\mathrm{Pd}(\mathrm{en})(\mathrm{CN})_{2}\right],(\mathbf{b})\) octahedral \(\left[\mathrm{Ni}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) (c) octahedral \(c i s-\left[\mathrm{V}(\mathrm{en})_{2} \mathrm{ClBr}\right] .\)

Short Answer

Expert verified
(a) not chiral, (b) not chiral, (c) chiral and has an optical isomer.

Step by step solution

01

Understanding Chirality in Metal Complexes

A metal complex is considered chiral if it lacks an internal plane of symmetry and cannot be superimposed on its mirror image.
02

Analyze Square Planar Structure (Part a)

The complex \([\mathrm{Pd}(\mathrm{en})(\mathrm{CN})_{2}]\) is square planar. In square planar complexes, all four ligands lie in the same plane. Typically, these structures do not exhibit chirality because they are symmetric and have a plane of symmetry.
03

Analyze Octahedral Structure (Part b)

The complex \([\mathrm{Ni}(\mathrm{en})(\mathrm{NH}_{3})_{4}]^{2+}\) is octahedral. The ethylenediamine (\(\mathrm{en}\)) ligand can, in theory, introduce chirality. However, the presence of four equivalent \(\mathrm{NH}_{3}\) ligands provides a plane of symmetry, suggesting the complex is achiral.
04

Analyze Octahedral Structure with Different Ligands (Part c)

The complex \(cis-[\mathrm{V}(\mathrm{en})_{2}\mathrm{ClBr}]\) is also octahedral. Here, the bidentate \(\mathrm{en}\) ligands and the different unidentate ligands (\(\mathrm{Cl}\) and \(\mathrm{Br}\)) diminish the symmetry, potentially leading to a chiral center. The use of these different ligands makes it difficult to superimpose the complex on its mirror image, thus making it chiral and optically active.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Optical Isomerism
Optical isomerism, in the realm of chemistry, is a form of stereoisomerism that relates to the spatial arrangement of molecules. When a molecule can exist in two forms that are mirror images of each other and cannot be superimposed, it exhibits optical isomerism. Such molecules are known as enantiomers. For a molecule to be optically active, it must not have a plane of symmetry or a center of symmetry, making it chiral.
Chirality is particularly significant in metal complexes, as some can rotate plane-polarized light. This property is used to distinguish between the two enantiomers. The difference might seem subtle initially but is crucial in applications such as pharmaceutical chemistry, where the chirality of a compound can influence its biological activity. Optical isomerism plays a vital role in determining the properties and functions of these compounds.
Square Planar Complexes
Square planar complexes are one of the key structural types found in coordination chemistry. In these complexes, the metal ion is at the center of a square plane with ligands positioned at the corners of the square. This planar geometry creates a distinct configuration but typically lacks chirality.
The reason square planar complexes are usually not chiral is due to their symmetrical nature. They have a plane of symmetry passing through the metal and opposite ligands, making any superimposable attempts on their mirror images feasible. A classic example is the \([\mathrm{Pd}(\mathrm{en})(\mathrm{CN})_{2}]\) complex. Since the ligands can be rotated and still align with their mirror image, the complex is achiral. Understanding the symmetry and structure of square planar complexes is essential when evaluating their chemical and physical behavior.
Octahedral Complexes
Octahedral complexes are another fundamental geometry encountered in coordination compounds. These complexes consist of a central metal atom surrounded by six ligands positioned at the vertices of an octahedron. The spatial arrangement of these ligands can lead to various structural isomers, some of which may be chiral.
In octahedral complexes like \([\mathrm{Ni}(\mathrm{en})(\mathrm{NH}_{3})_{4}]^{2+}\), the presence of symmetrical ligands often results in a plane of symmetry, making the complex achiral. However, complexes such as \([\mathrm{V}(\mathrm{en})_{2}ClBr]\) become chiral due to the arrangement of non-equivalent ligands. The presence of different ligands like Cl and Br disrupts symmetry, potentially causing the complex to lack a plane of symmetry and consequently exhibit optical activity. These differences highlight the significance of ligand arrangement in determining the chiral properties of octahedral complexes.
Symmetry in Chemistry
Symmetry is a concept woven deeply into the fabric of chemistry, influencing the structure, reactivity, and properties of molecules. It describes the balanced distribution of equivalent parts in a chemical structure. In terms of geometry, various elements of symmetry include:
  • Planes of symmetry: A geometric plane that bisects a molecule into two mirror-image halves.
  • Centers of symmetry: A central point from which, for each atom in the molecule, a mirror image exists directly opposite.
  • Axes of symmetry: Lines around which a rotation by certain angles results in an indistinguishable configuration.
Chirality in chemistry is often the result of the absence of these symmetrical elements, particularly planes and centers of symmetry. Achiral molecules possess symmetry elements and are generally optically inactive. Identifying symmetry elements helps predict whether a molecule can exist as enantiomers. These insights are invaluable in predicting and explaining the behavior and interaction of chemical species in various chemical and biological processes.

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Most popular questions from this chapter

Metallic elements are essential components of many important enzymes operating within our bodies. Carbonic anhydrase, which contains \(\mathrm{Zn}^{2+}\) in its active site, is responsible for rapidly interconverting dissolved \(\mathrm{CO}_{2}\) and bicarbonate ion, \(\mathrm{HCO}_{3}^{-}\). The zinc in carbonic anhydrase is tetrahedrally coordinated by three neutral nitrogencontaining groups and a water molecule. The coordinated water molecule has a p \(K_{a}\) of \(7.5,\) which is crucial for the enzyme's activity. (a) Draw the active site geometry for the \(\mathrm{Zn}(\mathrm{II})\) center in carbonic anhydrase, just writing "N" for the three neutral nitrogen ligands from the protein. (b) Compare the \(\mathrm{p} K_{a}\) of carbonic anhydrase's active site with that of pure water; which species is more acidic? (c) When the coordinated water to the \(\mathrm{Zn}(\mathrm{II})\) center in carbonic anhydrase is deprotonated, what ligands are bound to the \(\mathrm{Zn}(\mathrm{II})\) center? Assume the three nitrogen ligands are unaffected. (d) The \(\mathrm{pK}_{a}\) of \(\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) is \(10 .\) Suggest an explanation for the difference between this \(\mathrm{pK}_{a}\) and that of carbonic anhydrase. (e) Would you expect carbonic anhydrase to have a deep color, like hemoglobin and other metal-ion- containing proteins do? Explain.

Consider the following three complexes: \(\left(\right.\) Complex 1) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{Cl}\) \(\left(\right.\) Complex 2) \(\left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{ONO})_{2}\right]\) \(\left(\right.\) Complex 3) \(\left[\mathrm{V}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+},\) (a) geometric isomers, Which of the three complexes can have (b) linkage isomers, (d) coordination- (c) optical isomers, sphere isomers?

Indicate the coordination number and the oxidation number of the metal for each of the following complexes: (a) \(\mathrm{K}_{2} \mathrm{PtCl}_{4}\) (b) \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right] \mathrm{Br}_{2}\) (c) \(\mathrm{OsO}_{4}\) (d) \(\left[\mathrm{Mn}(\mathrm{en})_{3}\right]\left(\mathrm{NO}_{3}\right)_{2}\) (e) \(\left[\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{3}\) (f) \(\left[\mathrm{Zn}(\mathrm{bipy})_{2}\right]\left(\mathrm{ClO}_{4}\right)_{2}\)

Carbon monoxide, CO, is an important ligand in coordination chemistry. When CO is reacted with nickel metal, the product is \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right],\) which is a toxic, pale yellow liquid. (a) What is the oxidation number for nickel in this compound? (b) Given that \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) is a diamagnetic molecule with a tetrahedral geometry, what is the electron configuration of nickel in this compound? (c) Write the name for \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) using the nomenclature rules for coordination compounds.

The colors in the copper-containing minerals malachite, which is green and has an empirical formula of \(\mathrm{Cu}_{2} \mathrm{CO}_{3}\) \((\mathrm{OH})_{2},\) and azurite, which is blue and has an empirical formula of \(\mathrm{Cu}_{3}\left(\mathrm{CO}_{3}\right)_{2}(\mathrm{OH})_{2},\) come from a single \(d-d\) transition in each compound. The compounds are sometimes found together in nature as shown here. (a) What is the electron configuration of the copper ion in each mineral? (b) Based on their colors, in which compound would you predict the crystal-field splitting \(\Delta\) is larger?

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