Chapter 23: Problem 40
Consider the following three complexes: (Complex 1) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SCN}\right]^{2+}\) 2) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right]^{2+}\) (Complex \(\left(\right.\) Complex 3) \(\mathrm{CoClBr} \cdot 5 \mathrm{NH}_{3}\) Which of the three complexes can have (a) geometric isomers, (b) linkage isomers, (c) optical isomers, (d) coordination-sphere isomers?
Short Answer
Step by step solution
Understanding Complexes
Identify Geometric Isomers
Identify Linkage Isomers
Identify Optical Isomers
Identify Coordination-Sphere Isomers
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Isomerism
In the given complexes, the \[\text{[Co(NH}_3)_3\text{Cl}_3]^{2+}\] complex can exhibit geometric isomerism because it has three ammonia (\[\text{NH}_3\] ) and three chloride (\[\text{Cl}^-\] ) ligands that can arrange in facial or meridional formations.
Facial (fac) isomers have three identical ligands occupying one face of the octahedron, while meridional (mer) isomers have them in a plane passing through the octahedron.
On the other hand, \[\text{[Co(NH}_3)_5\text{SCN}]^{2+}\] has five \[\text{NH}_3\] ligands and one thiocyanate (\[\text{SCN}^-\] ), showing less potential for geometric variety.
Complex \(\text{CoClBr} \cdot 5\text{NH}_3\) is less likely to have distinct geometric isomers due to an unclear structure and less symmetry.
Linkage Isomerism
A classic example is the thiocyanate ion (\[\text{SCN}^-\]), which can bind through either the sulfur (\[\text{S}\] ) atom, termed thiocyanato, or through the nitrogen (\[\text{N}\] ) atom, termed isothiocyanato.
In the provided complexes, only \[\text{[Co(NH}_3)_5\text{SCN}]^{2+}\] is capable of showing linkage isomerism. This is because of the versatile binding nature of \[\text{SCN}^-\] .
The other complexes like \(\text{[Co(NH}_3)_3 \text{Cl}_3]^{2+}\) and \(\text{CoClBr} \cdot 5\text{NH}_3\) do not demonstrate linkage isomerism since their ligands (\[\text{Cl}^-\] and \[\text{Br}^-\] ) are monodentate and cannot reconfigure in such a manner.
Optical Isomerism
In coordination complexes, optical isomers (enantiomers) are common when bidentate ligands create a chiral environment around the metal center. For instance, an octahedral complex with three bidentate ligands, such as ethylenediamine, can become chiral.
The complex \[\text{[Co(NH}_3)_5\text{SCN}]^{2+}\] could potentially form optical isomers if its configuration is suitably asymmetric. However, due to its simpler ligand structure, this is rare. \[\text{[Co(NH}_3)_3 \text{Cl}_3]^{2+}\] is less likely to exhibit optical isomerism due to potential possession of internal symmetry.
Similarly, \(\text{CoClBr} \cdot 5\text{NH}_3\) would not exhibit optical isomerism without a more complex chiral setup, which is not apparent from its described formula.
Coordination-Sphere Isomerism
This type of isomerism is more about how ligands are positioned relative to the complex rather than within the coordination sphere itself.
For the complexes given, only \(\text{CoClBr} \cdot 5\text{NH}_3\) suggests a potential for coordination-sphere isomers. This is because its formulation indicates the possibility of ligand interchange between the inner and outer coordination sphere.
Meanwhile, \[\text{[Co(NH}_3)_5\text{SCN}]^{2+}\] and \[\text{[Co(NH}_3)_3 \text{Cl}_3]^{2+}\] do not offer coordination-sphere isomer possibilities as they do not possess distinctly bound external ligands that could alter this arrangement.