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Complete and balance the following equations: (a) \(\mathrm{CaO}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\) (b) \(\mathrm{Al}_{2} \mathrm{O}_{3}(s)+\mathrm{H}^{+}(a q) \longrightarrow\) (c) \(\mathrm{Na}_{2} \mathrm{O}_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\) (d) \(\mathrm{N}_{2} \mathrm{O}_{3}(g)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\) (e) \(\mathrm{KO}_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\) (f) \(\mathrm{NO}(g)+\mathrm{O}_{3}(g) \longrightarrow\)

Short Answer

Expert verified
(a) \(\mathrm{Ca(OH)_{2}}\), (b) \(2\mathrm{Al^{3+}} + 3\mathrm{H}_{2} \mathrm{O}\), (c) \(2\mathrm{NaOH} + \mathrm{O}_{2}\), (d) \(2\mathrm{HNO}_{2}\), (e) \(4\mathrm{KOH} + 3\mathrm{O}_{2}\), (f) \(\mathrm{NO}_{2} + \mathrm{O}_{2}\).

Step by step solution

01

Complete Reaction (a)

The reaction involves water and calcium oxide, a combination that typically results in calcium hydroxide. Thus, the complete reaction is: \[\mathrm{CaO}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{Ca(OH)_{2}}(s)\] The equation is already balanced.
02

Complete Reaction (b)

Aluminum oxide reacts with hydrogen ions (protons) to form water and aluminum ions in water. This is an acid-base reaction, resulting in: \[\mathrm{Al}_{2} \mathrm{O}_{3}(s) + 6\mathrm{H}^{+}(aq) \longrightarrow 2\mathrm{Al}^{3+}(aq) + 3\mathrm{H}_{2} \mathrm{O}(l)\] Ensure both sides of the equation are balanced.
03

Complete Reaction (c)

When sodium peroxide reacts with water, it forms sodium hydroxide and releases oxygen gas:\[\mathrm{Na}_{2} \mathrm{O}_{2}(s) + 2\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2\mathrm{NaOH}(aq) + \mathrm{O}_{2}(g)\] This equation is balanced based on hydrogen, oxygen, and sodium atoms.
04

Complete Reaction (d)

The reaction of dinitrogen trioxide with water generally forms nitrous acid:\[\mathrm{N}_{2} \mathrm{O}_{3}(g) + \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2\mathrm{HNO}_{2}(aq)\] Both the reactants and products are balanced for nitrogen, hydrogen, and oxygen atoms.
05

Complete Reaction (e)

Potassium superoxide reacts with water to produce potassium hydroxide, hydrogen peroxide, and oxygen gas:\[4\mathrm{KO}_{2}(s) + 2\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 4\mathrm{KOH}(aq) + 3\mathrm{O}_{2}(g) \] Both the reactant and product sides are balanced regarding atoms.
06

Complete Reaction (f)

Nitric oxide reacts with ozone to form nitrogen dioxide and oxygen. The balanced equation is:\[\mathrm{NO}(g) + \mathrm{O}_{3}(g) \longrightarrow \mathrm{NO}_{2}(g) + \mathrm{O}_{2}(g)\] All elements (nitrogen and oxygen) are balanced in this equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is like the recipe for chemical reactions. It tells us the quantity of each substance needed or produced in a reaction. When baking cookies, following the recipe precisely gives the best results. Similarly, stoichiometry ensures chemical reactions happen as expected by maintaining the right balance between reactants and products.

The foundation of stoichiometry lies in the law of conservation of mass. This principle states that mass is neither created nor destroyed in a chemical reaction. Thus, the mass of reactants must equal the mass of products. Stoichiometry helps in balancing chemical equations to respect this law.

In balanced equations, coefficients (numbers before molecules) show the molar ratio of reactants and products. In reaction (c), for example, sodium peroxide and water combine in a precise 1:2 mole ratio to form sodium hydroxide and oxygen gas. Understanding stoichiometry allows us to predict the amount of products formed from given reactants, or vice versa.
  • Ensures the correct conversion of reactants to products.
  • Balances chemical equations respecting mass conservation.
  • Uses coefficients to indicate molar ratios.
Chemical Reactions
Chemical reactions are transformations where substances change into new forms with different properties. They are everywhere, from cooking in the kitchen to processes within our bodies. Each chemical reaction comprises reactants converting into products.

In the given exercises, a variety of reactions are illustrated. For instance, reaction (a) involves calcium oxide reacting with water to form calcium hydroxide. Recognizing different reaction types helps in predicting the products formed.

Subcategories of chemical reactions include synthesis, decomposition, single-replacement, and double-replacement reactions. Reactions (d) and (e) belong to the synthesis category where two or more reactants combine to form one product. Chemical reactions are fundamental for producing energy, synthesizing materials, and supporting life processes.
  • Different types demonstrate varied reactant-product transformations.
  • Understanding types aids in predicting outcomes and balancing equations.
  • Vital for numerous biological and industrial processes.
Acid-Base Reactions
Acid-base reactions involve the transfer of protons (hydrogen ions) between reactants. They are crucial in processes like digestion, industrial production, and even regulating the pH in ecosystems.

An example from the exercises is reaction (b), where aluminum oxide reacts with acid (hydrogen ions). Here, the acid donates protons to form water, showcasing a typical acid-base interaction. Such reactions often produce water and a salt as products, balancing the reactants and products through the neutralization of acids and bases.

Acid-base reactions are characterized by:
  • The presence of acids that donate protons (H^+) and bases that accept them.
  • Producing water and sometimes salts as products.
  • Neutralizing effects which are essential in various chemical and biological systems.
These reactions also play a critical role in maintaining pH levels in biological systems, ensuring organisms function optimally.

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Most popular questions from this chapter

Consider the elements \(\mathrm{N}, \mathrm{F}\), Si, Rb, Te, and Ir. From this list, select the element that (a) is most electronegative, \((\mathbf{b})\) exhibits a maximum oxidation state of \(+6,(\mathbf{c})\) loses an electron most readily, (d) forms \(\pi\) bonds most readily, \((\mathbf{e})\) is a transition metal, (f) forms four covalent bonds to achieve octet.

Write the Lewis structure for each of the following species, describe its geometry, and indicate the oxidation state of the nitrogen: \((\mathbf{a}) \mathrm{N}_{2} \mathrm{O}_{3},(\mathbf{b}) \mathrm{NOCl},(\mathbf{c}) \mathrm{NO}_{2} \mathrm{Cl},(\mathbf{d}) \mathrm{N}_{2} \mathrm{O}_{4}\).

Which of the following statements are true? (a) Si can form an ion with six fluorine atoms, \(\mathrm{SiF}_{6}^{2-}\), whereas carbon cannot. (b) Si can form three stable compounds containing two Si atoms each, \(\mathrm{Si}_{2} \mathrm{H}_{2}, \mathrm{Si}_{2} \mathrm{H}_{4},\) and \(\mathrm{Si}_{2} \mathrm{H}_{6}\) (c) In \(\mathrm{HNO}_{3}\) and \(\mathrm{H}_{3} \mathrm{PO}_{4}\) the central atoms, \(\mathrm{N}\) and \(\mathrm{P}\), have different oxidation states. (d) \(\mathrm{S}\) is more electronegative than Se.

When aluminum replaces up to half of the silicon atoms in \(\mathrm{SiO}_{2}\), a mineral class called feldspars result. The feldspars are the most abundant rock-forming minerals, comprising about \(50 \%\) of the minerals in Earth's crust. Orthoclase is a feldspar in which Al replaces one-fourth of the Si atoms of \(\mathrm{SiO}_{2},\) and charge balance is completed by \(\mathrm{K}^{+}\) ions. Determine the chemical formula for orthoclase.

Write a balanced chemical reaction for the condensation reaction between \(\mathrm{H}_{3} \mathrm{PO}_{4}\) molecules to form \(\mathrm{H}_{6} \mathrm{P}_{4} \mathrm{O}_{13}\).

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