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91Ó°ÊÓ

Which of the following nuclides would you expect to be radioactive: \({ }_{26}^{58} \mathrm{Fe},{ }_{27}^{60} \mathrm{Co},{ }_{41}^{92} \mathrm{Nb},\) mercury-202, radium-226? Justify your choices.

Short Answer

Expert verified
Co-60, Nb-92, and Ra-226 are radioactive; Fe-58 and Hg-202 are stable.

Step by step solution

01

Understanding radioactive nuclides

Nuclides are considered radioactive if they are not stable. Stability can be influenced by factors such as an imbalance between protons and neutrons, being in a heavy atomic number region, or lying beyond the band of stability.
02

Analyzing Fe-58

Iron-58 (Fe) has 26 protons and 32 neutrons. This nuclide is considered stable as it lies within the band of stability with an even proton and neutron number.
03

Analyzing Co-60

Cobalt-60 (Co) has 27 protons and 33 neutrons. This nuclide is known to be radioactive, commonly used in medical and industrial processes, indicative of its radioactive nature.
04

Analyzing N-92

Niobium-92 (N-) has 41 protons and 51 neutrons. Due to the high atomic number and specific isotope, it does not fall within the band of stability, making it radioactive.
05

Analyzing Mercury-202

Mercury-202 has an atomic number of 80 with 122 neutrons. This nuclide is considered stable as it is a naturally occurring isotope of mercury and does not have radioactive characteristics.
06

Analyzing Radium-226

Radium-226 has an atomic number of 88 with 138 neutrons. This nuclide is known to be radioactive, commonly used in radiological and cancer treatments, confirming its unstable nature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nuclear Stability
Nuclear stability refers to the ability of a nucleus to remain unchanged from radioactive decay over time. A stable nucleus has a balance between the forces that hold protons and neutrons together and those that push them apart.
This balance is delicate. If a nucleus has too many or too few neutrons relative to protons, it can become unstable and radioactive.
Besides the proton-neutron ratio, the total number of protons and neutrons (mass number) impacts stability. Larger nuclei tend to be less stable due to repulsive electromagnetic forces between protons.
In practice, nuclear stability is what determines whether a nuclide is radioactive.
Isotope Analysis
Isotopes are variants of elements with the same number of protons but different numbers of neutrons. Looking at these differences helps in isotope analysis, as it relates to stability and potential radioactivity.
This analysis is critical because even small changes have drastic effects on a nucleus's behavior.
For example:
  • Iron-58, with 26 protons and 32 neutrons, is stable. Its neutron count complements its protons.
  • Cobalt-60, with 27 protons and 33 neutrons, is radioactive. It’s used widely due to its instability.
  • Niobium-92 has 41 protons and 51 neutrons, making it radioactive and unstable.
  • Mercury-202 is stable as it is a naturally occurring isotope.
  • Radium-226, despite being heavier, is radioactive and utilized in medical treatments.
Conducting such an analysis across different isotopes gives insight into the likelihood of radioactivity.
Band of Stability
The band of stability is a concept used to visualize which isotopes are stable. This band is a graph plotting neutron numbers against proton numbers, highlighting stable nuclides.
The band follows a gentle curve as elements become heavier. Lighter elements have approximately one neutron for each proton, but heavier elements need more neutrons for stability.
Anything deviating significantly from this band indicates instability and the potential for radioactivity, as seen in unstable isotopes like Cobalt-60 and Niobium-92.
Understanding this band helps scientists predict which nuclides might be radioactive without physical testing.
Proton-Neutron Ratio
The proton-neutron ratio is key in determining nuclear stability. It is simply the number of neutrons divided by the number of protons in a nucleus.
For light elements, a ratio of 1:1 is typical and contributes to stability.
As atomic numbers increase, more neutrons are needed. For heavier elements, a ratio of around 1.5:1 often denotes stability.
Deviations from ideal ratios often hint at radioactive tendencies. For instance, Cobalt-60 has a higher neutron-proton ratio that contributes to its radioactivity, contrasting with stable nuclides like Iron-58, which maintains an appropriate balance.
Awareness of these ratios can be crucial when studying nuclear chemistry and related fields.

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Most popular questions from this chapter

A \(65-\mathrm{kg}\) person is accidentally exposed for \(240 \mathrm{~s}\) to a 15-mCi source of beta radiation coming from a sample of \({ }^{90}\) Sr. (a) What is the activity of the radiation source in disintegrations per second? In becquerels? (b) Each beta particle has an energy of \(8.75 \times 10^{-14} \mathrm{~J}\). and \(7.5 \%\) of the radiation is absorbed by the person. Assuming that the absorbed radiation is spread over the person's entire body, calculate the absorbed dose in rads and in grays. (c) If the RBE of the beta particles is 1.0 , what is the effective dose in mrem and in sieverts? (d) Is the radiation dose equal to, greater than, or less than that for a typical mammogram \((3 \mathrm{mSv}) ?\)

Indicate the number of protons and neutrons in the following nuclei: \((\mathbf{a}){ }_{94}^{239} \mathrm{Pu},(\mathbf{b}){ }^{142} \mathrm{Ba},(\mathbf{c})\) potassium- 41 .

Which of the following statements about the uranium used in nuclear reactors is or are true? (i) Natural uranium has too little \({ }^{235} \mathrm{U}\) to be used as a fuel. (ii) \({ }^{238} \mathrm{U}\) cannot be used as a fuel because it forms a supercritical mass too easily. (iii) To be used as fuel, uranium must be enriched so that it is more than \(50 \%^{235} \mathrm{U}\) in composition. (iv) The neutron-induced fission of \({ }^{235} \mathrm{U}\) releases more neutrons per nucleus than fission of \({ }^{238} \mathrm{U}\).

Charcoal samples from Stonehenge in England were burned in \(\mathrm{O}_{2}\), and the resultant \(\mathrm{CO}_{2}\) gas bubbled into a solution of \(\mathrm{Ca}(\mathrm{OH})_{2}\) (limewater), resulting in the precipitation of \(\mathrm{CaCO}_{3}\). The \(\mathrm{CaCO}_{3}\) was removed by filtration and dried. A 788-mg sample of the \(\mathrm{CaCO}_{3}\) had a radioactivity of \(1.5 \times 10^{-2} \mathrm{~Bq}\) due to carbon-14. By comparison, living organisms undergo 15.3 disintegrations per minute per gram of carbon. Using the half- life of carbon-14, 5700 yr, calculate the age of the charcoal sample.

In 1930 the American physicist Ernest Lawrence designed the first cyclotron in Berkeley, California. In 1937 Lawrence bombarded a molybdenum target with deuterium ions, producing for the first time an element not found in nature. What was this element? Starting with molybdenum-96 as your reactant, write a nuclear equation to represent this process.

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