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One of the nuclides in each of the following pairs is radioactive. Predict which is radioactive and which is stable: (a) \(\frac{92}{44} \mathrm{Ru}\) and \({ }^{102} \mathrm{Ru}\), (b) \({ }_{56}^{138} \mathrm{Ba}\) and \({ }^{139} \mathrm{Ba}\) (c) tin-109 and \(\operatorname{tin}-120\)

Short Answer

Expert verified
(a) \\(^{92}\\text{Ru} \\) is radioactive. (b) \\(^{139}\\text{Ba} \\) is radioactive. (c) Tin-109 is radioactive.

Step by step solution

01

Understanding Nuclear Stability

To determine which nuclide is radioactive, one must first understand that certain ratios of neutrons to protons contribute to nuclear stability. Nuclides with stable combinations fall on or near the so-called 'line of stability'. Deviations from this line often result in instability or radioactivity.
02

Analyze Pair (a) for Stability

Pair (a) consists of \(_{44}^{92}\text{Ru}\) and \(_{44}^{102}\text{Ru}\). Calculate the neutron-to-proton ratios: \(n/p = (92 - 44) / 44 = 48/44 = 1.09\) for \(^{92}\text{Ru} \) and \(n/p = (102 - 44) / 44 = 58/44 = 1.32\) for \(^{102}\text{Ru} \). Nuclides closer to 1.5 are generally more stable in heavier elements, so \(^{102}\text{Ru} \) is more stable, making \(^{92}\text{Ru} \) radioactive.
03

Analyze Pair (b) for Stability

Pair (b) consists of \(_{56}^{138}\text{Ba}\) and \(_{56}^{139}\text{Ba}\). Calculate the neutron-to-proton ratios: \(n/p = (138 - 56) / 56 = 82/56 = 1.46\) for \(^{138}\text{Ba}\) and \(n/p = (139 - 56) / 56 = 83/56 = 1.48\) for \(^{139}\text{Ba}\). \(^{138}\text{Ba}\) is right on the edge of stable isotopes of barium, making \(^{139}\text{Ba} \) radioactive.
04

Analyze Pair (c) for Stability

Pair (c) includes tin-109 and tin-120. Calculate the neutron-to-proton ratios: \(n/p = (109 - 50) / 50 = 59/50 = 1.18\) for tin-109 and \(n/p = (120 - 50) / 50 = 70/50 = 1.4\) for tin-120. Since the stable isotopes of tin mainly have neutrons ranging from about 64 to 70, tin-120 falls within this range and is stable, leaving tin-109 as radioactive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Neutron-to-Proton Ratio
The neutron-to-proton ratio is a crucial factor in determining the stability of a nucleus. It is the number of neutrons divided by the number of protons in the nucleus. This ratio helps scientists predict whether a nuclide is likely to be stable or radioactive. For elements with lower atomic numbers, a neutron-to-proton ratio close to 1 is usually stable. However, as atomic numbers increase, a higher ratio is required for stability, approaching 1.5 for heavier elements. A balanced neutron-to-proton ratio can help keep the nucleus together, as neutrons contribute to the nuclear force that holds protons together despite their repulsive electromagnetic force. When the ratio is too high or too low, the nucleus may become unstable, leading to radioactive decay as it seeks balance.
Radioactive Decay
Radioactive decay is the process by which an unstable nucleus releases energy by emitting radiation. This process helps the nucleus move toward a more stable configuration. There are various forms of radioactive decay, such as alpha decay, beta decay, and gamma decay. Each type of decay involves different particles being released:
  • In alpha decay, the nucleus emits an alpha particle, consisting of 2 protons and 2 neutrons, thereby reducing its atomic number by 2 and mass by 4.
  • Beta decay involves the transformation of a neutron into a proton, with the emission of an electron or positron. This increases or decreases the atomic number by 1 without changing the mass.
  • Gamma decay occurs when a nucleus in an excited state releases energy in the form of gamma radiation, without changing its atomic mass or number.
Each of these processes helps the nucleus achieve a more stable neutron-to-proton ratio, reducing the energy and instability associated with the initial configuration.
Stable Isotopes
Stable isotopes are nuclei that do not undergo radioactive decay over time. They have a balanced neutron-to-proton ratio that keeps the nucleus intact. The periodic table's elements have both stable and unstable isotopes. Stable isotopes exist for various elements with natural abundance. These isotopes serve important roles in scientific research and practical applications. For instance, carbon-12 is a stable isotope widely used as a standard for atomic masses. Understanding which isotopes are stable helps researchers predict the behavior of elements in natural processes and their potential uses. Stability in isotopes is also crucial for understanding isotopic patterns and variations found in nature.
Line of Stability
The line of stability is an imaginary line on the chart of nuclides, where stable isotopes are plotted based on their neutron-to-proton ratios. This line serves as a reference for predicting the stability of isotopes. Nuclides that fall on or close to this line are generally stable, whereas those far from it tend to be radioactive. When evaluating isotopes, researchers look at how closely their neutron-to-proton ratio aligns with the line of stability. Deviations typically indicate potential instability. Observing this line helps in understanding both naturally occurring and synthetic elements, predicting the decay paths of radioactive isotopes, and developing nuclear models to explain subatomic interactions. This concept also plays a role in applications like nuclear medicine and energy production.

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Most popular questions from this chapter

A radioactive decay series that begins with \({ }_{90}^{232}\) Th ends with formation of the stable nuclide \({ }_{82}^{208} \mathrm{~Pb} .\) How many alpha-particle emissions and how many beta-particle emissions are involved in the sequence of radioactive decays?

A laboratory rat is exposed to an alpha-radiation source whose activity is \(14.3 \mathrm{mCi}\). (a) What is the activity of the radiation in disintegrations per second? In becquerels? (b) The rat has a mass of \(385 \mathrm{~g}\) and is exposed to the radiation for \(14.0 \mathrm{~s}\), absorbing \(35 \%\) of the emitted alpha particles, each having an energy of \(9.12 \times 10^{-13} \mathrm{~J} .\) Calculate the absorbed dose in millirads and grays. (c) If the RBE of the radiation is \(9.5,\) calculate the effective absorbed dose in mrem and Sv.

A 10.00 -g plant fossil from an archaeological site is found to have \(\mathrm{a}^{14} \mathrm{C}\) activity of 3094 disintegrations over a period of ten hours. A living plant is found to have a \({ }^{14} \mathrm{C}\) activity of 9207 disintegrations over the same period of time for an equivalent amount of sample with respect to the total contents of carbon. Given that the half-life of \({ }^{14} \mathrm{C}\) is 5715 years, how old is the plant fossil?

How much time is required for a 5.00-g sample of \({ }^{233} \mathrm{~Pa}\) to decay to \(0.625 \mathrm{~g}\) if the half-life for the beta decay of \({ }^{233} \mathrm{~Pa}\) is 27.4 days?

A 2.5-mL sample of 0.188 M silver nitrate solution was mixed with \(2.5 \mathrm{~mL}\) of \(0.188 \mathrm{M}\) sodium chloride solution labeled with radioactive chlorine-36. The activity of the initial sodium chloride solution was \(2.46 \times 10^{6} \mathrm{~Bq} / \mathrm{mL}\) After the resultant precipitate was removed by filtration, the remaining filtrate was found to have an activity of 175 Bq/mL. (a) Write a balanced chemical equation for the reaction that occurred. (b) Calculate the \(K_{s p}\) for the precipitate under the conditions of the experiment.

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