Chapter 20: Problem 68
A voltaic cell utilizes the following reaction: $$ 2 \mathrm{Fe}^{3+}(a q)+\mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{Fe}^{2+}(a q)+2 \mathrm{H}^{+}(a q) $$ (a) What is the emf of this cell under standard conditions? (b) What is the emf for this cell when \(\left[\mathrm{Fe}^{3+}\right]=3.50 \mathrm{M}, P_{\mathrm{H}_{2}}=\) \(96.3 \mathrm{kPa},\left[\mathrm{Fe}^{2+}\right]=0.0010 \mathrm{M}\), and the \(\mathrm{pH}\) in both half-cells is \(4.00 ?\)
Short Answer
Step by step solution
Write Half-Reactions
Determine Standard Electrode Potentials
Calculate Standard EMF (E°)
Use the Nernst Equation for Non-Standard Conditions
Calculate Reaction Quotient (Q)
Substitute into Nernst Equation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Electrode Potential
- For oxidation reactions, electrons are lost, and for reduction reactions, electrons are gained.
- Each half-cell in a voltaic cell has its own standard electrode potential.
- The standard electrode potential is crucial for determining the direction and spontaneity of a reaction.
Nernst Equation
- The Nernst Equation helps adjust the cell potential for changes in concentration, pressure, or pH levels.
- In non-standard conditions, such as when the concentrations of ions or pressure of gases differ from their standard states, the Nernst Equation comes into play.
- By accounting for these factors, it’s possible to calculate a more accurate EMF of the cell.
Reaction Quotient
- For a given reaction \( aA + bB \leftrightarrow cC + dD \), the reaction quotient is calculated as \( Q = \frac{[C]^c [D]^d}{[A]^a [B]^b} \).
- \( Q \) lets us determine which direction a reaction will shift to reach equilibrium.
- If \( Q \) is less than the equilibrium constant \( K \), the reaction proceeds forward.
- If \( Q \) is greater than \( K \), the reaction proceeds in reverse.
Redox Reactions
- Reduction is the gain of electrons, while oxidation is the loss of electrons.
- A complete redox reaction comprises two half-reactions — one for oxidation and one for reduction.
- The overall cell reaction is derived by combining these two half-reactions.