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If the equilibrium constant for a two-electron redox reaction at \(298 \mathrm{~K}\) is \(2.2 \times 10^{5}\), calculate the corresponding \(\Delta G^{\circ}\) and \(E^{\circ}\).

Short Answer

Expert verified
\( \Delta G^{\circ} \approx -30.5 \text{ kJ/mol} \) and \(E^{\circ} \approx 0.158 \text{ V}\).

Step by step solution

01

Identify Given Formula

First, you need to identify the formula that relates the equilibrium constant \( K \) to the Gibbs free energy change \( \Delta G^{\circ} \). The formula is: \[ \Delta G^{\circ} = -RT \ln K \] where \( R \) is the universal gas constant \( 8.314 \text{ J/molâ‹…K} \) and \( T \) is the temperature in Kelvin.
02

Substitute Known Values for \( \Delta G^{\circ} \)

Substitute the given values into the formula: \( R = 8.314 \text{ J/molâ‹…K} \), \( T = 298 \text{ K} \), and \( K = 2.2 \times 10^5 \). Calculate \( \Delta G^{\circ} \): \[ \Delta G^{\circ} = -8.314 \, \times \, 298 \, \times \, \ln(2.2 \times 10^5) \] First, calculate \( \ln(2.2 \times 10^5) \).
03

Calculate \( \ln(2.2 \times 10^5) \)

Compute \( \ln(2.2 \times 10^5) \). Using a calculator, you find: \[ \ln(2.2 \times 10^5) \approx 12.3 \]
04

Calculate \( \Delta G^{\circ} \)

Use the calculated \( \ln(2.2 \times 10^5) \) value: \( \Delta G^{\circ} = -8.314 \, \times \, 298 \, \times \, 12.3 \) Calculate the multiplication: \[ \Delta G^{\circ} \approx -30,501.29 \text{ J/mol} \] Convert to kJ/mol: \[ \Delta G^{\circ} \approx -30.5 \text{ kJ/mol} \]
05

Relate \( \Delta G^{\circ} \) to \( E^{\circ} \) with Formula

The relationship between Gibbs free energy and the standard cell potential \( E^{\circ} \) for a redox reaction is given by: \[ \Delta G^{\circ} = -nFE^{\circ} \] where \( n \) is the number of moles of electrons transferred (here \( n = 2 \)) and \( F \) is the Faraday's constant \( 96,485 \text{ C/mol} \).
06

Rearrange Formula to Solve for \( E^{\circ} \)

Rearrange the formula to solve for \( E^{\circ} \): \[ E^{\circ} = \frac{-\Delta G^{\circ}}{nF} \] Substitute the known values: \[ E^{\circ} = \frac{-(-30,501.29)}{2 \times 96,485} \]
07

Calculate \( E^{\circ} \)

Perform the calculation to find \( E^{\circ} \): \[ E^{\circ} \approx \frac{30,501.29}{192,970} \] \[ E^{\circ} \approx 0.158 \text{ V} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs free energy
Gibbs free energy, denoted as \( \Delta G \), is a thermodynamic potential used to predict the direction of a chemical reaction and its equilibrium position. It combines enthalpic (heat content) and entropic (degree of disorder) considerations, providing insights into the spontaneity of a process. If \( \Delta G \) is negative, the reaction is spontaneous and can proceed without external energy input. A positive \( \Delta G \) indicates a non-spontaneous reaction. To calculate \( \Delta G \) under standard conditions (i.e., \( \Delta G^{\circ} \)), we use the relationship with the equilibrium constant \( K \): \[ \Delta G^{\circ} = -RT \ln K \] Here, \( R \) is the universal gas constant, and \( T \) stands for temperature in Kelvin. By inserting known values, you can determine if a chemical system naturally evolves toward products or remains as reactants. This concept is essential in understanding chemical stability and reaction dynamics in various fields including chemistry and biochemistry.
standard cell potential
The standard cell potential, \( E^{\circ} \), is a measure of the electromotive force (emf) generated by a redox reaction under standard conditions (298 K, 1 atm, and 1 M concentrations for all solutions). It is calculated using electrode potentials from redox pairs and reflects the ability of a chemical species to either donate or accept electrons. A positive \( E^{\circ} \) indicates a spontaneous reaction when moving towards equilibrium, while a negative value suggests non-spontaneity under standard conditions.To link it to Gibbs free energy, we use the equation: \[ \Delta G^{\circ} = -nFE^{\circ} \] where \( n \) is the number of moles of electrons transferred in the reaction and \( F \) is Faraday's constant. This relationship allows us to determine \( E^{\circ} \) from \( \Delta G^{\circ} \) when the reaction progresses towards equilibrium, offering insights into both the energy yield and efficiency of the redox processes.
Faraday constant
The Faraday constant, symbolized as \( F \), is a fundamental physical constant that highlights the connection between charge and matter. It represents the total electric charge per mole of electrons, approximately \( 96,485 \text{ C/mol} \). This constant plays a crucial role in electrochemistry, forming a bridge between the macroscopic world of electric current and the microscopic world of chemical reactions.In the context of redox reactions, \( F \) allows us to convert between the energy involved in electron transfer and the electrical work done by these transfers. For instance, when calculating the standard cell potential \( E^{\circ} \), \( F \) is used in the equation \( \Delta G^{\circ} = -nFE^{\circ} \), linking the energy changes in the reaction to the electromotive force generated, thereby providing insights into the process's efficiency.
redox reaction
Redox reactions, or oxidation-reduction reactions, involve the transfer of electrons between two chemical species. These reactions are fundamental to countless biological, industrial, and environmental processes. In a redox reaction, one substance undergoes oxidation (loses electrons) while another undergoes reduction (gains electrons). Together, these processes enable energy conversion and chemical transformations.Redox reactions can be described using half-reactions:
  • Oxidation half-reaction: involves electron loss, represented by an increase in oxidation state.
  • Reduction half-reaction: involves electron gain, marked by a decrease in oxidation state.
The standard cell potential \( E^{\circ} \) measures the overall tendency of these reactions to occur spontaneously and is crucial for designing batteries and electrochemical cells. By determining \( E^{\circ} \), one evaluates the feasibility and directionality of redox processes, offering insights into energy storage, conversion, and utilization.

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Most popular questions from this chapter

Complete and balance the following equations, and identify the oxidizing and reducing agents. (Recall that the \(\mathrm{O}\) atoms in hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\), have an atypical oxidation state.) (a) \(\mathrm{NO}_{2}^{-}(a q)+\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q) \longrightarrow \mathrm{Cr}^{3+}(a q)+\mathrm{NO}_{3}^{-}(a q)\) (acidic solution) (b) \(\mathrm{S}(s)+\mathrm{HNO}_{3}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{SO}_{3}(a q)+\mathrm{N}_{2} \mathrm{O}(g)\) (acidic solution) (c) \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)+\mathrm{CH}_{3} \mathrm{OH}(a q) \longrightarrow \mathrm{HCOOH}(a q)+\) \(\mathrm{Cr}^{3+}(a q)\) (acidic solution) (d) \(\mathrm{BrO}_{3}^{-}(a q)+\mathrm{N}_{2} \mathrm{H}_{4}(g) \longrightarrow \mathrm{Br}^{-}(a q)+\mathrm{N}_{2}(g)\) (acidic solution) (e) \(\mathrm{NO}_{2}^{-}(a q)+\mathrm{Al}(s) \longrightarrow \mathrm{NH}_{4}^{+}(a q)+\mathrm{AlO}_{2}^{-}(a q)\) (basic solution) (f) \(\mathrm{H}_{2} \mathrm{O}_{2}(a q)+\mathrm{ClO}_{2}(a q) \longrightarrow \mathrm{ClO}_{2}^{-}(a q)+\mathrm{O}_{2}(g)\)

A \(1 M\) solution of \(\mathrm{AgNO}_{3}\) is placed in a beaker with a strip of Ag metal. A \(1 \mathrm{M}\) solution of \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\) is placed in a second beaker with a strip of Cu metal. A salt bridge connects the two beakers, and wires to a voltmeter link the two metal electrodes. (a) Which electrode serves as the anode, and which as the cathode? (b) Which electrode gains mass, and which loses mass as the cell reaction proceeds? (c) Write the equation for the overall cell reaction. (d) What is the emf generated by the cell under standard conditions?

Metallic magnesium can be made by the electrolysis of molten \(\mathrm{MgCl}_{2}\). (a) What mass of \(\mathrm{Mg}\) is formed by passing a current of 4.55 A through molten \(\mathrm{MgCl}_{2}\), for 4.50 days? (b) How many minutes are needed to plate out \(25.00 \mathrm{~g} \mathrm{Mg}\) from molten \(\mathrm{MgCl}_{2}\) using \(3.50 \mathrm{~A}\) of current?

(a) What is the difference between a battery and a fuel cell? (b) Can the "fuel" of a fuel cell be a solid?

Indicate whether each of the following statements is true or false: (a) If something is oxidized, it is formally losing electrons. (b) For the reaction \(\mathrm{Fe}^{3+}(a q)+\mathrm{Co}^{2+}(a q) \longrightarrow \mathrm{Fe}^{2+}(a q)+\) \(\mathrm{Co}^{3+}(a q), \mathrm{Fe}^{3+}(a q)\) is the reducing agent and \(\mathrm{Co}^{2+}(a q)\) is the oxidizing agent. (c) If there are no changes in the oxidation state of the reactants or products of a particular reaction, that reaction is not a redox reaction.

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