/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Complete the table by filling in... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Complete the table by filling in the formula for the ionic compound formed by each pair of cations and anions, as shown for the first pair. $$ \begin{array}{l|l|l|l|l} \hline \text { Ion } & \mathrm{K}^{+} & \mathrm{NH}_{4}^{+} & \mathrm{Mg}^{2+} & \mathrm{Fe}^{3+} \\ \hline \mathrm{Cl}^{-} & \mathrm{KCl} & & & \\ \mathrm{OH}^{-} & & & & \\ \mathrm{CO}_{3}^{2-} & & & & \\ \mathrm{PO}_{4}^{3-} & & & & \\ \hline \end{array} $$

Short Answer

Expert verified
KCl, NH₄Cl, MgCl₂, FeCl₃; KOH, NH₄OH, Mg(OH)₂, Fe(OH)₃; K₂CO₃, (NH₄)₂CO₃, MgCO₃, Fe₂(CO₃)₃; K₃PO₄, (NH₄)₃PO₄, Mg₃(PO₄)₂, FePO₄.

Step by step solution

01

Understand Ion Charges

Start by noting the charges of each ion. \[\begin{array}{l|l}K^+& +1\NH_4^+& +1\Mg^{2+}& +2\Fe^{3+}& +3\Cl^-& -1\OH^-& -1\CO_3^{2-}& -2\PO_4^{3-}& -3\\end{array}\]This information will help balance the charges when forming the ionic compounds.
02

Combine Ions to Form Compounds

Using the charge information, combine the cations and anions to make compounds where the total charge is neutral. Use the least common multiple (LCM) of the charges if necessary to balance the compound.- \(K^+ + Cl^- \rightarrow \text{KCl}\) (Given)- \(NH_4^+ + Cl^- \rightarrow \text{NH}_4\text{Cl}\)- \(Mg^{2+} + Cl^- \rightarrow \text{MgCl}_2\)- \(Fe^{3+} + Cl^- \rightarrow \text{FeCl}_3\)
03

Complete the Table with Hydroxide Ion

Combine each cation with the \(OH^-\) anion:- \(K^+ + OH^- \rightarrow \text{KOH}\)- \(NH_4^+ + OH^- \rightarrow \text{NH}_4\text{OH}\)- \(Mg^{2+} + OH^- \rightarrow \text{Mg(OH)}_2\)- \(Fe^{3+} + OH^- \rightarrow \text{Fe(OH)}_3\)
04

Combine with Carbonate Ion

Using \(CO_3^{2-}\):- \(K^+ + CO_3^{2-} \rightarrow \text{K}_2\text{CO}_3\)- \(NH_4^+ + CO_3^{2-} \rightarrow (\text{NH}_4)_2\text{CO}_3\)- \(Mg^{2+} + CO_3^{2-} \rightarrow \text{MgCO}_3\)- \(Fe^{3+} + CO_3^{2-} \rightarrow \text{Fe}_2(\text{CO}_3)_3\)
05

Combine with Phosphate Ion

Using \(PO_4^{3-}\):- \(K^+ + PO_4^{3-} \rightarrow \text{K}_3\text{PO}_4\)- \(NH_4^+ + PO_4^{3-} \rightarrow (\text{NH}_4)_3\text{PO}_4\)- \(Mg^{2+} + PO_4^{3-} \rightarrow \text{Mg}_3(\text{PO}_4)_2\)- \(Fe^{3+} + PO_4^{3-} \rightarrow \text{FePO}_4\)
06

Fill in the Table with Compounds

Now compile the results into the table format:\[\begin{array}{l|l|l|l|l}\hline \text{Ion} & \text{K}^+ & \text{NH}_4^+ & \text{Mg}^{2+} & \text{Fe}^{3+} \\hline \text{Cl}^- & \text{KCl} & \text{NH}_4\text{Cl} & \text{MgCl}_2 & \text{FeCl}_3 \\text{OH}^- & \text{KOH} & \text{NH}_4\text{OH} & \text{Mg(OH)}_2 & \text{Fe(OH)}_3 \\text{CO}_3^{2-} & \text{K}_2\text{CO}_3 & (\text{NH}_4)_2\text{CO}_3 & \text{MgCO}_3 & \text{Fe}_2(\text{CO}_3)_3 \\text{PO}_4^{3-} & \text{K}_3\text{PO}_4 & (\text{NH}_4)_3\text{PO}_4 & \text{Mg}_3(\text{PO}_4)_2 & \text{FePO}_4 \\hline\end{array}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cation and Anion Charges
Ionic compounds are formed by the combination of cations and anions, with the key goal of achieving electrical neutrality. A cation is a positively charged ion, while an anion carries a negative charge. The charges result from the loss or gain of electrons, respectively. In a chemical formula of an ionic compound, the total positive charges must balance the total negative charges so that the net charge is zero. This is crucial in constructing ionic compounds. For example, the ion potassium ( K^+ ) has a charge of +1 because it has lost one electron. Similarly, the chloride ion ( Cl^- ) has a charge of -1, having gained one electron.
When forming an ionic compound such as potassium chloride ( KCl ), each positive charge from the cation is paired with a negative charge from the anion, resulting in a neutral compound. Understanding and using the charges of ions is essential to predicting and writing the formulas of ionic compounds correctly.
Balancing Chemical Formulas
Balancing a chemical formula involves ensuring the total positive charges equal the total negative charges. It's about creating a stable ionic compound where the electrostatic forces between ions hold them together. A simple idea: their charges must cancel out.
If you take magnesium ( Mg^{2+} ), which has a charge of +2, and chloride ( Cl^- ) with a charge of -1, you'll need two chloride ions to balance the charge from the magnesium. This results in the formula MgCl_2 . The subscript indicates how many of each ion are present.
For more complex ions like phosphate ( PO_4^{3-} ), the approach is the same but might require finding the least common multiple (LCM) of the charges. Combining with magnesium would mean that we need three magnesium ions ( Mg^{2+} ) for two phosphate ions to form Mg_3( PO_4_n)_2 .
Balancing ensures the formula reflects a true representation of the compound's composition, maintaining charge neutrality, and follows stoichiometric principles.
Chemical Nomenclature
Chemical nomenclature is the language of chemistry that simplifies the naming of compounds. It follows standardized rules to ensure each compound's name is systematic and universally recognizable, allowing clear and concise communication among chemists.
For ionic compounds, naming starts with the cation (positively charged ion) followed by the anion (negatively charged ion). Simple examples include sodium chloride ( NaCl ) and calcium oxide ( CaO ). The method remains consistent even with more complex polyatomic ions. For instance, ammonium chloride ( NH_4Cl ) involves the polyatomic ion ammonium ( NH_4^+ ), with the name reflecting its components.
Special attention is required when multiple oxidation states are possible. Iron, for example, can form Fe^{2+} or Fe^{3+} ions; thus, its compounds FeO and Fe_2O_3 are named iron(II) oxide and iron(III) oxide, respectively. This nomenclature makes it clear which ions are involved, especially when elements form more than one type of ion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether each of the following statements is true or false. If false, correct the statement to make it true: \((\mathbf{a})\) The nucleus has most of the mass and comprises most of the volume of an atom. (b) Every atom of a given element has the same number of protons. (c) The number of electrons in an atom equals the number of neutrons in the atom. (d) The protons in the nucleus of the helium atom are held together by a force called the strong nuclear force.

Predict the chemical formulas of the ionic compound formed by (a) \(\mathrm{Fe}^{3+}\) and \(\mathrm{OH}^{-},\) (b) \(\mathrm{Cs}^{+}\) and \(\mathrm{NO}_{3}^{-}\), (c) \(\mathrm{V}^{2+}\) and \(\mathrm{CH}_{3} \mathrm{COO}^{-},(\mathbf{d}) \mathrm{Li}^{+}\) and \(\mathrm{PO}_{4}^{3-},(\mathbf{e}) \mathrm{In}^{3+}\) and \(\mathrm{O}^{2-} .\)

Naturally occurring lead has the following isotopic abundances: $$ \begin{array}{lcc} \hline \text { Isotope } & \text { Abundance (\%) } & \text { Atomic mass (u) } \\ \hline{ }^{204} \mathrm{~Pb} & 1.4 & 203.9730 \\ { }^{206} \mathrm{~Pb} & 24.1 & 205.9744 \\ { }^{207} \mathrm{~Pb} & 22.1 & 206.9759 \\ { }^{208} \mathrm{~Pb} & 52.4 & 207.9766 \\ \hline \end{array} $$ (a) What is the average atomic mass of \(\mathrm{Pb}\) ? (b) Sketch the mass spectrum of \(\mathrm{Pb}\).

A 1.0 -g sample of carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) is fully decomposed into its elements, yielding \(0.273 \mathrm{~g}\) of carbon and \(0.727 \mathrm{~g}\) of oxygen. (a) What is the ratio of the mass of \(\mathrm{O}\) to \(\mathrm{C} ?(\mathbf{b})\) If a sample of a different compound decomposes into \(0.429 \mathrm{~g}\) of carbon and \(0.571 \mathrm{~g}\) of oxygen, what is its ratio of the mass of \(\mathrm{O}\) to \(\mathrm{C} ?(\mathbf{c})\) According to Dalton's atomic theory, what is the empirical formula of the second compound?

Write the chemical formula for each substance mentioned in the following word descriptions (use the front inside cover to find the symbols for the elements you do not know). (a) Zinc carbonate can be heated to form zinc oxide and carbon dioxide. (b) On treatment with hydrofluoric acid, silicon dioxide forms silicon tetrafluoride and water. (c) Sulfur dioxide reacts with water to form sulfurous acid. \((\mathbf{d})\) The substance phosphorus trihydride, commonly called phosphine, is a toxic gas. (e) Perchloric acid reacts with cadmium to form cadmium(II) perchlorate. (f) Vanadium(III) bromide is a colored solid.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.