/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 97 (a) For each of the following re... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) For each of the following reactions, predict the sign of \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) without doing any calculations. (b) Based on your general chemical knowledge, predict which of these reactions will have \(K>1\) at \(25^{\circ} \mathrm{C} .(\mathbf{c})\) In each case, indicate whether \(K\) should increase or decrease with increasing temperature. (i) \(2 \mathrm{Fe}(s)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{FeO}(s)\) (ii) \(\mathrm{Cl}_{2}(g) \rightleftharpoons 2 \mathrm{Cl}(g)\) (iii) \(\mathrm{NH}_{4} \mathrm{Cl}(s) \rightleftharpoons \mathrm{NH}_{3}(g)+\mathrm{HCl}(g)\) (iv) \(\mathrm{CO}_{2}(g)+\mathrm{CaO}(s) \rightleftharpoons \mathrm{CaCO}_{3}(s)\)

Short Answer

Expert verified
(i) \(\Delta H^{\circ}<0\), \(\Delta S^{\circ}<0\), \(K>1\) (decreases with \(T\)); (ii) \(\Delta H^{\circ}>0\), \(\Delta S^{\circ}>0\), \(K<1\) (increases with \(T\)); (iii) \(\Delta H^{\circ}>0\), \(\Delta S^{\circ}>0\), \(K<1\) (increases with \(T\)); (iv) \(\Delta H^{\circ}<0\), \(\Delta S^{\circ}<0\), \(K>1\) (decreases with \(T\)).

Step by step solution

01

Analyzing Reaction (i)

The reaction \(2 \mathrm{Fe}(s)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{FeO}(s)\) is a combination reaction forming an ionic compound. Since new bonds are formed, exothermic behavior is expected, so \(\Delta H^{\circ} < 0\). The reaction involves gas molecules being consumed, leading to a decrease in randomness, so \(\Delta S^{\circ} < 0\). An exothermic reaction with a decrease in entropy can have \(K > 1\), favoring the formation of the product at lower temperatures. As temperature increases, \(K\) decreases due to the exothermic nature.
02

Analyzing Reaction (ii)

The reaction \(\mathrm{Cl}_{2}(g) \rightleftharpoons 2 \mathrm{Cl}(g)\) is a bond-breaking reaction that requires energy input, hence \(\Delta H^{\circ} > 0\). It involves the production of two moles of gas from one, increasing the system's disorder, so \(\Delta S^{\circ} > 0\). Despite requiring energy, the increase in entropy suggests \(K < 1\) at \(25^{\circ} \mathrm{C}\). However, \(K\) increases with temperature increase, as the reaction is endothermic.
03

Analyzing Reaction (iii)

For \(\mathrm{NH}_{4} \mathrm{Cl}(s) \rightleftharpoons \mathrm{NH}_{3}(g)+\mathrm{HCl}(g)\), sublimation of solid to gases generally requires energy, indicating \(\Delta H^{\circ} > 0\). The reaction involves the formation of gases from a solid, increasing the entropy, so \(\Delta S^{\circ} > 0\). \(K < 1\) at \(25^{\circ} \mathrm{C}\) due to the endothermic nature, but \(K\) increases with temperature.
04

Analyzing Reaction (iv)

The reaction \(\mathrm{CO}_{2}(g)+\mathrm{CaO}(s) \rightleftharpoons \mathrm{CaCO}_{3}(s)\) is a synthesis reaction forming a solid from a gas, usually exothermic, so \(\Delta H^{\circ} < 0\). The reaction results in decreased disorder, suggesting \(\Delta S^{\circ} < 0\). \(K > 1\) at \(25^{\circ} \mathrm{C}\) as the production of solid is favored, but \(K\) decreases as temperature increases due to the exothermic nature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Entropy
Entropy is a fundamental concept in thermodynamics that measures the degree of randomness or disorder in a system. It is denoted by the symbol \(S\). In chemistry, entropy changes, represented by \(\Delta S\), occur during chemical reactions and can indicate how the disorder of a system changes when reactants become products.

In a reaction where the number of gas molecules increases, like the conversion of \(\mathrm{Cl}_2(g)\) to \(2\mathrm{Cl}(g)\), entropy increases. This is because more particles are free to move, thus increasing randomness. On the other hand, in reactions where gases form more ordered states, such as when a gas reacts to form a solid, entropy decreases, as seen in the reaction \(\mathrm{CO}_2(g) + \mathrm{CaO}(s) \rightarrow \mathrm{CaCO}_3(s)\).

Understanding entropy helps predict whether a reaction is favorable. An increase in entropy \((\Delta S^{\circ} > 0)\) often means greater feasibility, especially at higher temperatures. However, entropy must be considered alongside enthalpy to determine the overall spontaneity of a reaction.
Enthalpy
Enthalpy is a measure of the total energy of a thermodynamic system, usually focused on heat changes during a reaction. It is represented by the symbol \(H\), and changes in enthalpy are denoted as \(\Delta H\).

Reactions can either release heat and be exothermic \((\Delta H^{\circ} < 0)\) or absorb heat and be endothermic \((\Delta H^{\circ} > 0)\). For example, reaction (i) \(2\mathrm{Fe}(s) + \mathrm{O}_2(g) \rightarrow 2\mathrm{FeO}(s)\) is exothermic since energy is released as new bonds are formed. Meanwhile, reaction (iii) \(\mathrm{NH}_4\mathrm{Cl}(s) \rightarrow \mathrm{NH}_3(g) + \mathrm{HCl}(g)\) is endothermic as energy is needed to sublimate the solid into gases.

The sign and magnitude of \(\Delta H\) help in determining the favorability of a reaction at different temperatures. Exothermic reactions, which release energy, are usually more spontaneous at lower temperatures, while endothermic reactions become more feasible as the temperature increases.
Chemical Equilibrium
Chemical equilibrium occurs when the rates of the forward and reverse reactions are equal, and the concentrations of reactants and products remain stable over time. This balance is described by the equilibrium constant \(K\).

For example, in the reaction \(2\mathrm{Fe}(s) + \mathrm{O}_2(g) \rightleftharpoons 2\mathrm{FeO}(s)\), the reaction is exothermic and has a lower entropy, leading to \(K > 1\) at room temperature, meaning the products are favored.

The value of \(K\) also varies with temperature changes due to the relationship between enthalpy and equilibrium, often described by the van 't Hoff equation. For exothermic reactions, \(K\) decreases with an increase in temperature because the reverse reaction becomes more favorable. Conversely, for endothermic reactions, such as the sublimation of \(\mathrm{NH}_4\mathrm{Cl}\), \(K\) increases with temperature, favoring product formation as the temperature is raised.

Understanding chemical equilibrium and its dependence on temperature is crucial for predicting how changes in conditions will affect the direction and extent of a chemical reaction.

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Most popular questions from this chapter

Predict the sign of \(\Delta S_{\text {sys }}\) for each of the following processes: (a) Gaseous \(\mathrm{H}_{2}\) reacts with liquid palmitoleic acid \(\left(\mathrm{C}_{16} \mathrm{H}_{30} \mathrm{O}_{2},\right.\) unsaturated fatty acid) to form liquid palmitic acid \(\left(\mathrm{C}_{16} \mathrm{H}_{32} \mathrm{O}_{2}\right.\) saturated fatty acid). (b) Liquid palmitic acid solidifies at \(1^{\circ} \mathrm{C}\) to solid palmitic acid. (c) Silver chloride precipitates upon mixing \(\mathrm{AgNO}_{3}(a q)\) and \(\mathrm{NaCl}(a q)\). (d) Gaseous \(\mathrm{H}_{2}\) dissociates in an electric arc to form gaseous Hatoms (used in atomic hydrogen welding).

Predict the sign of the entropy change of the system for each of the following reactions: (a) \(\mathrm{CO}(g)+\mathrm{H}_{2}(g) \longrightarrow C(s)+\mathrm{H}_{2} \mathrm{O}(g)\) (b) \(2 \mathrm{O}_{2}(g)+\mathrm{N}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g)\) (c) \(\mathrm{NH}_{4} \mathrm{Cl}(s) \longrightarrow \mathrm{HCl}(g)+\mathrm{NH}_{3}(g)\) (d) \(2 \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}(g)\)

For each of the following pairs, predict which substance possesses the larger entropy per mole: (a) \(1 \mathrm{~mol}\) of \(\mathrm{O}_{2}(g)\) at \(300^{\circ} \mathrm{C}, 1.013 \mathrm{kPa}\), or \(1 \mathrm{~mol}\) of \(\mathrm{O}_{3}(g)\) at \(300^{\circ} \mathrm{C}, 1.013 \mathrm{kPa} ;\) (b) \(1 \mathrm{~mol}\) of \(\mathrm{H}_{2} \mathrm{O}(g)\) at \(100^{\circ} \mathrm{C}, 101.3 \mathrm{kPa}\), or \(1 \mathrm{~mol}\) of \(\mathrm{H}_{2} \mathrm{O}(l)\) at \(100^{\circ} \mathrm{C}, 101.3 \mathrm{kPa} ;(\mathbf{c}) 0.5 \mathrm{~mol}\) of \(\mathrm{N}_{2}(g)\) at \(298 \mathrm{~K}, 20-\mathrm{L}\) vol- ume, or \(0.5 \mathrm{~mol} \mathrm{CH}_{4}(g)\) at \(298 \mathrm{~K}, 20-\mathrm{L}\) volume; \((\mathbf{d}) 100 \mathrm{~g}\) \(\mathrm{Na}_{2} \mathrm{SO}_{4}(s)\) at \(30^{\circ} \mathrm{C}\) or \(100 \mathrm{~g} \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)\) at \(30^{\circ} \mathrm{C}\)

In chemical kinetics, the entropy of activation is the entropy change for the process in which the reactants reach the activated complex. Predict whether the entropy of activation for a bimolecular process is usually positive of negative.

A standard air conditioner involves a refrigerant that is typically now a fluorinated hydrocarbon, such as \(\mathrm{CH}_{2} \mathrm{~F}_{2}\). An air- conditioner refrigerant has the property that it readily vaporizes at atmospheric pressure and is easily compressed to its liquid phase under increased pressure. The operation of an air conditioner can be thought of as a closed system made up of the refrigerant going through the two stages shown here (the air circulation is not shown in this diagram). During expansion, the liquid refrigerant is released into an expansion chamber at low pressure, where it vaporizes. The vapor then undergoes compression at high pressure back to its liquid phase in a compression chamber. (a) What is the sign of \(q\) for the expansion? (b) What is the sign of \(q\) for the compression? (c) In a central air-conditioning system, one chamber is inside the home and the other is outside. Which chamber is where, and why? (d) Imagine that a sample of liquid refrigerant undergoes expansion followed by compression, so that it is back to its original state. Would you expect that to be a reversible process? (e) Suppose that a house and its exterior are both initially at \(31^{\circ} \mathrm{C}\). Some time after the air conditioner is turned on, the house is cooled to \(24^{\circ} \mathrm{C}\). Is this process spontaneous or nonspontaneous?

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