Chapter 17: Problem 112
A sample of \(7.5 \mathrm{~L}\) of \(\mathrm{NH}_{3}\) gas at \(22^{\circ} \mathrm{C}\) and 735 torr is bubbled into a \(0.50-\mathrm{L}\) solution of \(0.40 \mathrm{M} \mathrm{HCl}\). Assuming that all the \(\mathrm{NH}_{3}\) dissolves and that the volume of the solution remains \(0.50 \mathrm{~L},\) calculate the \(\mathrm{pH}\) of the resulting solution.
Short Answer
Step by step solution
Calculate moles of NH3
Calculate moles of HCl in the solution
Determine the limiting reactant and excess
Calculate concentration of NH4+
Calculate pH of the solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas Law
- \( P \) is the pressure of the gas,
- \( V \) is the volume of the gas,
- \( n \) is the number of moles,
- \( R \) is the ideal gas constant (0.0821 L·atm/mol·K), and
- \( T \) is the temperature in Kelvin.
By rearranging the ideal gas law, \( n = \frac{PV}{RT} \), we calculated the number of moles of \( \text{NH}_3 \) present in the sample. This calculation is crucial for further determining the amount of \( \text{NH}_3 \) available for reacting with \( \text{HCl} \). Thus, understanding this equation allows you to predict how gases will behave under different conditions.
Limiting Reactant
In this case, both \( \text{NH}_3 \) and \( \text{HCl} \) react in a 1:1 mole ratio to form \( \text{NH}_4^+ \) and \( \text{Cl}^- \). By calculating the moles of each reactant, we found there were 0.303 moles of \( \text{NH}_3 \) and 0.20 moles of \( \text{HCl} \).
Since \( \text{HCl} \) has fewer moles, it is the limiting reactant. This means all of the \( \text{HCl} \) will react, leaving an excess of \( \text{NH}_3 \). Recognizing the limiting reactant helps predict the extent of the reaction and the composition of the resulting solution.
pH Calculation
After the reaction, the concentration of \( \text{NH}_4^+ \) is determined to be 0.40 M. With the weak base dissociation constant \( K_b \) for ammonia known, we can calculate \( [\text{OH}^-] \) and subsequently \( \text{pOH} \). The relationship \( \text{pH} = 14 - \text{pOH} \) then allows us to find the \( \text{pH} \).
This process involves logarithms and equilibrium constants, granting insight into the acidity of weak acid solutions, which is central to chemistry studies.
Acid-Base Reaction
These reactions typically proceed through proton transfer, where the base accepts \( \text{H}^+ \) ions from the acid. In this case, \( \text{NH}_3 \) gains a proton from \( \text{HCl} \), transforming into \( \text{NH}_4^+ \). Understanding these reactions is crucial, as they underlie many processes in chemistry and biology.
Often, such reactions are central in buffer solutions, where weak acids/bases help maintain \( \text{pH} \) levels. Thus, knowledge of acid-base interactions expands your understanding of chemical behavior in various environments.