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For each of these reactions, identify the acid and base among the reactants, and state if the acids and bases are Lewis, Arrhenius, and/or Br酶nsted-Lowry: (a) \(\mathrm{PCl}_{4}^{+}+\mathrm{Cl}^{-} \longrightarrow \mathrm{PCl}_{5}\) (b) \(\mathrm{NH}_{3}+\mathrm{BF}_{3} \longrightarrow \mathrm{H}_{3} \mathrm{NBF}_{3}\) (c) \(\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}+\mathrm{H}_{2} \mathrm{O} \longrightarrow\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{OH}\right]^{2+}+\mathrm{H}_{3} \mathrm{O}^{+}\)

Short Answer

Expert verified
(a) \( \mathrm{PCl}_{4}^{+} \) is Lewis acid; \( \mathrm{Cl}^{-} \) is Lewis base. (b) \( \mathrm{BF}_{3} \) is Lewis acid; \( \mathrm{NH}_{3} \) is Lewis base. (c) \( \left[\mathrm{Al}\left(\mathrm{H}_{2}\mathrm{O}\right)_{6}\right]^{3+} \) is Br酶nsted-Lowry acid; \( \mathrm{H}_{2}\mathrm{O} \) is Br酶nsted-Lowry base.

Step by step solution

01

Identify Acid and Base for Reaction (a)

In the reaction \( \mathrm{PCl}_{4}^{+}+\mathrm{Cl}^{-} \longrightarrow \mathrm{PCl}_{5} \), we have \( \mathrm{PCl}_{4}^{+} \) accepting a pair of electrons from \( \mathrm{Cl}^{-} \) to form \( \mathrm{PCl}_{5} \). The acceptor of electron pairs is the Lewis acid, which is \( \mathrm{PCl}_{4}^{+} \), and \( \mathrm{Cl}^{-} \), which donates an electron pair, is the Lewis base. There are no protons (H鈦) involved, so it is not characterized under Arrhenius or Br酶nsted-Lowry definitions.
02

Identify Acid and Base for Reaction (b)

In the reaction \( \mathrm{NH}_{3}+\mathrm{BF}_{3} \longrightarrow \mathrm{H}_{3}\mathrm{NBF}_{3} \), \( \mathrm{NH}_{3} \) donates a pair of electrons to \( \mathrm{BF}_{3} \) to form the adduct \( \mathrm{H}_{3}\mathrm{NBF}_{3} \). Here, \( \mathrm{BF}_{3} \) is the Lewis acid as it accepts the electron pair, and \( \mathrm{NH}_{3} \) is the Lewis base since it donates an electron pair. This reaction is purely Lewis as no protons are transferred.
03

Identify Acid and Base for Reaction (c)

In the reaction \( \left[\mathrm{Al}\left(\mathrm{H}_{2}\mathrm{O}\right)_{6}\right]^{3+}+\mathrm{H}_{2}\mathrm{O} \longrightarrow\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{OH}\right]^{2+}+\mathrm{H}_{3}\mathrm{O}^{+} \), the \( \left[\mathrm{Al}\left(\mathrm{H}_{2}\mathrm{O}\right)_{6}\right]^{3+} \) ion donates a proton to water, forming \( \mathrm{H}_{3}\mathrm{O}^{+} \). Thus, \( \left[\mathrm{Al}\left(\mathrm{H}_{2}\mathrm{O}\right)_{6}\right]^{3+} \) is the Br酶nsted-Lowry acid, and \( \mathrm{H}_{2}\mathrm{O} \) is the Br酶nsted-Lowry base because it accepts a proton. There are no electron pair changes characterizing Lewis, nor ionization in water, which would indicate Arrhenius.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis Acid
Lewis acids are fascinating components in chemical reactions. They are defined by their ability to accept electron pairs from other entities. In essence, they are electron-pair acceptors. This concept is crucial in various fields, such as organic chemistry, because it helps predict how molecules might interact.
The classic example of a Lewis acid, as seen in Reaction (a), is \( \mathrm{PCl}_{4}^{+} \), which accepts an electron pair from the chloride ion \( \mathrm{Cl}^{-} \) to form \( \mathrm{PCl}_{5} \). This kind of interaction underscores the simplicity of Lewis's theory when no protons are involved. It broadens the understanding beyond traditional acids that usually donate protons.
To identify a Lewis acid, look for species with an incomplete octet or positively charged ions. These are often eager to accept electrons to complete their electronic structure. Lewis acids play essential roles in catalysts, especially in the industrial production of various chemicals.
Br酶nsted-Lowry Acid
Br酶nsted-Lowry acid is a concept centered around the donation of protons (H鈦 ions). Unlike Lewis acids, Br酶nsted-Lowry acids must have a hydrogen ion to donate, emphasizing the transfer of protons rather than electron pairs.
In Reaction (c), \( \left[\mathrm{Al}\left(\mathrm{H}_{2}\mathrm{O}\right)_{6}\right]^{3+} \) exemplifies a Br酶nsted-Lowry acid by donating a proton to water, forming the hydronium ion \( \mathrm{H}_{3}\mathrm{O}^{+} \).
This is a fundamental concept in acid-base chemistry, often used to predict the behavior of substances in aqueous solutions. Br酶nsted-Lowry theory expands on the classical definitions by covering reactions even outside water, making it a versatile tool in understanding the nature of acids.
Br酶nsted-Lowry Base
Br酶nsted-Lowry bases are defined by their ability to accept protons. Recognizing a Br酶nsted-Lowry base involves looking for substances that participate in the proton transfer process.
In the context of Reaction (c), water \( \mathrm{H}_{2}\mathrm{O} \) acts as a Br酶nsted-Lowry base by accepting a proton from \( \left[\mathrm{Al}\left(\mathrm{H}_{2}\mathrm{O}\right)_{6}\right]^{3+} \), resulting in the formation of the hydronium ion \( \mathrm{H}_{3}\mathrm{O}^{+} \).
Understanding bases in this way provides a clear framework for predicting reactions, particularly in diverse chemical environments, not limited to water. The concept of Br酶nsted-Lowry bases is particularly relevant in biochemistry and environmental science, where proton transfers are pivotal reactions.
Lewis Base
Lewis bases are substances that donate electron pairs. This role is essential in many chemical reactions where an electron pair donor is required to complete the electronic structure of another molecule.
Taking Reaction (b) as an illustration, \( \mathrm{NH}_{3} \) donates its electron pair to \( \mathrm{BF}_{3} \), forming an adduct \( \mathrm{H}_{3}\mathrm{NBF}_{3} \). This clearly shows the action of a Lewis base, as \( \mathrm{NH}_{3} \) shares its lone pair to facilitate reaction completion.
Lewis bases are typically molecules with lone pairs of electrons, such as amines, alcohols, or any species with a negative charge. Their study is vital in coordination chemistry, where complex formation often relies on this donation mechanism.

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Most popular questions from this chapter

(a) Write a chemical equation that illustrates the autoionization of water. \((\mathbf{b})\) Write the expression for the ionproduct constant for water, \(K_{w \cdot}(\mathbf{c})\) If a solution is described as basic, which of the following is true: (i) \(\left[\mathrm{H}^{+}\right]>\left[\mathrm{OH}^{-}\right]\) (ii) \(\left[\mathrm{H}^{+}\right]=\left[\mathrm{OH}^{-}\right],\) or (iii) \(\left[\mathrm{H}^{+}\right]<\left[\mathrm{OH}^{-}\right] ?\)

Succinic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{4}\right),\) which we will denote \(\mathrm{H}_{2} \mathrm{Suc},\) is a biologically relevant diprotic acid with the structure shown below. At \(25^{\circ} \mathrm{C}\), the acid-dissociation constants for succinic acid are \(K_{a 1}=6.9 \times 10^{-5}\) and \(K_{a 2}=2.5 \times 10^{-6}\) (a) Determine the pH of a \(0.32 \mathrm{M}\) solution of \(\mathrm{H}_{2} \mathrm{Suc}\) at \(25^{\circ} \mathrm{C}\), assuming that only the first dissociation is relevant. (b) Determine the molar concentration of \(\mathrm{Suc}^{2-}\) in the solution in part (a). (c) Is the assumption you made in part (a) justified by the result from part (b)? (d) Will a solution of the salt NaHSuc be acidic, neutral, or basic?

Identify the Lewis acid and Lewis base among the reactants in each of the following reactions: (a) \(\mathrm{Fe}\left(\mathrm{ClO}_{4}\right)_{3}(s)+6 \mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons\) $$ \left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}(a q)+3 \mathrm{ClO}_{4}^{-}(a q) $$ (b) \(\mathrm{CN}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{HCN}(a q)+\mathrm{OH}^{-}(a q)\) (c) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}(g)+\mathrm{BF}_{3}(g) \rightleftharpoons\left(\mathrm{CH}_{3}\right)_{3} \mathrm{NBF}_{3}(s)\) (d) \(\mathrm{HIO}(l q)+\mathrm{NH}_{2}^{-}(l q) \rightleftharpoons \mathrm{NH}_{3}(l q)+\mathrm{IO}^{-}(l q)\) (lq denotes liquid ammonia as solvent)

Many moderately large organic molecules containing basic nitrogen atoms are not very soluble in water as neutral molecules, but they are frequently much more soluble as their acid salts. Assuming that \(\mathrm{pH}\) in the stomach is \(2.5,\) indicate whether each of the following compounds would be present in the stomach as the neutral base or in the protonated form: nicotine, \(K_{b}=7 \times 10^{-7} ;\) caffeine, \(K_{b}=4 \times 10^{-14}\) strychnine, \(K_{b}=1 \times 10^{-6} ;\) quinine, \(K_{b}=1.1 \times 10^{-6} .\)

Calculate \(\left[\mathrm{OH}^{-}\right]\) for each of the following solutions, and indicate whether the solution is acidic, basic, or neutral: (a) \(\left[\mathrm{H}^{+}\right]=0.00010 \mathrm{M} ;(\mathbf{b})\left[\mathrm{H}^{+}\right]=7.3 \times 10^{-14} \mathrm{M} ;(\mathbf{c})\) a solu- tion in which \(\left[\mathrm{OH}^{-}\right]\) is 100 times greater than \(\left[\mathrm{H}^{+}\right]\).

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