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(a) What is meant by the term elementary reaction? (b) What is the difference between a unimolecular and a bimolecular elementary reaction? (c) What is a reaction mechanism? (d) What is meant by the term ratedetermining step?

Short Answer

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(a) An elementary reaction is a single-step process without intermediates. (b) A unimolecular reaction involves one reactant; a bimolecular involves two. (c) A reaction mechanism is the sequence of steps in a reaction. (d) The rate-determining step is the slowest step controlling the reaction rate.

Step by step solution

01

Understanding Elementary Reactions

An elementary reaction refers to a single-step process in a chemical reaction where reactants are directly converted to products in one event or collision. These reactions occur in a single molecular step and thus have no intermediates.
02

Unimolecular vs Bimolecular Reactions

A unimolecular elementary reaction involves a single reactant molecule undergoing a change to form products, such as isomerization or decomposition. Meanwhile, a bimolecular elementary reaction involves two reactant molecules colliding and reacting together to form products, like in a synthesis or displacement reaction.
03

Defining Reaction Mechanism

A reaction mechanism comprises a series of elementary steps that describe the overall progress of a chemical reaction from reactants to products. It provides insights into the sequence and the pathway of transformations that occur during the reaction.
04

Defining Rate-Determining Step

The rate-determining step is the slowest step in a reaction mechanism that acts as a bottleneck, limiting the overall rate of the reaction. This step has the highest energy barrier to overcome and therefore dictates the speed at which the entire chemical reaction can proceed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unimolecular Reactions
A unimolecular reaction is a type of elementary reaction. It involves a single reactant molecule that undergoes a transformation to form products. This transformation can include processes like isomerization, where the molecule changes its structure without changing the number of atoms, or decomposition, where the molecule breaks down into smaller molecules or atoms.
For example, an isomerization reaction might occur when a complex organic molecule rearranges its structure, while decomposition might take place when a compound like nitrogen dioxide breaks down into nitrogen oxide and a free oxygen atom.
Unimolecular reactions are essential because they help us understand how molecules behave and react on their own without needing other molecules to interact with. These reactions are influenced mainly by the structure and energy of the reactant molecule itself.
Reaction Mechanism
A reaction mechanism provides a detailed description of how reactants transform into products in a chemical reaction. It outlines all the elementary steps, from start to finish, showing the sequence of events that occur.
  • The mechanism includes all the intermediate species that may form temporarily and the order in which bonds are broken and formed.
  • Each step of the mechanism is itself an elementary reaction, with its own reactants and products.
  • Understanding the mechanism is crucial for predicting how changes in conditions, like temperature or concentration, can affect the overall reaction.
By studying the mechanism, chemists can infer important details about the reaction pathway and uncover ways to control or optimize the reaction. Reaction mechanisms provide valuable insights that can be applied in fields like pharmaceuticals, where efficient and selective transformations are essential.
Rate-Determining Step
The rate-determining step in a reaction mechanism is the slowest step that sets the pace for the entire reaction. Imagine a multi-step process where one step takes significantly longer than the others. That slow step becomes a bottleneck, limiting the speed at which the final products can form.
This step usually requires the most energy to proceed, often involving a transition state with a high energy barrier. As a result, the rate-determine step dictates the overall reaction rate and thus provides chemists with a target for improvement.
  • By understanding which step is rate-determining, scientists can experiment with methods to lower the energy barrier and speed up the reaction.
  • This could involve using catalysts, which provide alternative pathways with lower activation energy, or changing reaction conditions, like temperature and pressure.
Knowing which step in the reaction mechanism is the slowest allows us to gain better control over the reaction kinetics and improve the efficiency of chemical processes.

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Most popular questions from this chapter

(a) Most commercial heterogeneous catalysts are extremely finely divided solid materials. Why is particle size important? (b) What role does adsorption play in the action of a heterogeneous catalyst?

Platinum nanoparticles of diameter \(-2 \mathrm{nm}\) are important catalysts in carbon monoxide oxidation to carbon dioxide. Platinum crystallizes in a face- centered cubic arrangement with an edge length of \(392.4 \mathrm{pm} .\) (a) Estimate how many platinum atoms would fit into a \(2.0-\mathrm{nm}\) sphere; the volume of a sphere is \((4 / 3) \pi r^{3}\). Recall that \(1 \mathrm{pm}=1 \times 10^{-12} \mathrm{~m}\) and \(1 \mathrm{nm}=1 \times 10^{-9} \mathrm{~m} .\) (b) Esti- mate how many platinum atoms are on the surface of a \(2.0-\mathrm{nm}\) Pt sphere, using the surface area of a sphere \(\left(4 \pi r^{2}\right)\) and assuming that the "footprint" of one \(\mathrm{Pt}\) atom can be estimated from its atomic diameter of \(280 \mathrm{pm}\) (c) Using your results from (a) and \((b),\) calculate the percentage of \(\mathrm{Pt}\) atoms that are on the surface of a \(2.0-\mathrm{nm}\) nanoparticle. (d) Repeat these calculations for a \(5.0-\mathrm{nm}\) platinum nanoparticle. (e) Which size of nanoparticle would you expect to be more catalytically active and why?

For each of the following gas-phase reactions, indicate how the rate of disappearance of each reactant is related to the rate of appearance of each product: (a) \(\mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g})\) (b) \(2 \mathrm{NO}(g)+\mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{NOCl}(g)\) (c) \(\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)\) (d) \(\mathrm{N}_{2} \mathrm{O}_{4}(g) \longrightarrow 2 \mathrm{NO}_{2}(g)\)

From the following data for the second-order gas-phase decomposition of HI at \(430^{\circ} \mathrm{C},\) calculate the second-order rate constant and half- life for the reaction: \begin{tabular}{rl} \hline Time (s) & [HIYmol dm \(^{-3}\) \\ \hline 0 & 1 \\ 100 & 0.89 \\ 200 & 0.8 \\ 300 & 0.72 \\ 400 & 0.66 \end{tabular}

A colored dye compound decomposes to give a colorless product. The original dye absorbs at \(608 \mathrm{nm}\) and has an extinction coefficient of \(4.7 \times 10^{4} \mathrm{M}^{-1} \mathrm{~cm}^{-1}\) at that wavelength. You perform the decomposition reaction in a \(1-\mathrm{cm}\) cuvette in a spectrometer and obtain the following data: \begin{tabular}{cc} \hline Time (min) & Absorbance at \(608 \mathrm{nm}\) \\ \hline 0 & 1.254 \\ 30 & 0.941 \\ 60 & 0.752 \\ 90 & 0.672 \\ 120 & 0.545 \\ \hline \end{tabular} From these data, determine the rate law for the reaction "dye \(\longrightarrow\) product" and determine the rate constant.

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