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Breathing air that contains \(4.0 \%\) by volume \(\mathrm{CO}_{2}\) over time causes rapid breathing, throbbing headache, and nausea, among other symptoms. What is the concentration of \(\mathrm{CO}_{2}\) in such air in terms of \((\mathbf{a})\) mol percentage, \((\mathbf{b})\) molarity, assuming 101.3 kPa pressure and a body temperature of \(37^{\circ} \mathrm{C} ?\)

Short Answer

Expert verified
(a) Mole percent: 4.0% (b) Molarity: 0.00157 mol/L

Step by step solution

01

Convert Volume Percent to Mole Fraction

The volume percent of CO鈧 is given as 4.0%. In the gas phase, under the assumption of ideal behavior, the volume percent is equivalent to mole percent. Therefore, the mole percent of CO鈧 is also 4.0%.
02

Convert Temperature to Kelvin

The given temperature is 37掳C. To convert this to Kelvin, use the formula: \[ T(K) = T(掳C) + 273.15 \]Thus, \[ T = 37 + 273.15 = 310.15 \text{ K} \]
03

Determine Total Pressure in Atmospheres

The pressure is given as 101.3 kPa. To convert to atmospheres, use the conversion: 1 atm = 101.325 kPa.\[ P = \frac{101.3}{101.325} \approx 1.00 \text{ atm} \]
04

Calculate Molarity Using Ideal Gas Law

Use the ideal gas law \( PV = nRT \) to find the molarity, where \( P = 1.00 \text{ atm} \), \( R = 0.0821 \text{ L atm mol}^{-1} \text{ K}^{-1} \), and \( T = 310.15 \text{ K} \). For 1 mole of ideal gas at this pressure and temperature:\[ V = \frac{nRT}{P} \approx \frac{(1)(0.0821)(310.15)}{1} \approx 25.42 \text{ L} \]The moles of CO鈧 in 1 L is \( 0.04 \times n \) because it is 4% mole fraction:\[ n_{\text{CO}_2} = 0.04 \times \frac{1}{25.42} \text{ mol/L} \approx 0.00157 \text{ mol/L} \]
05

Final Answers

(a) The mole percent of CO鈧 is 4.0%. (b) The molarity of CO鈧 is approximately 0.00157 mol/L.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a crucial equation in chemistry that describes the behavior of ideal gases. It combines several individual gas laws into one comprehensive formula, which tells us the relationship between pressure (P), volume (V), temperature (T), and the number of moles (n) of a gas. The ideal gas law is expressed as:
\[ PV = nRT \]Here, R is the ideal gas constant, and its typical value is 0.0821 L atm mol鈦宦 K鈦宦. This equation is pivotal in calculating various properties of gases.
  • When you know three of the variables (P, V, T, or n), you can determine the fourth.
  • The formula assumes the gas behaves ideally, meaning there are no intermolecular forces and the gas molecules occupy no volume.
In the context of our exercise, the ideal gas law helps calculate the molarity of CO鈧 by determining how much volume one mole of gas occupies under the given conditions of pressure and temperature. This calculated volume allows us to find the number of CO鈧 moles in one liter of air, thus determining molarity.
Molarity
Molarity is a way to express the concentration of a solution. It indicates the number of moles of a solute per liter of solution. The formula for molarity is:
\[ M = \frac{n}{V} \]Here, M stands for molarity, n is the moles of solute, and V is the volume of the solution in liters.
  • It's a very common unit of concentration in chemistry because it directly relates the quantity of substance to the volume of solution.
  • Molarity provides insight into how much solute is present in a given volume, which can affect reactions involving the solution.
In our context, the exercise calculates the molarity of CO鈧 in the breathing air scenario. By using the calculated volume from the ideal gas law, the moles of CO鈧 per liter are computed, resulting in the molarity value. This helps understand how much CO鈧 is present, in terms of moles, in every liter of the air.
Temperature Conversion
Temperature conversion is a necessary calculation when working with gases, as the ideal gas law requires temperature to be in Kelvin. Kelvin is an absolute temperature scale, which starts at absolute zero, where all molecular motion ceases.
  • To convert from Celsius to Kelvin, use the formula:
\[ T(K) = T(掳C) + 273.15 \]In our problem, we converted the body temperature from 37掳C to 310.15 K.
  • This ensures accurate use of the ideal gas law, as Kelvin is the standard unit for thermodynamic temperature.
  • Keeps calculations consistent and avoids having negative numbers when calculating with absolute temperatures.
Pressure Conversion
In gas calculations, standard units of pressure are often needed. Common units include atmospheres (atm), kiloPascals (kPa), and millimeters of mercury (mmHg). For the ideal gas law to work properly, pressure is typically converted to atmospheres.
  • Pressure conversion is crucial because the constant R in the ideal gas law is usually expressed in terms of atmospheres.
  • To convert from kPa to atm, use the relation:
\[ P(atm) = \frac{P(kPa)}{101.325} \]In the exercise, the pressure was given as 101.3 kPa, which converts approximately to 1.00 atm.
  • This makes calculations feasible without adjusting the ideal gas constant, ensuring that our calculations maintain accuracy.
  • Understanding this conversion helps ensure consistency and correctness when performing gas-related calculations, as mismatched units can lead to errors.

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Most popular questions from this chapter

Common laboratory solvents include acetone \(\left(\mathrm{CH}_{3} \mathrm{COCH}_{3}\right),\) methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right),\) toluene \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3}\right),\) and water. Which of these is the best solvent for nonpolar solutes?

At \(35^{\circ} \mathrm{C}\) the vapor pressure of acetone, \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO},\) is 47.9 \(\mathrm{kPa}\), and that of carbon disulfide, \(\mathrm{CS}_{2}\), is \(66.7 \mathrm{kPa}\). A solution composed of an equal number of moles of acetone and carbon disulfide has a vapor pressure of \(86.7 \mathrm{kPa}\) at \(35^{\circ} \mathrm{C} .(\mathbf{a})\) What would be the vapor pressure of the solution if it exhibited ideal behavior? (b) Based on the behavior of the solution, predict whether the mixing of acetone and carbon disulfide is an exothermic \(\left(\Delta H_{\text {soln }}<0\right)\) or endothermic \(\left(\Delta H_{\text {soln }}>0\right)\) process.

(a) What is the mass percentage of iodine in a solution containing \(0.035 \mathrm{~mol} \mathrm{I}_{2}\) in \(125 \mathrm{~g}\) of \(\mathrm{CCl}_{4} ?\) (b) Seawater contains \(0.0079 \mathrm{~g}\) of \(\mathrm{Sr}^{2+}\) per kilogram of water. What is the concentration of \(\mathrm{Sr}^{2+}\) in \(\mathrm{ppm}\) ?

Glucose makes up about \(0.10 \%\) by mass of human blood. Calculate this concentration in (a) ppm, (b) molality. (c) What further information would you need to determine the molarity of the solution?

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